即使其他人加入了频道，也继续播放歌曲

Posted 2023-03-14

【中文标题】即使其他人加入了频道，也继续播放歌曲

【英文标题】：keep playing the song even if someone else joined the channel

【发布时间】：2022-01-21 13:30:40

【问题描述】：

您好，我正在尝试让机器人播放特定歌曲，然后我希望机器人离开频道并且我做到了，但问题是当机器人播放时其他人加入频道时重新开始播放歌曲

client.on('voiceStateUpdate', async (oldState, newState) => 
    const channel = client.channels.cache.get('921118985876017217')
    if (oldState.channel == null && newState.channel == channel) 
  await new Promise(function (resolve , reject) 
            resolve(
                joinVoiceChannel(
                    channelId: channel.id,
                    guildId: newState.guild.id,
                    adapterCreator: newState.guild.voiceAdapterCreator
                ))
            let stream = ytdl('https://www.youtube.com/watch?v=TU1i6I1ms6s', 
                filter: "audioonly",
                fmt: "mp3",
                encoderArgs: ['-af', 'bass=g=10'],
            )

            let secStream = ytdl('https://www.youtube.com/watch?v=wHqKkiHlvJc&list=RDwHqKkiHlvJc&start_radio=1', 
                filter: "audioonly",
                fmt: "mp3",
                encoderArgs: ['-af', 'bass=g=10'],
            )
         
            const resource = createAudioResource(stream, 
                inputType: StreamType.Arbitrary,
                inlineVolume: true,
            );
            // resource.volume.setVolume(0.5);
            const secReasorce = createAudioResource(secStream, 
                inputType: StreamType.Arbitrary, /* StreamType.Arbitrary type of the song like mpe */
                inlineVolume: true,
            );
            const player = createAudioPlayer();
            player.play(resource)
            const connection = getVoiceConnection(oldState.guild.id)
            connection.subscribe(player)
            player.on(AudioPlayerStatus.Idle, () =>setTimeout(() => 
                try
                    player.play(secReasorce)
                catch
                    connection.destroy()
                
            , 3000))
            player.on( AudioPlayerStatus.Playing , ()=>
                //I think there will be the solution but I don't know any functions does what I want
             )
        )

【参考方案1】：

您必须跟踪它是否已经在播放音频。由于您是根据 ID 获取频道的；我假设您只在一个语音通道中使用它。所以你可以在 lambda 表达式的范围之外有一个布尔值来跟踪它是否正在播放。

如果你实现它，你会有这样的东西：

let isPlaying = false; // Create a variable to keep track of whether it's playing or not.

client.on('voiceStateUpdate', async (oldState, newState) => 

    // If it's already playing, return and do nothing.
    if (isPlaying) return;

    const channel = client.channels.cache.get('921118985876017217')
    if (oldState.channel == null && newState.channel == channel) 
            await new Promise(function (resolve , reject) 
            resolve(
                joinVoiceChannel(
                    channelId: channel.id,
                    guildId: newState.guild.id,
                    adapterCreator: newState.guild.voiceAdapterCreator
                ))

            isPlaying = true; // Bot successfully joined vc, it now begins to play audio.

            // Removed code unrelated to the answer so you can more easily see the changes.

            player.on(AudioPlayerStatus.Idle, () =>setTimeout(() => 
                try
                    player.play(secReasorce)
                catch
                    // I assume this is where you make it disconnect? 
                    // If so, retain the integrity of `isPlaying` by setting it back to false.
                    isPlaying = false;
                    connection.destroy()
                
            , 3000))
        )```