所以我正在制作一个程序，可以根据需要多次重复向用户打招呼，但是当他们想要继续时，它不会显示该代码

Posted 2023-03-15

【中文标题】所以我正在制作一个程序，可以根据需要多次重复向用户打招呼，但是当他们想要继续时，它不会显示该代码

【英文标题】：So I'm making a program that repeats a greeting to the user as many times they want, but when they want to continue it doesnt show that code

【发布时间】：2021-12-10 11:59:45

【问题描述】：

print("This program will print the amount of greeting you would like to see.")
print()
play = input("Do you want to continue? (y/n): ") 
while play == "y":
    name = input("Enter your name: ")
    print()
    greetings = int(input("How many times would you like to see your custom greeting?: "))
    print()
    for i in range(greetings):
        print("Hello " + name + "." + " It's a pleasure to meet you!")
    while play == "n":
        continue

因此，在这一行中，它不会显示您想查看更多信息，而是显示输入您的姓名。 我不确定是否应该删除此代码或更改某些内容

        play_2 = input("Would you like to see more? (y/n): ")
        while play_2 == "y":
            name_2 = input("Enter your name: ")
            print()
            greetings_2 = int(input("How many times would you like to see your custom 
greeting?: "))
            print()
            for i in range(greetings_2):
                print("Hello " + name_2 + "." + "It's a pleasure to meet you!")
            while play_2 == "n":
                continue

print()                 
print("Bye. Thanks for using my program!")

【问题讨论】：

你永远不会在你的循环中改变play。那么您如何期望while play == "y": 或while play == "y": 退出循环？当然while play == "n": 永远不会循环，因为它处于一个循环中，程序只有在play 是'y' 时才会进入。

【参考方案1】：

        play_2 = input("Would you like to see more? (y/n): ")
        while play_2 == "y":
            name_2 = input("Enter your name: ")
            print()
            greetings_2 = int(input("How many times would you like to see your custom 
greeting?: "))
            print()
            for i in range(greetings_2):
                print("Hello " + name_2 + "." + "It's a pleasure to meet you!")
            while play_2 == "n":
                continue

取消缩进一次。我建议先进行调试。

【参考方案2】：

您可以按如下方式更改您的代码：

print("This program will print the amount of greeting you would like to see.")
print()
play = input("Do you want to continue? (y/n): ") 
while play == "y":
    name = input("Enter your name: ")
    print()
    greetings = int(input("How many times would you like to see your custom greeting?: "))
    print()
    for i in range(greetings):
        print("Hello " + name + "." + " It's a pleasure to meet you!")
    play = input("Would you like to see more? (y/n): ")

问题在于您的 while 循环的设置。检查用户是否想在最后再次运行程序只需要一个。如果用户输入的不是“y”，循环就会中断。

【参考方案3】：

您需要一种机制来重复输入，Do you want to continue? (y/n): 例如在下面的代码中，它已被放入while 循环中，因此它将在打印给定名称指定次数后再次运行。

print("This program will print the amount of greeting you would like to see.")
print()

play = input("Do you want to continue? (y/n): ")

while play == "y":
    name = input("Enter your name: ")
    greetings = int(input("How many times would you like to see your custom greeting?: "))
    for i in range(greetings):
        print("Hello " + name + "." + " It's a pleasure to meet you!")
    play = input("Do you want to continue? (y/n): ")

示例运行：

This program will print the amount of greeting you would like to see.

Do you want to continue? (y/n): y
Enter your name: Naomi
How many times would you like to see your custom greeting?: 2
Hello Naomi. It's a pleasure to meet you!
Hello Naomi. It's a pleasure to meet you!
Do you want to continue? (y/n): y
Enter your name: Campbell
How many times would you like to see your custom greeting?: 2
Hello Campbell. It's a pleasure to meet you!
Hello Campbell. It's a pleasure to meet you!
Do you want to continue? (y/n): n

Process finished with exit code 0

【讨论】：

但在开始时我想问用户是否要在“此程序将打印...”之后继续

@Naomi - 我已更新程序以满足此要求。

非常感谢！

【参考方案4】：

如果用户不想继续，请使用 while True 的无限循环，然后使用 break 离开。这样做的好处是您不必在多行代码中跟踪其他变量。

print("This program will print the amount of greetings you would like to see.")
while True:
    name = input("Enter your name: ")
    number_of_greetings = int(input("How many times would you like to see your custom greeting?: "))
    for _ in range(number_of_greetings):
        print(f"Hello name. It's a pleasure to meet you!")
    play_again = input("Do you want to continue? (y/n): ")
    if play_again != 'y':
        break

print("Bye. Thanks for using my program!")

【参考方案5】：

print("This program will print the amount of greeting you would like to see.")
while (play := input("\nDo you want to continue? (y/n): ")).lower() == "y" :
    name = input("Enter your name: ")
    print()
    greetings = int(input("How many times would you like to see your custom greeting?: "))
    print()
    for i in range(greetings):
        print("Hello " + name + "." + " It's a pleasure to meet you!")

您可以通过对输入添加检查并在字符串末尾使用 \n 来消除 print() 行，从而减少代码的长度来改进代码。