类型错误：序列项 0：预期字符串，找到无类型
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【中文标题】类型错误：序列项 0：预期字符串，找到无类型【英文标题】：TypeError: sequence item 0: expected string, NoneType found 【发布时间】：2013-09-22 00:54:20 【问题描述】：我正在努力改进战舰游戏。原始版本运行良好，没有错误。我编写了代码来帮助克服这样一个事实，即第一个版本每次都将船放在同一个地方，所以我从一艘船（由两个正方形组成）开始。我通过创建两个函数来做到这一点：第一个生成随机坐标...
# Destroyer (2 squares)
def Deploy_Destroyer_1(Player):
rand_col_1 = randint(0,11)
if rand_col_1 <= 5:
rand_row_1 = randint(0,11)
else:
rand_row_1 = randint(6,11)
return rand_col_1
return rand_row_1
if Player[rand_row_1][rand_col_1] == 'X':
Deploy_Destroyer_1(Player)
else:
Deploy_Destroyer_2(Player)
第二次尝试根据条件调整坐标（如果它适合板上以及可以放置哪个旋转）。
def Deploy_Destroyer_2(Player):
if rand_col_1 == 5 and rand_row_1 == 6:
#can be 1, 2, 3 or 4... in that order below
rand_position_1 = randint(1,4)
if rand_position_1 == 1:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
if rand_position_1 == 4:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif rand_col_1 in range(1,4) and rand_row_1 in range(1,10):
#can be any 1, 2, 3 or 4... in that order below
rand_position_1 = randint(1,4)
if rand_position_1 == 1:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
if rand_position_1 == 4:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif rand_col_1 in range(5,10) and rand_row_1 in range(7,10):
#can be any 1, 2, 3 or 4... in that order below
rand_position_1 = randint(1,4)
if rand_position_1 == 1:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
if rand_position_1 == 4:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif rand_col_1 == 0 and rand_row_1 == 0:
#can be any 1, 2, 3 or 4... in that order below
rand_position_1 = randint(1,4)
if rand_position_1 == 1:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
if rand_position_1 == 4:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif (rand_col_1 == 5 and rand_row_1 == 0) or (rand_col_1 == 11 and rand_row_1 ==6):
#can be one or four
#check brackets and booleans here
rand_position_1 = randint(1,2)
if rand_position_1 == 1: #position 1
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2: #position 4
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif rand_col_1 == 0 and rand_row_1 == 11:
#can be 2 or 3
rand_position_1 = randint(2,3)
if rand_position_1 == 2: #position 2
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3: #position 3
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
elif rand_col_1 == 11 and rand_row_1 == 11:
#can be 2 or 4
rand_position_1 = randint(1,2)
if rand_position_1 == 1: #position 2
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 2: #position 4
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif (rand_row_1 == 0 and rand_col_1 in range(1,4)) or (rand_row_1 == 6 and rand_col_1 in range(6,10)):
#can be 1, 3 or 4
#check brackets and booleans here
rand_position_1 = randint(1,3)
if rand_position_1 == 1: #position 1
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2: #position 3
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
if rand_position_1 == 3: #position 4
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif (rand_col_1 == 5 and rand_row_1 in range(1,5)) or (rand_col_1 == 11 and rand_row_1 in range(7,10)):
#can be 1, 2 or 4
#check brackets and booleans here
rand_position_1 = randint(1,3)
if rand_position_1 == 1: #position 1
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2: #position 2
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3: #position 4
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
elif rand_col_1 == 0 and rand_row_1 in range(1,10):
#can be 1, 2 or 3... in that order below
rand_position_1 = randint(1,3)
if rand_position_1 == 1:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 + 1][rand_col_1] = 2
if rand_position_1 == 2:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3:
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
elif rand_col_1 in range(1,10) and rand_row_1 == 11:
#can be 2, 3 or 4
rand_position_1 = randint(1,3)
if rand_position_1 == 2: #position 2
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1 - 1][rand_col_1] = 2
if rand_position_1 == 3: #position 3
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 + 1] = 2
if rand_position_1 == 4: #position 4
Player[rand_row_1][rand_col_1] = 2
Player[rand_row_1][rand_col_1 - 1] = 2
应用我的代码后出现此错误。
Traceback (most recent call last):
File "<stdin>", line 310, in <module>
File "<stdin>", line 15, in PrintBoards
TypeError: sequence item 0: expected string, NoneType found
这里是PrintBoards 函数
def PrintBoards(Player,Opponent):
print ' '*10, 'PLAYER', ' '*30, 'OPPONENT'
letters = ['A','B','C','D','E','F','G','H','I','J','K','L']
for x in range(6):
print letters[x]," ".join(map(DisplayChar,Player[x]))," "*18,"| "," ".join(map(DisplayChar,Opponent[x]))
for x in range(6,12):
print letters[x]," ".join(map(DisplayChar,Player[x]))," | "," ".join(map(DisplayChar,Opponent[x]))
print " "," ".join(map(str,range(1,10)))," 10 11 12"," "," ".join(map(str,range(1,10)))," 10 11 12"
这里是DisplayChar 函数
def DisplayChar(x):
if x==0:
return '?'
