jdbcAuthentication() 而不是 inMemoryAuthentication() 不提供访问权限 - Spring Security 和 Spring Data JPA
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【中文标题】jdbcAuthentication() 而不是 inMemoryAuthentication() 不提供访问权限 - Spring Security 和 Spring Data JPA【英文标题】:jdbcAuthentication() instead of inMemoryAuthentication() doesn't give access - Spring Security and Spring Data JPA 【发布时间】:2019-01-09 13:48:08 【问题描述】:我只是使用 spring mvc、gradle、spring security、spring data jpa 创建简单的应用程序。现在我想测试一下 spring security 是如何工作的,但是我有一个问题。首先我给你看一点代码,然后我会提到我的问题。
结构:
Person.java
package com.test.business;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name = "person")
public class Person
@Id
@Column(name = "id")
private int id;
@Column(name = "name")
private String name;
@Column(name = "password")
private String password;
@Column(name = "role")
private String role;
public Person()
public Person(int id, String name, String password, String role)
this.id = id;
this.name = name;
this.password = password;
this.role = role;
//setters and getters
PersonController.java
package com.test.controller;
import com.test.service.PersonService;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.ResponseBody;
@Controller
public class PersonController
@Autowired
private PersonService personService;
@GetMapping(value="/")
@ResponseBody
public String printWelcome()
return "home";
@GetMapping(value="/admin")
@ResponseBody
public String admin()
return "admin";
@GetMapping(value="/user")
@ResponseBody
public String user()
return "user";
MyWebInitializer.java
package com.test.config;
import org.springframework.web.servlet.support.AbstractAnnotationConfigDispatcherServletInitializer;
public class MyWebInitializer extends
AbstractAnnotationConfigDispatcherServletInitializer
@Override
protected Class<?>[] getRootConfigClasses()
return new Class[] RootConfig.class, SecurityConfig.class ;
@Override
protected Class<?>[] getServletConfigClasses()
return new Class[] WebConfig.class ;
@Override
protected String[] getServletMappings()
return new String[] "/" ;
SecurityWebInitializer.java
package com.test.config;
import org.springframework.security.web.context.AbstractSecurityWebApplicationInitializer;
public class SecurityWebInitializer
extends AbstractSecurityWebApplicationInitializer
RootConfig.java
package com.test.config;
import java.util.Properties;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.context.annotation.Import;
import org.springframework.context.annotation.PropertySource;
import org.springframework.core.env.Environment;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.jdbc.datasource.DriverManagerDataSource;
import org.springframework.orm.jpa.JpaTransactionManager;
import org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean;
import org.springframework.orm.jpa.vendor.Database;
import org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter;
import org.springframework.transaction.PlatformTransactionManager;
import org.springframework.transaction.annotation.EnableTransactionManagement;
@Configuration
@EnableJpaRepositories( basePackages = "com.test.repository")
@PropertySource(value = "classpath:application.properties" )
@EnableTransactionManagement
@Import( SecurityConfig.class )
@ComponentScan(basePackages = "com.test.service", "com.test.repository", "com.test.controller", "com.test.business")
public class RootConfig
@Autowired
private Environment environment;
@Autowired
private DataSource dataSource;
@Bean
public DataSource dataSource()
DriverManagerDataSource dataSource = new DriverManagerDataSource();
dataSource.setDriverClassName(environment.getRequiredProperty("jdbc.driverClassName"));
dataSource.setUrl(environment.getRequiredProperty("jdbc.url"));
dataSource.setUsername(environment.getRequiredProperty("jdbc.username"));
dataSource.setPassword(environment.getRequiredProperty("jdbc.password"));
return dataSource;
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory()
HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
vendorAdapter.setDatabase(Database.POSTGRESQL);
vendorAdapter.setGenerateDdl(true);
vendorAdapter.setShowSql(true);
LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setJpaVendorAdapter(vendorAdapter);
factory.setPackagesToScan("com.test.business");
factory.setDataSource(dataSource());
factory.setJpaProperties(jpaProperties());
return factory;
private Properties jpaProperties()
Properties properties = new Properties();
properties.put("hibernate.dialect", environment.getRequiredProperty("hibernate.dialect"));
properties.put("hibernate.show_sql", environment.getRequiredProperty("hibernate.show_sql"));
properties.put("hibernate.format_sql", environment.getRequiredProperty("hibernate.format_sql"));
return properties;
@Bean
public PlatformTransactionManager transactionManager()
JpaTransactionManager txManager = new JpaTransactionManager();
txManager.setEntityManagerFactory(entityManagerFactory().getObject());
return txManager;
WebConfig.java
package com.test.config;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.ViewResolverRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurer;
@EnableWebMvc
@Configuration
@ComponentScan( "com.test.controller" )
public class WebConfig implements WebMvcConfigurer
@Override
public void addResourceHandlers(ResourceHandlerRegistry registry)
registry.addResourceHandler("/resources/**")
.addResourceLocations("/resources/");
@Override
public void configureViewResolvers(ViewResolverRegistry registry)
registry.jsp().prefix("/WEB-INF/views/").suffix(".jsp");
SecurityConfig.java
package com.test.config;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter
@Autowired
private DataSource dataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception
auth.jdbcAuthentication().dataSource(dataSource)
.usersByUsernameQuery("select name, password"
+ " from person where name=?")
.authoritiesByUsernameQuery("select name, role"
+ "from person where name=?");
@Override
protected void configure(HttpSecurity http) throws Exception
http.authorizeRequests().antMatchers("/admin").hasRole("ADMIN")
.and()
.httpBasic(); // Authenticate users with HTTP basic authentication
在 DB 中记录为 JSON:
"id": 1,
"name": "test1",
"password": "test1",
"role": "ADMIN"
还有什么问题?查看 SecurityConfig.java。有 jdbcAuthentication()。当我尝试访问 /admin 时,浏览器会要求我输入用户名和密码。不幸的是,当我这样做时,什么也没发生,浏览器会一次又一次地询问。
我改变了一点我的代码。在 SecurityConfig.java 而不是 jdbcAuthentication() 我使用 inMemoryAuthentication() 所以它看起来像:
SecurityConfig.java
@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter
@Autowired
private DataSource dataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception
auth.inMemoryAuthentication().withUser("user").password("password").roles("ADMIN");
@Override
protected void configure(HttpSecurity http) throws Exception
http.authorizeRequests().antMatchers("/admin").hasRole("ADMIN")
.and()
.httpBasic(); // Authenticate users with HTTP basic authentication
现在我尝试访问 /admin。浏览器要求我输入用户名和密码,当我这样做时,我将获得对 /admin 的访问权限。这是为什么?为什么我无法使用 jdbcAuthentication() 获得访问权限?你能给我一些建议吗?
【问题讨论】:
【参考方案1】:我猜是你的查询错误
auth.jdbcAuthentication().dataSource(dataSource)
.usersByUsernameQuery("select name, password"
+ " from person where name=?")
.authoritiesByUsernameQuery("select name, role"
+ "from person where name=?");
jdbcAuthentication 期望
对于 users-by-username-query:username
、password
和 enabled
对于 authorities-by-username-query username
和 role
所以对你来说这应该有效:
auth.jdbcAuthentication().dataSource(dataSource)
.usersByUsernameQuery("select name as username, password, true"
+ " from person where name=?")
.authoritiesByUsernameQuery("select name as username, role"
+ " from person where name=?");
【讨论】:
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