在 Swift 4 中将 Json 对象转换为数组格式

Posted 2023-03-15

【中文标题】在 Swift 4 中将 Json 对象转换为数组格式

【英文标题】：Convert Json Object to Array format in Swift 4

【发布时间】：2019-12-20 12:30:09

【问题描述】：

我有 json

  "message": null,
  "data": 
    "Commodity Department": 
      "total": 2,
      "completed": 1,
      "completedWithDue": 0,
      "completedWithOutDue": 1,
      "inProgress": 1,
      "inProgressWithDue": 0,
      "inProgressWithOutDue": 1,
      "statusCounter": null
    

我需要将每个部门的 json 对象转换为数组。目前每个类别值("total": 0, "completed": 0, "completedWithDue": 0, "completedWithOutDue": 0, "inProgress": 0, "inProgressWithDue": 0, "inProgressWithOutDue": 0,) 将采用对象格式。我需要转换数组并根据类别加载到collectionview。截至目前，我正在尝试在下面的代码中解码我的 json

public struct Dashboard: Decodable 
    public let data : [String:Departments]


public struct Departments: Decodable 
    public let total, completed, completedWithDue, completedWithOutDue: Int
    public let inProgress, inProgressWithDue, inProgressWithOutDue: Int


let dashboard = try? JSONDecoder().decode(Dashboard.self, from: response.data!)

print(dashboard!.data.keys)

【问题讨论】：

问题是什么？

@vadian 当前每个类别的值（“total”：0，“completed”：0，“completedWithDue”：0，“completedWithOutDue”：0，“inProgress”：0，“inProgressWithDue”：0 , "inProgressWithOutDue": 0,) 将是对象格式。我需要根据类别将数组加载转换为collectionview

为了便于阅读，请将代码添加到您的问题中，而不是在 cmets 中。另外，print(dashboard!.data.keys) 的输出是什么？

这能回答你的问题吗？ How to parse Array of JSON to array in Swift

@koen 我得到了部门名称 All Departments, Portfolio Mangement Service.....

【参考方案1】：

您可以通过向结构添加计算属性来创建值数组

public struct Departments: Decodable 
    public let total, completed, completedWithDue, completedWithOutDue: Int
    public let inProgress, inProgressWithDue, inProgressWithOutDue: Int

    var categoryValues: [Int] get 
        return [total, completed, completedWithDue, completedWithOutDue,
         inProgress, inProgressWithDue, inProgressWithOutDue]
        
    

或使用map 即时创建数组

dashboard?.data.mapValues[$0.total, $0.completed, $0.completedWithDue, ...]

【讨论】：

我收到一个错误缺少返回预期返回“[Int]”的函数

抱歉，这是 Swift 5 的新功能。

如何访问密钥

数组中没有键，但值的顺序始终相同。想要key就需要字典，解决方法基本一样

【参考方案2】：

您可以在不知道密钥的情况下解码 json，如下所示：

func printJSON(json: [String:Any]) 
let jsonKeys = json.keys //Gets the list of keys on the outer-most layer of the JSON
for i in 0..<jsonKeys.count 
    let level1 = json[jsonKeys.index(jsonKeys.startIndex, offsetBy: i)] //retrieves the object with the specific keys
    if let level2 = json[level1.key] as? [String:Any] //if the key is another object
        printJSON(json: level2) //send it as a new json object to the function again
     else if let level2 = json[level1.key] as? [[String:Any]]  //if the key is an array of objects
        for i in 0..<level2.count  //loop through the array
            printJSON(json: level2[i]) //send each array element to the function
        
     else if let value = json[level1.key] as? String  //if value of String/Integer/Bool type
        print(value) //then only print values of the specified type (String-type in this case)
    

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