SQL：根据 B 列中的布尔值更改 SELECT 查询以在 A 列上显示不同的值

Posted 2023-03-23

【中文标题】SQL：根据 B 列中的布尔值更改 SELECT 查询以在 A 列上显示不同的值

【英文标题】：SQL: Changing SELECT Query to Show Different Values on Column A based off Boolean in Column B

【发布时间】：2020-10-22 17:01:01

【问题描述】：

我有一个产生此输出的 SQL 查询：

如果“CROSSDOMAIN”列的值为true?，我将如何调整我的查询以使“SCORE”列的值增加 3 我想我会用处理这种情况的另一个查询，但我不确定该查询是什么。

我现有的查询如下（不是最漂亮的，但它有效）：

                SELECT HORSUM.TEAMNAME, HORSUM.EMAIL1, SUM(HORSUM.TOTALSUM) Score, COUNT(*) Count, TEAM.THEME, TEAM.FINALIST, TEAM.WINNER, TEAM.CROSSDOMAIN
                FROM 
                    (SELECT "JUDGEEMAIL", "TEAMNAME", "EMAIL1", "DEVOPSPRACTICES" + "BUSINESSIMPACT" + 
                    "NEWSKILLS" + "EXECUTION"
                    + "INNOVATION" + "CLARITY" as totalSum
                    FROM "DOMAINSCORES") AS HORSUM
                INNER JOIN (SELECT "THEME", "TEAMNAME" as nameID, "FINALIST", "WINNER", "CROSSDOMAIN" FROM "TEAMS" WHERE "FINALIST" = True) AS TEAM ON HORSUM.TEAMNAME = TEAM.nameID
                GROUP BY "TEAMNAME", EMAIL1, THEME, FINALIST, WINNER, CROSSDOMAIN
                ORDER BY Score DESC;

编辑：按照 Michael 的建议，我已尝试过此查询，但出现语法错误。我还想补充一点，我正在使用 IBM 的 DB2，如果这有影响的话。

SELECT HORSUM.TEAMNAME
     , HORSUM.EMAIL1
     , case
         when TEAM.CROSSDOMAIN = 'true' 
         then SUM(HORSUM.TOTALSUM) + 3
         else SUM(HORSUM.TOTALSUM) 
       end as Score
     , COUNT(*) Count
     , TEAM.THEME
     , TEAM.FINALIST
     , TEAM.WINNER
     , TEAM.CROSSDOMAIN
FROM
(SELECT HORSUM.TEAMNAME, HORSUM.EMAIL1, SUM(HORSUM.TOTALSUM) Score, COUNT(*) Count, TEAM.THEME, TEAM.FINALIST, TEAM.WINNER, TEAM.CROSSDOMAIN
                FROM 
                    (SELECT "JUDGEEMAIL", "TEAMNAME", "EMAIL1", "DEVOPSPRACTICES" + "BUSINESSIMPACT" + 
                    "NEWSKILLS" + "EXECUTION"
                    + "INNOVATION" + "CLARITY" as totalSum
                    FROM "DOMAINSCORES") AS HORSUM
                INNER JOIN (SELECT "THEME", "TEAMNAME" as nameID, "FINALIST", "WINNER", "CROSSDOMAIN" FROM "TEAMS" WHERE "FINALIST" = True) AS TEAM ON HORSUM.TEAMNAME = TEAM.nameID
                GROUP BY "TEAMNAME", EMAIL1, THEME, FINALIST, WINNER, CROSSDOMAIN)
ORDER BY Score DESC;

【参考方案1】：

试试这个作为外部 SELECT

SELECT HORSUM.TEAMNAME
     , HORSUM.EMAIL1
     , case
         when TEAM.CROSSDOMAIN = 'true' 
         then SUM(HORSUM.TOTALSUM) + 3
         else SUM(HORSUM.TOTALSUM) 
       end as Score
     , COUNT(*) Count
     , TEAM.THEME
     , TEAM.FINALIST
     , TEAM.WINNER
     , TEAM.CROSSDOMAIN
     ...

               

【讨论】：

嗨，迈克尔，感谢您的快速回复。我正在尝试如下查询，但我收到错误“HORSUM.TEAMNAME”在使用它的上下文中无效。有什么想法吗？

查看我对上面原始问题的编辑，了解我正在尝试的内容。

您构建了一个额外的外部选择，这就是您遇到此问题的原因 - 替换原始查询的最外部选择（您的第一个 SELECT）

非常感谢迈克尔，你应该意识到这就是你的意思。很抱歉！