如何解析响应 xml 字符串？

Posted 2023-03-16

【中文标题】如何解析响应 xml 字符串？

【英文标题】：How can I parse the response xml string?

【发布时间】：2013-01-07 17:43:18

【问题描述】：

<?xml version="1.0" encoding="utf-8"?>
  <soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" 
                 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
                 xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <soap:Body>
      <VideoListResponse xmlns="http://tempuri.org/">
        <VideoListResult>
          "List":["GUID":"127381638172638173","PageNumber":[2,1]]
        </VideoListResult>
      </VideoListResponse>
    </soap:Body>
  </soap:Envelope>

这是我的响应 xml 字符串。如何从这个 xml 字符串中解析 PageNumber？

【参考方案1】：

这是一个简单的代码片段，您可以使用它来扩展

ViewController.h 文件

#import <UIKit/UIKit.h>

@interface ViewController : UIViewController <NSXMLParserDelegate>

@property(retain,nonatomic)NSString *videoListResult;

@property(retain,nonatomic)NSString *currentElement;

@end

ViewController.m 文件

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

- (void)viewDidLoad

    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.


- (void)didReceiveMemoryWarning

    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.


-(void)viewDidAppear:(BOOL)animated
    [self parseXML];


-(void)parseXML
    NSString *xmlString = @"<?xml version=\"1.0\" encoding=\"utf-8\"?>\
    <soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">\
    <soap:Body>\
    <VideoListResponse xmlns=\"http://tempuri.org/\">\
    <VideoListResult>\"List\":[\"GUID\":\"127381638172638173\",\"PageNumber\":[2,1]]\
    </VideoListResult>\
    </VideoListResponse>\
    </soap:Body>\
    </soap:Envelope>";

    NSData *xmlData = [xmlString dataUsingEncoding:NSASCIIStringEncoding];

    NSXMLParser *xmlParser = [[NSXMLParser alloc] initWithData:xmlData];

    [xmlParser setDelegate:self];

    [xmlParser parse];



-(void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict

    NSLog(@"Element started %@",elementName);
    self.currentElement=elementName;



-(void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName

    NSLog(@"Element ended %@",elementName);
    self.currentElement=@"";



-(void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string
    if([self.currentElement isEqualToString:@"VideoListResult"])
       // NSLog(@"The characters are %@",string);

        id data = [NSJSONSerialization JSONObjectWithData:[string dataUsingEncoding:NSASCIIStringEncoding] options:0 error:nil];


        NSLog(@"The page numbers are %@",[[[data valueForKey:@"List"] objectAtIndex:0] valueForKey:@"PageNumber"]);


    


@end

【讨论】：

嗨，我正在尝试使用您的代码并正在尝试此操作，但我在字符串 xlmns 行收到了预期表达式错误：-(void)parseXML NSString *xmlString = @"<?xml version=\"1.0\" encoding=\"utf-8\"?>\ <string xmlns=\"http://server.com">\; NSData *xmlData = [xmlString dataUsingEncoding:NSASCIIStringEncoding]; NSXMLParser *xmlParser = [[NSXMLParser alloc] initWithData:xmlData]; [xmlParser setDelegate:self]; [xmlParser parse];

【参考方案2】：

您想使用LibXML 解析XML，然后您想使用SBJSON 解析VideoListResult 中包含的JSON。

【讨论】：

还有NSXMLParser、NSXMLParserDelegate和NSJSONSerialization。我肯定更喜欢内置类而不是第三方库。

除非你需要支持 ios 4.X，Richard 基本上是对的。 libXML 对 XML 解析稍微好一点（因为你可以只在 XPath 上解析，然后抓取你想要的字段），而如果你使用 NSXMLParser，你必须弄乱更多的文档。