如何以有效的方式同步列表和可枚举?
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【中文标题】如何以有效的方式同步列表和可枚举?【英文标题】:How to synchronize a list and an enumerable in an effective way? 【发布时间】:2014-09-11 01:27:52 【问题描述】:我经常遇到问题,我需要在 C# 中同步两个列表。 例如,我有一个简单的字符串数组。 我想以一种非常简单的方式将这些字符串加载到 Listview 的 Items 列表中。我还想以最少的项目交换来更新列表视图。
示例:
var strings = new List<string>() "a", "b", "c", "d" ;
listview1.Items.Synchronize(strings);
strings.Add("xx");
listview1.Items.Synchronize(strings); // just create a new item for xx
【问题讨论】:
【参考方案1】:我这里有一个简短的扩展函数,它可以同步两个不同类型的列表。 Lambda 扩展函数进行转换。 用法示例:
listView1.Items.SyncList(strings, lvItem => lvItem.Tag as string, str => new ListViewItem(str) Tag = str );
扩展函数定义如下:
/// <summary>
/// synchronizes an enumerable with a list with two different types,
/// </summary>
/// <typeparam name="TSource">Type of the elements in the source list</typeparam>
/// <typeparam name="TDestination">Type of the elements in the destination list</typeparam>
/// <param name="source">Source</param>
/// <param name="destination">Destination list</param>
/// <param name="selector">returns the corresponding source object for the destination list item</param>
/// <param name="creator">Creates new object for the destination list from the source. The selection function applied on the new object must return the source object. </param>
public static void SyncList<TSource, TDestination>(this IList destination, IEnumerable<TSource> source, Func<TDestination, TSource> selector, Func<TSource, TDestination> creator)
where TDestination : class
where TSource : class
if (source == null)
throw new ArgumentNullException("source");
if (destination == null)
throw new ArgumentNullException("destination");
if (selector == null)
throw new ArgumentNullException("selector");
if (creator == null)
throw new ArgumentNullException("creator");
var syncObject = destination.IsSynchronized ? destination.SyncRoot : new object();
lock (syncObject)
var ExistingItems = destination.OfType<TDestination>().Where(d => selector(d) != null).ToDictionary(d => selector(d));
foreach (var s in source)
if (!ExistingItems.Remove(s)) // s does not exist yet in the destination list
var NewObject = creator(s);
if (selector(NewObject) != s)
throw new ArgumentException("the selector must return the creation object of the new item");
destination.Add(creator(s));
var RemovedItems = ExistingItems.Values;
if (RemovedItems.Count == destination.Count)
destination.Clear();
else
foreach (var i in RemovedItems)
destination.Remove(i);
【讨论】:
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