elif x==1:
return ' '
elif x==2:
return 'X'
elif x==3:
return ' '
elif x==4:
return '*'
我试着把上面的函数编辑成这个...
def DisplayChar(x):
if x==0:
return '?'
elif x==2:
return 'X'
elif x==4:
return '*'
else:
return ' '
但是它给了我这个错误
Traceback (most recent call last):
File "<stdin>", line 309, in <module>
File "<stdin>", line 15, in PrintBoards
TypeError: argument 2 to map() must support iteration
我还尝试在 PrintBoards 函数之后打印列表 Player 和 Opponent，以确保它们包含它们所做的 0 和 1（指 DisplayChar 函数）（当插入原始时，而不是当我放入我的新的很长的代码）
下一点是对迈克尔的回应
PLAYER OPPONENT
[[1, 1, 1, 1, 1, 1], [1, 2, 2, 2, 1, 1], [1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 1, 1], [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1], [1, 1, 2, 1, 1, 2, 1, 1, 1, 1, 1, 1], [1, 2, 2, 2, 1, 2, 2, 2, 2, 1, 1, 1], [1, 2, 1, 2, 1, 2, 1, 1, 1, 1, 1, 1], [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]]
[0, 0, 0, 0, 0, 0]
A | ? ? ? ? ? ?
<function Deploy_Destroyer_1 at 0x1c2634>
[0, 0, 0, 0, 0, 0]
B
Traceback (most recent call last):
File "<stdin>", line 314, in <module>
File "<stdin>", line 17, in PrintBoards
TypeError: argument 2 to map() must support iteration
在有人好心指出我分配了函数而不是调用它之后，我发现发生了另一个错误（我认为 Python 不喜欢我）
Traceback (most recent call last):
File "<stdin>", line 313, in <module>
File "<stdin>", line 17, in PrintBoards
TypeError: argument 2 to map() must support iteration
下面我还包括了我调用函数的地方，以防我做了一些愚蠢的事情
Player, Opponent = InitBoards()
Player = DeployFleet(Player), Deploy_Destroyer_1(Player)
PrintBoards(Player,Opponent)
我把它改成了 Micheal0x2a 所说的，它运行没有错误，但是代码放置的船消失了
据我了解，PrintBoards 函数通过将列表中的项目映射到 DisplayChar 函数来打印 Player 的板（如果 2 是列表中的项目，它会打印 X 等）。所以我的新手知识告诉我Deploy_Destroyer_1函数应该在Main函数（上面包含）中调用Player =，以确保列表中的项目发生变化，因此打印的字符应该发生变化。
我猜我的新代码 (Deploy_Destroyer_1) 有问题，它不能正确执行此操作（要么不更改列表中的项目，因此不打印正确的字符，或者其他什么其他我想不到的）。
不过也有很大可能是我自己搞糊涂了
我只学了几个星期的 Python，所以如果有人需要更多细节来帮助我，请询问
【问题讨论】：
您需要显示完整的回溯，以便我们可以看到错误出现的位置。 这有帮助吗？你可能需要整个程序？啊 你的问题绝对不是TypeError。
有任何建议@septi？
我们不知道PrintBoards 函数，但我猜它里面有一个join 将所有单元格内容连接在一起。这不适用于无。
【参考方案1】：
如果您来到这里是因为您正在寻找“TypeError: sequence item 0: expected string, NoneType found”的根本原因，那么它可能来自于按照这些思路做一些事情......
','.join([None])
【讨论】：
谢谢，这正是我需要知道的。如果您的列表中有其他内容，但仍包含无，也会发生这种情况。 [None, 'foo', 'bar'] 现在我必须找到从数组中清除 'None's 的方法 这是一个很好的方法：>>> filter(None, ['a', None, 'c']) @NoelEvans: +1，但你需要指出，这不会从列表中过滤掉 None，还会过滤任何其他虚假值。 受@NoelEvans 启发，我发现这很有用：','.join(map(str,[None])) 您，先生，让我免于花费无数个小时绝望地查看 Google Cloud 日志，这些日志几乎是不言自明的。【参考方案2】：您的 DisplayChar 函数没有默认值。如果您要为x 处理所有可能的情况，这不会有任何害处，但显然您不是。试试
def DisplayChar(x):
if x == 0:
return '?'
