@ModelAttribute 不适用于 Spring Security

Posted 2023-02-27

【中文标题】@ModelAttribute 不适用于 Spring Security

【英文标题】：@ModelAttribute is not working with spring security

【发布时间】：2015-11-03 18:47:27

【问题描述】：

我试图在登录失败时重定向登录页面上输入的用户名，但在我的控制器中，从“@ModelAttribute("user")”检索到的用户的用户名为空。当我不使用弹簧安全时，这是可行的。

我假设表单实际上首先发布到 Spring Security，然后它被重定向到控制器，因此输入的信息在 Spring Security 之间丢失。

如何在不将用户发送到链接参数的情况下检索用户？

PS：我尝试为“/loginFailed”创建一个控制器，并在登录失败时将其发送到那里，并在该控制器上使用 method = RequestMethod.POST。

登录控制器

@RequestMapping(value = "/login", method = RequestMethod.GET)
    public String listPersons(@ModelAttribute("user") User u, @RequestParam(required = false) String authfailed, String logout,
            String denied, Model model) 
        model.addAttribute("user", u);
        String message = "";
        if (authfailed != null) 
            message = "Invalid username or password, try again !";
         else if (logout != null) 
            message = "Logged Out successfully, login again to continue !";
         else if (denied != null) 
            message = "Access denied for this user !";
        
        model.addAttribute("error", message);
        return "login";
    

---

login.jsp

<c:url var="trylogin" value="/j_spring_security_check" ></c:url>
<c:url var="register" value="/register" ></c:url>

<div id="login-box">
    <form:form action="" modelAttribute="user" method="POST">
        <table>
            <tr>
                <td> <form:label path="username"> <spring:message text="Username: "/> </form:label> </td>
                <td> <form:input path="username" /> </td> 
            </tr>
            <tr>
                <td> <form:label path="password"> <spring:message text="Password: "/> </form:label> </td>
                <td> <form:password path="password" /> </td> 
            </tr>
            <tr>
                <td> <input type="submit" value="<spring:message text="Login"/>"
                                    onclick="document.getElementById('user').setAttribute('action', '$trylogin')"/> </td>
                <td> <input type="submit" value="<spring:message text="Register"/>"
                                    onclick="document.getElementById('user').setAttribute('action', '$register')"/> </td>
            </tr>
        </table>
    </form:form>
    <c:if test="$not empty error">
        <div class="error">$error</div>
    </c:if>
</div>

---

编辑（解决方案）：

谢谢@James，创建一个 failureHandler 是可行的方法，但是您的解决方案不能正常工作，因为即使我有“authentication-failure-url =”，您似乎在 failureHandler bean 中也需要“p:defaultFailureUrl” /login?authfailed"" 在表单登录中

<bean id="failureHandler" class="org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler"
    p:useForward="true"
    p:defaultFailureUrl="/login"/>

之后我不得不为 /login 添加另一个函数，因为 p:defaultFailureUrl="/login?authFailed" 只会将它作为 /login 发送，并且浏览器上的链接保持为 "/j_spring_security_check" 我不能'不明白为什么。

@RequestMapping(value = "/login", method = RequestMethod.POST)
public String loginFail(@ModelAttribute("user") User u, @RequestParam(required = false) String authfailed, RedirectAttributes redirectAttrs) 
    redirectAttrs.addFlashAttribute("user", u);
    redirectAttrs.addFlashAttribute("error", "Invalid username or password, try again !");
    return "redirect:/login";

【参考方案1】：

您应该使用 AuthenticationFailureHandler。出于您的目的，声明 Spring SimpleUrlAuthenticationFailureHandler 类的 bean 并指定将请求转发到目标 URL 而不是配置中的默认重定向行为就足够了。这样，您的登录控制器将可以访问包括用户名在内的原始请求。

文档：http://docs.spring.io/autorepo/docs/spring-security/3.2.1.RELEASE/apidocs/org/springframework/security/web/authentication/SimpleUrlAuthenticationFailureHandler.html

来源：https://github.com/spring-projects/spring-security/blob/master/web/src/main/java/org/springframework/security/web/authentication/SimpleUrlAuthenticationFailureHandler.java

<bean id="failureHandler" class="org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler"
    p:useForward="true"
/>

然后在您的表单登录规范中：

<security:form-login 
    ...
    authentication-failure-handler-ref="failureHandler"
    ...
/> 

【参考方案2】：

这是错误的方法。登录页面控制器仅用于查看此页面。对于检查凭证，您需要创建服务，例如：

@Service("adminDetailsServiceImpl")
public class AdminDetailsServiceImpl implements UserDetailsService 
    @Autowired
    private SepAdminDao adminDao;

