带部分的 tableview 搜索栏

Posted 2023-02-27

【中文标题】带部分的 tableview 搜索栏

【英文标题】：tableview search bar with section

【发布时间】：2018-05-10 18:05:45

【问题描述】：

在问你之前，我遵循了 3 个教程，但没有任何结果。 我有一个包含 20 个部分的表格视图，每个单元格都有 2 个标签：1 个用于标题，1 个用于艺术家。所以我有 20 个按字母顺序排列的标题数组和 20 个按字母顺序排列的艺术家数组。 我想在这两个数组之间实现一个搜索栏，仅基于标题数组。 有可能吗？

这是我的代码

import UIKit

class TableViewController: UITableViewController 


    //Creo le sezioni
    let sections = ["A","B","C","D","E","F","G","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","Z"]

    let cantiTitles: [String] = ["A","B","C","D","E","F","G","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","Z"]

    var categoriacliccata = 0
    var rowCliccata = 0

    @IBOutlet weak var searchBar: UISearchBar!
    let searchController = UISearchController(searchResultsController: nil)

    override func viewDidLoad() 
        super.viewDidLoad()

    

    override func sectionIndexTitles(for tableView: UITableView) -> [String]? 
        return cantiTitles
    

    override func didReceiveMemoryWarning() 
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    

    override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) 
        print("section: \(indexPath.section)")
        categoriacliccata = indexPath.section
        print("row: \(indexPath.row)")
        rowCliccata = indexPath.row
        performSegue(withIdentifier: "segue_testo", sender: self)
    

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) 
        if (segue.identifier == "segue_testo") 
            let secondVC: TextView_Controller = segue.destination as! TextView_Controller
            secondVC.recivedCategoria = categoriacliccata
            secondVC.recivedRow = rowCliccata
        
    

    override func tableView(_ tableView: UITableView, titleForHeaderInSection section: Int) -> String? 
        return sections[section]
    

    override func numberOfSections(in tableView: UITableView) -> Int 
        return sections.count
    

    override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int 
        switch section 
        case 0:
            return titoliA.count
        case 1:
            return titoliB.count
        case 2:
            return titoliC.count
        case 3:
            return titoliD.count
        case 4:
            return titoliE.count
        case 5:
            return titoliF.count

        default:
            return 0
        
    

    override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell 

        let cell = tableView.dequeueReusableCell(withIdentifier: "cellaCustom") as! Cella

        switch indexPath.section 
        case 0:
            cell.lbl_titolo.text = titoliA[indexPath.row]
            cell.lbl_artista.text = artistaA[indexPath.row]
            break
        case 1:
            cell.lbl_titolo.text = titoliB[indexPath.row]
            cell.lbl_artista.text = artistaB[indexPath.row]
            break
        case 2:
            cell.lbl_titolo.text = titoliC[indexPath.row]
            cell.lbl_artista.text = artistaC[indexPath.row]
            break
        case 3:
            cell.lbl_titolo.text = titoliD[indexPath.row]
            cell.lbl_artista.text = artistaD[indexPath.row]
            break
        case 4:
            cell.lbl_titolo.text = titoliE[indexPath.row]
            cell.lbl_artista.text = artistaE[indexPath.row]
            break
        case 5:
            cell.lbl_titolo.text = titoliF[indexPath.row]
            cell.lbl_artista.text = artistaF[indexPath.row]
            break

        default:
            break
        
        return cell
    

【问题讨论】：

是的，这是可能的。但显然，只使用一个大数组，不要将它们分开。您的数据不应该去同步化。对于搜索栏，请使用 filter()。现在搜索您的数据已同步更有意义，因此请仅使用一个大数组。

【参考方案1】：

首先，您需要将此代码添加到您的 viewDidLoad 方法中：

    searchController.searchResultsUpdater = self
    searchController.obscuresBackgroundDuringPresentation = false
    searchController.searchBar.placeholder = "Search Events"
    navigationItem.searchController = searchController
    definesPresentationContext = true

接下来，在你的类中添加这个委托方法：

func filterContentForSearchText(_ searchText: String, scope: String = "All") 
    //Filter artists based on searchText here

    self.reloadData()

【讨论】：

如果您有任何问题，请尽管问

你能给我一个教程，我可以在其中找到如何实现 filterContentForSearchText 吗？？

这个答案应该可以帮助***.com/questions/41663233/tableview-search-in-swift