从 openweathermAp 使用 RESTful Web 服务的问题?
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【中文标题】从 openweathermAp 使用 RESTful Web 服务的问题?【英文标题】:issue with consuming restful webservice from openweather Api? 【发布时间】:2021-05-11 00:15:45 【问题描述】:我试图从 openweathermap api 检索天气详细信息,有些我无法让它在以下错误中工作。任何帮助将不胜感激
控制器
@Controller
public class CurrentWeatherController
private final StubWeatherService stubWeatherService;
private final LiveWeatherService liveWeatherService;
public CurrentWeatherController(StubWeatherService stubWeatherService, LiveWeatherService liveWeatherService)
this.stubWeatherService = stubWeatherService;
this.liveWeatherService = liveWeatherService;
@GetMapping("/current-weather")
public String getCurrentWeather(Model model)
model.addAttribute("currentWeather", liveWeatherService.getCurrentWeather("Detroit","us"));
return "current-weather";
public StubWeatherService getStubWeatherService()
return stubWeatherService;
服务代码
@Service
public class LiveWeatherService
private static final String WEATHER_URL = "http://api.openweathermap.org/data/2.5/weather?q=city,country&APPID=key&units=metric";
private final String apiKey="526a647fcd4f3f465c0340c19d26ef3a";
private final RestTemplate restTemplate;
private final ObjectMapper objectMapper;
public LiveWeatherService(RestTemplateBuilder restTemplateBuilder, ObjectMapper objectMapper)
this.restTemplate = restTemplateBuilder.build();
this.objectMapper = objectMapper;
public CurrentWeather getCurrentWeather(String city, String country)
URI url = new UriTemplate(WEATHER_URL).expand(city, country,this.apiKey); // line 34 issue with accepting apikey
ResponseEntity<String> response = restTemplate.getForEntity(url, String.class);
return convert(response);
private CurrentWeather convert(ResponseEntity<String> response)
try
JsonNode root = objectMapper.readTree(response.getBody());
return new CurrentWeather(root.path("weather").get(0).path("main").asText(),
BigDecimal.valueOf(root.path("main").path("temp").asDouble()),
BigDecimal.valueOf(root.path("main").path("feels_like").asDouble()),
BigDecimal.valueOf(root.path("wind").path("speed").asDouble()));
catch (JsonProcessingException e)
throw new RuntimeException("Error parsing JSON", e);
错误
2-07 02:34:48.710 错误 43384 --- [nio-8080-exec-3] o.a.c.c.C.[.[.[/].[dispatcherServlet] :Servlet.service() for 带有路径 [] 的上下文中的 servlet [dispatcherServlet] 引发异常 [处理程序调度失败;嵌套异常是 java.lang.Error: 未解决的编译问题: 类型不匹配:无法从 UriTemplate 转换为 URI ] 有根本原因
java.lang.Error: Unresolved compilation problem: Type mismatch: cannot convert from UriTemplate to URI at com.meshupProjekt.service.LiveWeatherService.getCurrentWeather(LiveWeatherService.java:34)
~[classes/:na] 在 com.meshupProjekt.controller.CurrentWeatherController.getCurrentWeather(CurrentWeatherController.java:36) 〜[类/:na] 在 java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native 方法)~[na:na] 在 java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) 〜[无:无] 在 java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 〜[无:无] 在 java.base/java.lang.reflect.Method.invoke(Method.java:567) ~[na:na] 在 org.springframework.web.method.support.InvocableHandlerMethod.doInvoke(InvocableHandlerMethod.java:197) ~[spring-web-5.3.2.jar:5.3.2] 在 org.springframework.web.method.support.InvocableHandlerMethod.invokeForRequest(InvocableHandlerMethod.java:141) ~[spring-web-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.mvc.method.annotation.ServletInvocableHandlerMethod.invokeAndHandle(ServletInvocableHandlerMethod.java:106) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter.invokeHandlerMethod(RequestMappingHandlerAdapter.java:894) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter.handleInternal(RequestMappingHandlerAdapter.java:808) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.mvc.method.AbstractHandlerMethodAdapter.handle(AbstractHandlerMethodAdapter.java:87) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:1061) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:961) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:1006) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:898) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 javax.servlet.http.HttpServlet.service(HttpServlet.java:626) ~[tomcat-embed-core-9.0.41.jar:4.0.FR] 在 org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:883) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 javax.servlet.http.HttpServlet.service(HttpServlet.java:733) ~[tomcat-embed-core-9.0.41.jar:4.0.FR] 在 org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231) ~[tomcat-embed-core-9.0.41.jar:9.0.41] 在 org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166) ~[tomcat-embed-core-9.0.41.jar:9.0.41] 在 org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:53) ~[tomcat-embed-websocket-9.0.41.jar:9.0.41] 在 org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193) ~[tomcat-embed-core-9.0.41.jar:9.0.41] 在 org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166) ~[tomcat-embed-core-9.0.41.jar:9.0.41] 在 org.springframework.web.servlet.resource.ResourceUrlEncodingFilter.doFilter(ResourceUrlEncodingFilter.java:67) ~[spring-webmvc-5.3.2.jar:5.3.2] 在 org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193) ~[tomcat-embed-core-9.0.41.jar:9.0.41] 在 org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166) ~[tomcat-embed-core-9.0.41.jar:9.0.41] 在 org.springframework.web.filter.RequestContextFilter.doFilterInternal(RequestContextFilter.java:100) ~[春天-
【问题讨论】:
【参考方案1】:对我来说,您的代码是这样工作的:
String WEATHER_URL = "http://api.openweathermap.org/data/2.5/weather?q=city,country&APPID=key&units=metric";
String apiKey = "526a647fcd4f3f465c0340c19d26ef3a";
var x = new UriTemplate(WEATHER_URL).expand("Darmstadt", "Deutschland", apiKey);
System.out.println(x);
我使用 var
而不是 URI
,以便 Java 选择正确的类型。
您的编译错误可能是由于 URI
类的错误导入造成的。
【讨论】:
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