如何使用 java 播放 .wav 文件
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【中文标题】如何使用 java 播放 .wav 文件【英文标题】:How to play .wav files with java 【发布时间】:2011-01-25 21:26:16 【问题描述】:我正在尝试使用 Java 播放 *.wav 文件。我希望它执行以下操作: 按下按钮时,播放短促的哔声。
我已经用谷歌搜索过了,但大部分代码都不起作用。谁能给我一个简单的代码 sn-p 来播放 .wav 文件?
【问题讨论】:
【参考方案1】:没有java反射的解决方案DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat)
Java 反射会降低性能。
运行:java playsound absoluteFilePathTo/file.wav
import javax.sound.sampled.*;
import java.io.*;
public class playsound
public static void main (String args[]) throws Exception
playSound (args[0]);
public static void playSound () throws Exception
AudioInputStream
audiostream = AudioSystem.getAudioInputStream(new File (filename));
int BUFFER_SIZE = 128000;
AudioFormat audioFormat = null;
SourceDataLine sourceLine = null;
audioFormat = audioStream.getFormat();
sourceLine = AudioSystem.getSourceDataLine(audioFormat);
sourceLine.open(audioFormat);
sourceLine.start();
int nBytesRead = 0;
byte[] abData = new byte[BUFFER_SIZE];
while (nBytesRead != -1)
try
nBytesRead =
audioStream.read(abData, 0, abData.length);
catch (IOException e)
e.printStackTrace();
if (nBytesRead >= 0)
int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
sourceLine.drain();
sourceLine.close();
【讨论】:
【参考方案2】:使用AudioInputStream
的另一种方法:
import java.io.File;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.Clip;
import javax.sound.sampled.Line;
import javax.sound.sampled.LineEvent;
import javax.sound.sampled.LineListener;
import javax.swing.JDialog;
import javax.swing.JFileChooser;
public class CoreJavaSound extends Object implements LineListener
File soundFile;
JDialog playingDialog;
Clip clip;
public static void main(String[] args) throws Exception
CoreJavaSound s = new CoreJavaSound();
public CoreJavaSound() throws Exception
JFileChooser chooser = new JFileChooser();
chooser.showOpenDialog(null);
soundFile = chooser.getSelectedFile();
System.out.println("Playing " + soundFile.getName());
Line.Info linfo = new Line.Info(Clip.class);
Line line = AudioSystem.getLine(linfo);
clip = (Clip) line;
clip.addLineListener(this);
AudioInputStream ais = AudioSystem.getAudioInputStream(soundFile);
clip.open(ais);
clip.start();
public void update(LineEvent le)
LineEvent.Type type = le.getType();
if (type == LineEvent.Type.OPEN)
System.out.println("OPEN");
else if (type == LineEvent.Type.CLOSE)
System.out.println("CLOSE");
System.exit(0);
else if (type == LineEvent.Type.START)
System.out.println("START");
playingDialog.setVisible(true);
else if (type == LineEvent.Type.STOP)
System.out.println("STOP");
playingDialog.setVisible(false);
clip.close();
【讨论】:
为什么是extends Object
?
@MazeOfEncryption 我真的不记得了 :)【参考方案3】:
您也可以通过这种方式使用 AudioStream:
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import sun.audio.AudioPlayer;
import sun.audio.AudioStream;
public class AudioWizz extends JPanel implements ActionListener
private static final long serialVersionUID = 1L; //you like your cereal and the program likes their "serial"
static AudioWizz a;
static JButton playBuddon;
static JFrame frame;
public static void main(String arguments[])
frame= new JFrame("AudioWizz");
frame.setSize(300,300);
frame.setVisible(true);
a= new AudioWizz();
playBuddon= new JButton("PUSH ME");
playBuddon.setBounds(10,10,80,30);
playBuddon.addActionListener(a);
frame.add(playBuddon);
frame.add(a);
public void actionPerformed(ActionEvent e) //an eventListener
if (e.getSource() == playBuddon)
try
InputStream in = new FileInputStream("*.wav");
AudioStream sound = new AudioStream(in);
AudioPlayer.player.start(sound);
catch(FileNotFoundException e1)
e1.printStackTrace();
catch (IOException e1)
e1.printStackTrace();
【讨论】:
【参考方案4】:将播放 WAV 文件的类,在声音播放完毕之前一直阻塞:
class Sound implements Playable
private final Path wavPath;
private final CyclicBarrier barrier = new CyclicBarrier(2);
Sound(final Path wavPath)
this.wavPath = wavPath;
@Override
public void play() throws LineUnavailableException, IOException, UnsupportedAudioFileException
