您如何以编程方式和异步方式定义 Mocha 测试？

Posted 2023-03-08

【中文标题】您如何以编程方式和异步方式定义 Mocha 测试？

【英文标题】：How do you define Mocha tests programmatically and asynchronously?

【发布时间】：2015-11-17 04:29:20

【问题描述】：

我正在尝试将一些以编程方式生成的测试与 node.js 中的 Mocha 测试框架集成。

var Promise = require('promise');

var resolved = Promise.resolve(true);

suite("Synchronously defined suite", function() 
  test("Synchronously defined test", function() 
    return resolved;
  );
);

defer(function() 
  suite("Asynch DEFINED test", function() 
    suiteSetup(function() 
      console.log("Asynch setupSuite running...");
    );

    test("Asynch Test", function() 
      console.log("Async test running...");
      return resolved;
    );
  );
);

function defer(fn) 
  console.log("Calling defer...");
  setTimeout(fn, 100);

当我执行这个时，我得到：

$ mocha --ui tdd nested-test.js 
Calling defer...


  Synchronously defined suite
    ✓ Synchronously defined test


  1 passing (4ms)

似乎 Mocha 要求所有“套件”函数在模块加载时同步执行 - 延迟调用似乎（默默地）被忽略（或者程序在调用它们之前退出）。

【参考方案1】：

这是我想出的。它不在 mocha 下运行，而是作为一个独立的节点程序运行：

var Promise = require('promise');
var Mocha = require('mocha');

var resolved = Promise.resolve(true);
var rejected = Promise.reject(new Error("Failing test."));

defer(function() 
  console.log("Programmatic test suite creation.");
  var suite = new Mocha.Suite("Programatic Suite");
  var runner = new Mocha.Runner(suite);
  var reporter = new Mocha.reporters.Spec(runner);

  suite.addTest(new Mocha.Test("My test", function() 
    return resolved;
  ));

  suite.addTest(new Mocha.Test("My (failing) test", function() 
    return rejected;
  ));

  runner.run();
);

function defer(fn) 
  setTimeout(fn, 100);

运行时输出：

$ node deferred-test.js 
Programmatic test suite creation.

Programatic Suite
  ✓ My test
  1) My (failing) test

  1 passing (7ms)
  1 failing

  1) Programatic Suite My (failing) test:
     Error: Failing test.
      at Object.<anonymous> (deferred-test.js:5:31)
      at node.js:935:3

不过，我希望能够将此测试包含在我的应用程序中的所有（静态定义的）mocha-run 测试套件中。