    @Override
    public UserDetails loadUserByUsername(String login) 
        SepAdmin admin;

        if (StringUtils.isBlank(login))
            throw new UsernameNotFoundException("Admin not found!");
        admin = adminDao.findByEmail(login);
        return new org.springframework.security.core.userdetails.User(
                admin.getEmail(),
                admin.getPassword(),
                getGrantedAuthorities(admin.getRole().getPermissionNames()));
    

    private static List<GrantedAuthority> getGrantedAuthorities(String[] roles) 
        List<GrantedAuthority> authorities = new ArrayList<>();
        for (String role : roles)
            authorities.add(new SimpleGrantedAuthority(role));
        return authorities;
    

用 spring 分配这个服务（例如我查看我的简单安全配置）：

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
             xmlns:beans="http://www.springframework.org/schema/beans"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security.xsd">
    <beans:bean id="roleHierarchy" class="org.springframework.security.access.hierarchicalroles.RoleHierarchyImpl">
        <beans:property name="hierarchy">
            <beans:value>
                <!--Admin-->
                PERM_ROOT > PERM_CREATE_ADMINS
                PERM_CREATE_ADMINS > PERM_DELETE_ADMINS
                PERM_DELETE_ADMINS > PERM_EDIT_ADMINS
                PERM_EDIT_ADMINS > PERM_VIEW_ADMINS
                <!--Role-->
                PERM_ROOT > PERM_CREATE_ROLES
                PERM_CREATE_ROLES > PERM_DELETE_ROLES
                PERM_DELETE_ROLES > PERM_EDIT_ROLES
                PERM_EDIT_ROLES > PERM_VIEW_ROLES
            </beans:value>
        </beans:property>
    </beans:bean>
    <beans:bean id="expressionHandler"
                class="org.springframework.security.web.access.expression.DefaultWebSecurityExpressionHandler">
        <beans:property name="roleHierarchy" ref="roleHierarchy"/>
    </beans:bean>
    <beans:bean id="accessDecisionManager" class="org.springframework.security.access.vote.AffirmativeBased">
        <beans:property name="decisionVoters">
            <beans:list>
                <beans:bean class="org.springframework.security.web.access.expression.WebExpressionVoter">
                    <beans:property name="expressionHandler" ref="expressionHandler"/>
                </beans:bean>
            </beans:list>
        </beans:property>
    </beans:bean>
    <beans:bean id="roleVoter" class="org.springframework.security.access.vote.RoleHierarchyVoter">
        <beans:constructor-arg ref="roleHierarchy"/>
    </beans:bean>
    <beans:bean id="passwordEncoder"
                class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
        <beans:constructor-arg value="10"/>
    </beans:bean>
    <http pattern="/resources/js/vendor/language" security="none"/>
    <http pattern="/favicon.ico" security="none"/>
    <http auto-config="true" use-expressions="true" access-denied-page="/403"
          access-decision-manager-ref="accessDecisionManager">
        <intercept-url pattern="/login" access="permitAll"/>
        <!--Admin-->
        <intercept-url pattern="/dashboard" access="hasRole('PERM_ROOT')"/>
        <intercept-url pattern="/admin/create_admin" access="hasRole('PERM_CREATE_ADMINS')"/>
        <intercept-url pattern="/admin/users/*/edit_admin" access="hasRole('PERM_EDIT_ADMINS')"/>
        <intercept-url pattern="/admin/users/*/view_admin" access="hasRole('PERM_VIEW_ADMINS')"/>
        <intercept-url pattern="/admin/users/*/delete_admin" access="hasRole('PERM_DELETE_ADMINS')"/>
        <!--Role-->
        <intercept-url pattern="/role/create_role" access="hasRole('PERM_CREATE_ROLES')"/>
        <intercept-url pattern="/role/*/edit_role" access="hasRole('PERM_EDIT_ROLES')"/>
        <intercept-url pattern="/role/*/view_role" access="hasRole('PERM_VIEW_ROLES')"/>
        <intercept-url pattern="/role/*/delete_role" access="hasRole('PERM_DELETE_ROLES')"/>
        <!--Route-->
        <form-login username-parameter="email"
                    password-parameter="password"
                    login-page="/login" default-target-url="/" authentication-failure-url="/login?failed"/>
        <logout logout-url="/logout" logout-success-url="/login"/>
    </http>
    <authentication-manager alias="authManager">
        <authentication-provider user-service-ref="adminDetailsServiceImpl">
            <password-encoder ref="passwordEncoder"/>
        </authentication-provider>
    </authentication-manager>
</beans:beans>

然后当用户提交登录表单时，我们重定向到 /j_spring_security_check 使用我们的服务的地方，如果我们有登录异常，我们可以在登录 jsp 页面检查它：

<!-- spring_exception -->
<c:if test="$not empty SPRING_SECURITY_LAST_EXCEPTION">
    <p class="alert alert-danger alert-dismissable">
        <spring:message code="Error.Msg.Login"/>
    </p>
    <br/>
</c:if>

如果成功，我们将重定向到默认目标 url，在我的例子中 - 到 root。

 <form-login username-parameter="email"
         password-parameter="password"
         login-page="/login" default-target-url="/" authentication-failure-url="/login?failed"/>

这就是为什么浏览器上的链接保持为“/j_spring_security_check”的原因。