elif x == 2:
return 'X'
elif x == 4:
return '*'
else:
return ' '
但这可能会在您不希望出现的地方产生空白字符串。
一般来说，我建议先阅读一个好的 Python 教程。您上面的所有代码都可以大大简化。
【讨论】：
将其更改为...它确实打印了另一行板，但出现此错误：STraceback (most recent call last): File "<stdin>", line 308, in <module> File "<stdin>", line 15, in PrintBoards TypeError: argument 2 to map() must support iteration
对。您的意思可能是 DisplayChar(Player[x]) 而不是 map(DisplayChar,Player[x])【参考方案3】：
问题很可能在这 4 行中的某处：
for x in range(6):
print letters[x]," ".join(map(DisplayChar,Player[x]))," "*18,"| "," ".join(map(DisplayChar,Opponent[x]))
for x in range(6,12):
print letters[x]," ".join(map(DisplayChar,Player[x]))," | "," ".join(map(DisplayChar,Opponent[x]))
在这些行中，您多次使用了join 语句。 join 语句需要一个字符串列表才能工作。但是，当您将 DisplayChar 映射到 Player[x] 时，DisplayChar 函数将返回值 None 而不是某种字符串。
如果您查看DisplayChar 函数，它只处理从0 到4 的值。您使用的列表可能包含其他数字或字符。如果x 恰好是5，DisplayChar 将终止并简单地返回值None。请记住，函数默认返回值None。
您要么需要在DisplayChar 中处理这些额外的数字，要么修改DisplayChar 以包含else 语句以返回一个空字符串，如下所示：
def DisplayChar(x):
if x==0:
return '?'
elif x==1:
return ' '
elif x==2:
return 'X'
elif x==3:
return ' '
elif x==4:
return '*'
else:
return ' '
编辑：
好的，鉴于新的编辑，我想我可能知道发生了什么。
注意到当您打印出Player[x] 时，它第二次打印出<function Deploy_Destroyer_1 at 0x1c2634>？
这意味着在某个地方，深埋在你的代码中，你做了一些Player[row] = Deploy_Destroyer_1 的效果（注意缺少的括号！）。您已分配该函数，而不是调用该函数。
寻找并添加缺少的括号应该很可能解决问题。
编辑 2：
我认为你的问题在于这一行：Player = DeployFleet(Player), Deploy_Destroyer_1(Player)
如果您尝试在之后立即执行print Player，我认为您很可能会看到一大串数字，然后是None。
这是因为 DeployFleet 函数正在返回表（我认为？），而 Deploy_Destroyer_1 函数什么也不返回。相反，它只是改变了Player 表。
要解决此问题，请尝试执行以下任一操作：
Player = DeployFleet(Player)
Deploy_Destroyer_1(Player)
...或修改Deployer_Destroyer_1，使其在完成后返回Player，这样您就可以这样做：
Player = DeployFleet(Player)
Deploy_Destroyer_1(Player)
【讨论】：
Player 是另一个函数def InitBoards(): #The following convention is used for storing the state of a square: #0=Unknown #1= Empty #2= Occupied #3= Missed #4= Hit (player or opponent) # Initially, the player's board is all empty, the opponent's is all unknown Player = [[1]*(6 if x<6 else 12) for x in range(12)] Opponent = [[0]*(6 if x<6 else 12) for x in range(12)] return Player,Opponent 中的定义列表，这是我的想法：map() 检查正方形/单元格的状态并使用DisplayChar 函数打印正确的字符串。我尝试更改显示
@BLeeM - 就在for 循环之后，您可以尝试编写print Player[x], Opponent[x] 以便我们可以检查这些列表中实际包含的内容吗？现在，我们只是在猜测这些值中的内容，我想确定一下。
它在InitBoards函数中定义（其中1和0指的是DisplayChar）def InitBoards(): # Initially, the player's board is all empty, the opponent's is all unknown Player = [[1]*(6 if x<6 else 12) for x in range(12)] Opponent = [[0]*(6 if x<6 else 12) for x in range(12)] return Player,Opponent所以它只打印所有的1和0，因为我们对对手一无所知我还没有部署我的舰队
@BleeM -- 不管怎样，你还能打印出来吗？某些东西可能会以意想不到的方式修改它们。此外，在调试时，偏执并测试您的假设总是好的——如果您的假设是正确的，就不会有错误:)
它没有到达print 它像以前一样停止并给我traceback 错误:( 并感谢您的建议！【参考方案4】：
如果出现任何此类错误，请使用它： 例如 ','.join((map(str,video_url)) 地图功能帮助您将 tuble 更改为 str
【讨论】：
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