Jackson XML 反序列化问题
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【中文标题】Jackson XML 反序列化问题【英文标题】:Jackson XML Deserialisation Issue 【发布时间】:2018-10-26 17:22:47 【问题描述】:我能够编写 XML 文档,但是无法反序列化创建的 XML。原始代码在 Kotlin 中,但我发布了 Java 等效代码。
@JacksonXmlRootElement(localName = "assets")
public class Assets
@JacksonXmlElementWrapper(useWrapping = false)
private Asset[] asset;
public Assets(Asset[] asset)
this.asset = asset;
public Asset[] getAsset()
return asset;
public void setAsset(Asset[] asset)
this.asset = asset;
public class Asset
@JacksonXmlProperty(isAttribute = true)
private String type;
@JacksonXmlProperty(isAttribute = true)
private String name;
@JacksonXmlProperty(isAttribute = true)
private String displayName;
@JacksonXmlElementWrapper(localName = "permissions")
private Permission[] permission;
public Asset(String type, String name, String displayName, Permission[] permission)
this.type = type;
this.name = name;
this.displayName = displayName;
this.permission = permission;
public String getType()
return type;
public void setType(String type)
this.type = type;
public String getName()
return name;
public void setName(String name)
this.name = name;
public String getDisplayName()
return displayName;
public void setDisplayName(String displayName)
this.displayName = displayName;
public Permission[] getPermission()
return permission;
public void setPermission(Permission[] permission)
this.permission = permission;
public class Permission
@JacksonXmlProperty(isAttribute = true)
private String name;
private Group[] group;
public Permission(String name, Group[] group)
this.name = name;
this.group = group;
public String getName()
return name;
public void setName(String name)
this.name = name;
public Group[] getGroup()
return group;
public void setGroup(Group[] group)
this.group = group;
用 (Kotlin) 实例化:
fun writeToXml(obj: Any) : String
val xmlMapper = XmlMapper()
xmlMapper.enable(SerializationFeature.INDENT_OUTPUT)
return xmlMapper.writeValueAsString(obj)
val assets = Assets(arrayOf(
Asset("bdo", "approval-matrix", "Approval Matrix", arrayOf(Permission("Create", arrayOf(Group(arrayOf("Admin", "Approver")))))),
Asset("bdo", "approval-matrix-2", "Approval Matrix 2", arrayOf(Permission("Delete", arrayOf(Group(arrayOf("Admin", "Approver")), Group(arrayOf("Admin-2", "Approver-2"))))))))
val xmlModule = JacksonXmlModule()
val objectMapper = XmlMapper(xmlModule)
println(writeToXml(assets))
生成的 XML 符合预期:
<assets>
<asset type="bdo" name="approval-matrix" displayName="Approval Matrix">
<permissions>
<permission name="Create">
<groups>
<group>Admin</group>
<group>Approver</group>
</groups>
</permission>
</permissions>
</asset>
<asset type="bdo" name="approval-matrix-2" displayName="Approval Matrix 2">
<permissions>
<permission name="Delete">
<groups>
<group>Admin</group>
<group>Approver</group>
</groups>
<groups>
<group>Admin-2</group>
<group>Approver-2</group>
</groups>
</permission>
</permissions>
</asset>
</assets>
但是在尝试反序列化时:
val generated = objectMapper.readValue<Assets>(xmlAssets)
我收到以下错误:
Exception in thread "main" com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `uk.co.processflows.configuration.entities.Assets` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator)
at [Source: (StringReader); line: 2, column: 3]
at com.fasterxml.jackson.databind.exc.InvalidDefinitionException.from(InvalidDefinitionException.java:67)
at com.fasterxml.jackson.databind.DeserializationContext.reportBadDefinition(DeserializationContext.java:1451)
at com.fasterxml.jackson.databind.DeserializationContext.handleMissingInstantiator(DeserializationContext.java:1027)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.deserializeFromObjectUsingNonDefault(BeanDeserializerBase.java:1290)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:326)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:159)
at com.fasterxml.jackson.dataformat.xml.deser.WrapperHandlingDeserializer.deserialize(WrapperHandlingDeserializer.java:113)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4001)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3011)
at uk.co.processflows.module.EntryPoint.main(EntryPoint.kt:58)
任何帮助将不胜感激。
【问题讨论】:
您是否尝试过按照错误提示添加默认构造函数?public Asset()
是的,同样的问题。
Assets
也一样?抱歉 - 我刚刚注意到错误是在谈论 Assets
类。
是的,我已经为每种类型添加了一个默认构造函数。
谢谢,每种类型的默认设置都已解决问题。
【参考方案1】:
只是为了澄清答案:
我包括
dependencies
...
compile(kotlin("reflect"))
compile("com.fasterxml.jackson.module:jackson-module-kotlin:2.9.+")
compile("com.fasterxml.jackson.dataformat:jackson-dataformat-xml:2.9.+")
...
在build.gradle.kts
然后有同样的问题。通过向构造函数添加默认值来更改我的数据类似乎可以解决它。即:
data class HelloWorld(val hello: Boolean, val world: Boolean)
变成
data class HelloWorld(val hello: Boolean = false, val world: Boolean = false)
然后:
const val xml = """
<HelloWorld>
<hello>true</hello>
<world>true</world>
</HelloWorld>
"""
将通过数据类在 kotlin 中正常序列化和反序列化。谢谢!
【讨论】:
【参考方案2】:现在有一个 Jackson 模块,允许它反序列化为 Kotlin 数据类无需添加默认构造函数。
见https://github.com/FasterXML/jackson-module-kotlin
compile "com.fasterxml.jackson.module:jackson-module-kotlin:2.9.+"
尝试将其添加到您的 Kotlin 项目中,这样您就可以保持您的域类“纯”。
【讨论】:
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