ActionScript 3.0 + 计算两个日期之间的时间跨度？
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【中文标题】ActionScript 3.0 + 计算两个日期之间的时间跨度？【英文标题】：ActionScript 3.0 + Calculate timespan between two dates? 【发布时间】：2010-09-15 05:08:53 【问题描述】：在 ActionScript 3.0 中，是否有自动计算两个指定日期之间的天数、小时数、分钟数和秒数的方法？
基本上，我需要的是 .NET Timespan 类的 ActionScript 等效项。
有什么想法吗？
【问题讨论】：
【参考方案1】：我创建了一个 ActionScript TimeSpan 类，它使用与 System.TimeSpan 类似的 API 来填补这一空白，但由于缺少运算符重载，因此存在差异。你可以这样使用它：
TimeSpan.fromDates(later, earlier).totalDays;
下面是该类的代码（抱歉，这篇大文章 - 我不会包含单元测试；）
/**
* Represents an interval of time
*/
public class TimeSpan
private var _totalMilliseconds : Number;
public function TimeSpan(milliseconds : Number)
_totalMilliseconds = Math.floor(milliseconds);
/**
* Gets the number of whole days
*
* @example In a TimeSpan created from TimeSpan.fromHours(25),
* totalHours will be 1.04, but hours will be 1
* @return A number representing the number of whole days in the TimeSpan
*/
public function get days() : int
return int(_totalMilliseconds / MILLISECONDS_IN_DAY);
/**
* Gets the number of whole hours (excluding entire days)
*
* @example In a TimeSpan created from TimeSpan.fromMinutes(1500),
* totalHours will be 25, but hours will be 1
* @return A number representing the number of whole hours in the TimeSpan
*/
public function get hours() : int
return int(_totalMilliseconds / MILLISECONDS_IN_HOUR) % 24;
/**
* Gets the number of whole minutes (excluding entire hours)
*
* @example In a TimeSpan created from TimeSpan.fromMilliseconds(65500),
* totalSeconds will be 65.5, but seconds will be 5
* @return A number representing the number of whole minutes in the TimeSpan
*/
public function get minutes() : int
return int(_totalMilliseconds / MILLISECONDS_IN_MINUTE) % 60;
/**
* Gets the number of whole seconds (excluding entire minutes)
*
* @example In a TimeSpan created from TimeSpan.fromMilliseconds(65500),
* totalSeconds will be 65.5, but seconds will be 5
* @return A number representing the number of whole seconds in the TimeSpan
*/
public function get seconds() : int
return int(_totalMilliseconds / MILLISECONDS_IN_SECOND) % 60;
/**
* Gets the number of whole milliseconds (excluding entire seconds)
*
* @example In a TimeSpan created from TimeSpan.fromMilliseconds(2123),
* totalMilliseconds will be 2001, but milliseconds will be 123
* @return A number representing the number of whole milliseconds in the TimeSpan
*/
public function get milliseconds() : int
return int(_totalMilliseconds) % 1000;
/**
* Gets the total number of days.
*
* @example In a TimeSpan created from TimeSpan.fromHours(25),
* totalHours will be 1.04, but hours will be 1
* @return A number representing the total number of days in the TimeSpan
*/
public function get totalDays() : Number
return _totalMilliseconds / MILLISECONDS_IN_DAY;
/**
* Gets the total number of hours.
*
* @example In a TimeSpan created from TimeSpan.fromMinutes(1500),
* totalHours will be 25, but hours will be 1
* @return A number representing the total number of hours in the TimeSpan
*/
public function get totalHours() : Number
return _totalMilliseconds / MILLISECONDS_IN_HOUR;
/**
* Gets the total number of minutes.
*
* @example In a TimeSpan created from TimeSpan.fromMilliseconds(65500),
* totalSeconds will be 65.5, but seconds will be 5
* @return A number representing the total number of minutes in the TimeSpan
*/
public function get totalMinutes() : Number
return _totalMilliseconds / MILLISECONDS_IN_MINUTE;
/**
* Gets the total number of seconds.
*
* @example In a TimeSpan created from TimeSpan.fromMilliseconds(65500),
* totalSeconds will be 65.5, but seconds will be 5
* @return A number representing the total number of seconds in the TimeSpan
*/
public function get totalSeconds() : Number
return _totalMilliseconds / MILLISECONDS_IN_SECOND;
/**
* Gets the total number of milliseconds.
*
* @example In a TimeSpan created from TimeSpan.fromMilliseconds(2123),
* totalMilliseconds will be 2001, but milliseconds will be 123
* @return A number representing the total number of milliseconds in the TimeSpan
*/
public function get totalMilliseconds() : Number
return _totalMilliseconds;
/**
* Adds the timespan represented by this instance to the date provided and returns a new date object.
* @param date The date to add the timespan to
* @return A new Date with the offseted time
*/
public function add(date : Date) : Date
var ret : Date = new Date(date.time);
ret.milliseconds += totalMilliseconds;
return ret;
/**
* Creates a TimeSpan from the different between two dates
*
* Note that start can be after end, but it will result in negative values.