try (final AudioInputStream audioIn = AudioSystem.getAudioInputStream(wavPath.toFile());
final Clip clip = AudioSystem.getClip())
listenForEndOf(clip);
clip.open(audioIn);
clip.start();
waitForSoundEnd();
private void listenForEndOf(final Clip clip)
clip.addLineListener(event ->
if (event.getType() == LineEvent.Type.STOP) waitOnBarrier();
);
private void waitOnBarrier()
try
barrier.await();
catch (final InterruptedException ignored)
catch (final BrokenBarrierException e)
throw new RuntimeException(e);
private void waitForSoundEnd()
waitOnBarrier();
【讨论】:
【参考方案5】:这是我在不使用 sun 的情况下能想到的最优雅的形式。*:
import java.io.*;
import javax.sound.sampled.*;
try
File yourFile;
AudioInputStream stream;
AudioFormat format;
DataLine.Info info;
Clip clip;
stream = AudioSystem.getAudioInputStream(yourFile);
format = stream.getFormat();
info = new DataLine.Info(Clip.class, format);
clip = (Clip) AudioSystem.getLine(info);
clip.open(stream);
clip.start();
catch (Exception e)
//whatevers
【讨论】:
我听不到使用此示例代码发出的任何音频。我有什么遗漏的吗? 应该是完整的,不过也是五岁了,丑陋的。我确信有更好的方法,使用漂亮的 Java 库。 要听到输出,您应该延迟应用程序终止一段播放时间。尝试将Thread.sleep(1000)
放在clip.start()
之后。【参考方案6】:
您可以在播放后使用事件监听器关闭剪辑
import java.io.File;
import javax.sound.sampled.*;
public void play(File file)
try
final Clip clip = (Clip)AudioSystem.getLine(new Line.Info(Clip.class));
clip.addLineListener(new LineListener()
@Override
public void update(LineEvent event)
if (event.getType() == LineEvent.Type.STOP)
clip.close();
);
clip.open(AudioSystem.getAudioInputStream(file));
clip.start();
catch (Exception exc)
exc.printStackTrace(System.out);
【讨论】:
如果你想等到音频流被线路处理,你可以在句子开头添加“clip.drain()”。【参考方案7】:最后我设法做到了以下,它工作正常
import java.io.File;
import java.io.IOException;
import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;
public class MakeSound
private final int BUFFER_SIZE = 128000;
private File soundFile;
private AudioInputStream audioStream;
private AudioFormat audioFormat;
private SourceDataLine sourceLine;
/**
* @param filename the name of the file that is going to be played
*/
public void playSound(String filename)
String strFilename = filename;
try
soundFile = new File(strFilename);
catch (Exception e)
e.printStackTrace();
System.exit(1);
try
audioStream = AudioSystem.getAudioInputStream(soundFile);
catch (Exception e)
e.printStackTrace();
System.exit(1);
audioFormat = audioStream.getFormat();
DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
try
sourceLine = (SourceDataLine) AudioSystem.getLine(info);
sourceLine.open(audioFormat);
catch (LineUnavailableException e)
e.printStackTrace();
System.exit(1);
catch (Exception e)
e.printStackTrace();
System.exit(1);
sourceLine.start();
int nBytesRead = 0;
byte[] abData = new byte[BUFFER_SIZE];
while (nBytesRead != -1)
try
nBytesRead = audioStream.read(abData, 0, abData.length);
catch (IOException e)
e.printStackTrace();
if (nBytesRead >= 0)
@SuppressWarnings("unused")
int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
sourceLine.drain();
sourceLine.close();
【讨论】:
这个对我不起作用。我推荐一个非常简单的:http://alvinalexander.com/java/java-audio-example-java-au-play-sound 说真的,如果这是在 Java 中播放 wav 声音所需要的,那么我将停止使用 Java,幸运的是我怀疑这是正确的。 如果你在游戏循环中尝试这个,它会冻结游戏【参考方案8】:最短形式(无需安装随机库)?
public static void play(String filename)
try
Clip clip = AudioSystem.getClip();
clip.open(AudioSystem.getAudioInputStream(new File(filename)));
clip.start();
catch (Exception exc)
exc.printStackTrace(System.out);
唯一的问题是没有好的方法可以让这个方法阻塞在 *.wav 完成后关闭和处理数据。
clip.drain()
说它正在阻塞,但事实并非如此。剪辑未在之后 start()
运行。
我发现的唯一可行但 UGLY 的方法是:
// ...
clip.start();
while (!clip.isRunning())
Thread.sleep(10);
while (clip.isRunning())
Thread.sleep(10);
clip.close();
【讨论】:
【参考方案9】:sn-p here 工作正常,用 windows 声音测试:
public static void main(String[] args)
AePlayWave aw = new AePlayWave( "C:\\WINDOWS\\Media\\tada.wav" );
aw.start();
【讨论】:
如果您仍然有问题,请尝试更换声音设备。另请参阅此处推荐的工具***.com/questions/2175318/…以上是关于如何使用 java 播放 .wav 文件的主要内容,如果未能解决你的问题,请参考以下文章
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