来自标准查询的休眠 NamedQuery --> 需要帮助

Posted 2023-03-23

【中文标题】来自标准查询的休眠 NamedQuery --> 需要帮助

【英文标题】：nhibernate NamedQuery from criteriaQuery --> help needed

【发布时间】：2011-03-16 21:57:25

【问题描述】：

我正在尝试将工作条件查询转换为命名查询，但语法不正确。 hql 版本显然需要指定类型和 id 参数。

查询是在一个用 ANY 映射的类上（下面也是）

谁能帮我弄对语法？

干杯， 浆果

WORKING 条件查询

    result = _session
        .CreateCriteria<Allocation>()
        .Add(Restrictions.Eq(propName_Resource, resource))
        .Add(Restrictions.Between(propName_StartTime, (DateTime)searchRange.Start, (DateTime)searchRange.End))
        .AddOrder(Order.Asc(propName_StartTime))
        .List<Allocation>();

                produces
SELECT this_.AllocationId as Allocati1_2_0_, this_.ResourceType as Resource2_2_0_, this_.ResourceId as ResourceId2_0_, this_.ActivityType as Activity4_2_0_, 
        this_.ActivityId as ActivityId2_0_, this_.StartTime as StartTime2_0_, this_.EndTime as EndTime2_0_, this_.PostingTime as PostingT8_2_0_ 
FROM Allocations this_ 
WHERE this_.ResourceType = @p0 and this_.ResourceId = @p1 and this_.StartTime between @p2 and @p3 ORDER BY this_.StartTime asc;@p0 = 'EMPLOYEE' [Type: String (0)], @p1 = 98304 [Type: Int32 (0)], @p2 = 3/14/2011 12:00:00 AM [Type: DateTime (0)], @p3 = 3/20/2011 11:59:59 PM [Type: DateTime (0)] 2011-03-14 Mon - 2011-03-20 Sun

ANY 映射（有效！）

<any name="Resource" cascade="all" id-type="System.Int32" meta-type="System.String"
     >
  <meta-value value="EMPLOYEE" class="Employee, ..." />
  <meta-value value="Facility" class="Facility, ..." />

  <column name="ResourceType"/>
  <column name="ResourceId"/>
</any>

迄今已命名的查询（不工作）

我认为这是 hql 语法，但错误消息说缺少参数

....
          select a 
          from Allocation a 
          where a.Resource = :resource 
            and a.TimeRange.StartTime between :periodStart and :periodEnd
          order by a.TimeRange.StartTime
....

        return _session.GetNamedQuery("FetchByResourceForDateRange")
            .SetEntity("resource", resource)
            .SetDateTime("periodStart", searchRange.Start)
            .SetDateTime("periodEnd", searchRange.End)
            .List<Allocation>();

NHibernate.Exceptions.GenericADOException : could not execute query
[ select allocation0_.AllocationId as Allocati1_2_, allocation0_.ResourceType as   Resource2_2_, allocation0_.ResourceId as ResourceId2_, allocation0_.ActivityType as Activity4_2_, allocation0_.ActivityId as ActivityId2_, allocation0_.StartTime as StartTime2_, allocation0_.EndTime as EndTime2_, allocation0_.PostingTime as PostingT8_2_ from Allocations allocation0_ where allocation0_.ResourceType=@p0 and allocation0_.ResourceId=@p1 and (allocation0_.StartTime between @p2 and @p3) order by allocation0_.StartTime ]
  Name:resource - Value:George Washington 000001  Name:periodStart - Value:3/14/2011 12:00:00 AM  Name:periodEnd - Value:3/20/2011 11:59:59 PM
[SQL: select ... 
    from Allocations allocation0_ 
where allocation0_.ResourceType=@p0 and allocation0_.ResourceId=@p1 and (allocation0_.StartTime between @p2 and @p3) 
order by allocation0_.StartTime]

 ----> System.Data.SQLite.SQLiteException : SQLite error
Insufficient parameters supplied to the command

更新

这个组合执行但给出了错误的答案。不知道它是否离我需要的更近或更远

          select a 
          from Allocation a 
          where a.Resource.class = :class and a.Resource.id = :id 
            and a.TimeRange.StartTime between :periodStart and :periodEnd
          order by a.TimeRange.StartTime

        return _session.GetNamedQuery("FetchByResourceForDateRange")
            .SetString("class", typeof(Resource).FullName)
            .SetInt32("id", resource.Id)
            .SetDateTime("periodStart", searchRange.Start)
            .SetDateTime("periodEnd", searchRange.End)
            .List<Allocation>();

【参考方案1】：

好的，NHib 的首席开发人员 Fabio Maulo 说：

“你必须使用你的元数据值而不是 typeof(entity).FullName”

所以在我的情况下，以下是我工作的最后一个 hql：

return _session.GetNamedQuery("FetchByResourceForDateRange")
        .SetString("class", "EMPLOYEE")
        .SetInt32("id", resource.Id)
        .SetDateTime("periodStart", searchRange.Start)
        .SetDateTime("periodEnd", searchRange.End)
        .List<Allocation>();

比我希望的要丑一些，但我会接受它:--)

HTH， 浆果