*
* @param start The start date of the timespan
* @param end The end date of the timespan
* @return A TimeSpan that represents the difference between the dates
*
*/
public static function fromDates(start : Date, end : Date) : TimeSpan
return new TimeSpan(end.time - start.time);
/**
* Creates a TimeSpan from the specified number of milliseconds
* @param milliseconds The number of milliseconds in the timespan
* @return A TimeSpan that represents the specified value
*/
public static function fromMilliseconds(milliseconds : Number) : TimeSpan
return new TimeSpan(milliseconds);
/**
* Creates a TimeSpan from the specified number of seconds
* @param seconds The number of seconds in the timespan
* @return A TimeSpan that represents the specified value
*/
public static function fromSeconds(seconds : Number) : TimeSpan
return new TimeSpan(seconds * MILLISECONDS_IN_SECOND);
/**
* Creates a TimeSpan from the specified number of minutes
* @param minutes The number of minutes in the timespan
* @return A TimeSpan that represents the specified value
*/
public static function fromMinutes(minutes : Number) : TimeSpan
return new TimeSpan(minutes * MILLISECONDS_IN_MINUTE);
/**
* Creates a TimeSpan from the specified number of hours
* @param hours The number of hours in the timespan
* @return A TimeSpan that represents the specified value
*/
public static function fromHours(hours : Number) : TimeSpan
return new TimeSpan(hours * MILLISECONDS_IN_HOUR);
/**
* Creates a TimeSpan from the specified number of days
* @param days The number of days in the timespan
* @return A TimeSpan that represents the specified value
*/
public static function fromDays(days : Number) : TimeSpan
return new TimeSpan(days * MILLISECONDS_IN_DAY);
/**
* The number of milliseconds in one day
*/
public static const MILLISECONDS_IN_DAY : Number = 86400000;
/**
* The number of milliseconds in one hour
*/
public static const MILLISECONDS_IN_HOUR : Number = 3600000;
/**
* The number of milliseconds in one minute
*/
public static const MILLISECONDS_IN_MINUTE : Number = 60000;
/**
* The number of milliseconds in one second
*/
public static const MILLISECONDS_IN_SECOND : Number = 1000;
【讨论】：
@nchrysler - 我不建议向其他人的示例代码添加功能。不过，您可以随意使用新功能添加您自己的答案。 @Erwinus - 有趣，你能给我一份复制声明吗？ 您可以为其添加许可证吗？最好是 Apache 或 BSD？不幸的是，有些人在没有许可的情况下不能使用它。 此要点是上述代码的副本，附有 Apache 许可证：gist.github.com/richardszalay/8d5b7b3410c3730b213f 太棒了！谢谢理查德【参考方案2】：您可以将两个日期时间转换为自纪元以来的毫秒数，执行数学运算，然后使用得到的毫秒数来计算这些更高的时间跨度数。
var someDate:Date = new Date(...);
var anotherDate:Date = new Date(...);
var millisecondDifference:int = anotherDate.valueOf() - someDate.valueOf();
var seconds:int = millisecondDifference / 1000;
....
LiveDocs 对这类事情也很有用。抱歉，ActionScript 有点不对劲，但已经有一段时间了。
如果您要进行大量此类数学运算，我还建议您创建一组可以执行这些操作的静态类方法。遗憾的是，标准 API 中并不存在这种基本功能。
【讨论】：
【参考方案3】：对于一些像这样的单一功能我更可取... [浓缩自 Richard Szalay 的代码]
public function timeDifference(startTime:Date, endTime:Date) : String
if (startTime == null) return "startTime empty.";
if (endTime == null) return "endTime empty.";
var aTms = Math.floor(endTime.valueOf() - startTime.valueOf());
return "Time taken: "
+ String( int(aTms/(24*60*+60*1000)) ) + " days, "
+ String( int(aTms/( 60*60*1000)) %24 ) + " hours, "
+ String( int(aTms/( 60*1000)) %60 ) + " minutes, "
+ String( int(aTms/( 1*1000)) %60 ) + " seconds.";
【讨论】：
不准确。不考虑闰年或有 29 天的 2 月。【参考方案4】：没有自动执行此操作的方法。使用提供的类可以实现的最佳效果是获取 date1.time 和 date2.time，以给出两个数字自 1970 年 1 月 1 日以来的毫秒数。然后，您可以计算出它们之间的毫秒数。通过一些基本的数学运算，您可以推导出秒、小时、天等。
【讨论】：
【参考方案5】：为了准确起见，Russell 的上述帖子是正确的，直到您达到 25 天的差异，然后这个数字对于 int 变量来说变得太大了。 因此声明millisecondDifference:Number;
记录的 getTime() 和 valueOf() 之间可能存在一些差异，但实际上我看不到它
【讨论】：
【参考方案6】：var timeDiff:Number = endDate - startDate;
var days:Number = timeDiff / (24*60*60*1000);
var rem:Number = int(timeDiff % (24*60*60*1000));
var hours:Number = int(rem / (60*60*1000));
rem = int(rem % (60*60*1000));
var minutes:Number = int(rem / (60*1000));
rem = int(rem % (60*1000));
var seconds:Number = int(rem / 1000);
trace(days + " << >> " +hours+ " << >> " +minutes+ " << >> " +seconds);
或
var time:Number = targetDate - currentDate;
var secs:Number = time/1000;
var mins:Number = secs/60;
var hrs:Number = mins/60;
var days:Number = int(hrs/24);
secs = int(secs % 60);
mins = int(mins % 60);
hrs = int(hrs % 24);
trace(secs + " << >> " + mins + " << >> " + hrs + " << >> " + days);
【讨论】：
【参考方案7】：ArgumentValidation 是 Szalays 先生的另一类，它进行一些检查以确保每个方法都有正确的值来执行其任务，而不会引发无法识别的错误。它们对于使 TimeSpan 类正常工作不是必需的，因此您只需将它们注释掉，该类就会正常工作。
Rich 可能会在这里发布 Argument 验证类，它非常方便，但我会把它留给他；P
【讨论】：
James 是对的，它只是一个实用类来保持消费代码干净 ...虽然这个答案和 sideDoors 答案都应该是 cmets ;)以上是关于ActionScript 3.0 + 计算两个日期之间的时间跨度？的主要内容，如果未能解决你的问题，请参考以下文章
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