奏鸣曲管理员。如何将发布数据传递给另一个控制器
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【中文标题】奏鸣曲管理员。如何将发布数据传递给另一个控制器【英文标题】:Sonata admin. How to pass post data to another controller 【发布时间】:2017-07-01 19:21:47 【问题描述】:我是 Symfony 的新手,请原谅我的无知。
我有一个父实体“文章”和子实体,如“页面”、“新闻”等。它们有共同的字段,如标题、日期等。
我为文章创建了初始表单(在 ArticleAdmin 类中),可以在其中选择子实体的标题和类型,并尝试调用子实体的 Admin 类并在那里传递 POST 数据。但这不起作用,因为 Controller 中的 createAction 负责表单呈现及其处理,当我尝试在 createAction() 中覆盖它时,我收到错误“错误:调用私有方法 Sonata\AdminBundle\控制器\CRUDController::setFormTheme()"
这是我的代码:
ArticleAdmin - 父实体
<?php
namespace A26\CMS\ContentBundle\Admin;
use Sonata\AdminBundle\Admin\AbstractAdmin;
use Sonata\AdminBundle\Show\ShowMapper;
use Sonata\AdminBundle\Form\FormMapper;
use Sonata\AdminBundle\Datagrid\ListMapper;
use Sonata\AdminBundle\Datagrid\DatagridMapper;
class ArticleAdmin extends AbstractAdmin
// Fields to be shown on create/edit forms
protected function configureFormFields(FormMapper $formMapper)
$formMapper
->add('title', 'text', array(
'label' => 'Title'
))
->add('slug', 'text', array(
'label' => 'Slug'
))
->add('type', 'choice', array(
'choices' => array(
'Page' => 'Text Page',
'News' => 'News'
),
));
protected function configureDatagridFilters(DatagridMapper $datagridMapper)
$datagridMapper
->add('title');
protected function configureListFields(ListMapper $listMapper)
$listMapper
->addIdentifier('title')
->add('is_publish');
protected function configureShowFields(ShowMapper $showMapper)
$showMapper
->add('title');
?>
PageAdmin - 子实体
<?php
namespace A26\CMS\PagesBundle\Admin;
use Sonata\AdminBundle\Admin\AbstractAdmin;
use Sonata\AdminBundle\Show\ShowMapper;
use Sonata\AdminBundle\Form\FormMapper;
use Sonata\AdminBundle\Datagrid\ListMapper;
use Sonata\AdminBundle\Datagrid\DatagridMapper;
use Ivory\CKEditorBundle\Form\Type\CKEditorType;
class PageAdmin extends AbstractAdmin
// Fields to be shown on create/edit forms
protected function configureFormFields(FormMapper $formMapper)
$formMapper
->tab('Content')
->with('Content')
->add('title', 'text', array(
'label' => 'Title'
))
->add('content', CKEditorType::class, array(
'label' => 'Content'
))
->end()
->end();
// Fields to be shown on filter forms
protected function configureDatagridFilters(DatagridMapper $datagridMapper)
$datagridMapper
->add('title');
// Fields to be shown on lists
protected function configureListFields(ListMapper $listMapper)
$listMapper
->addIdentifier('title');
// Fields to be shown on show action
protected function configureShowFields(ShowMapper $showMapper)
$showMapper
->add('title');
?>
ArticleAdmin 控制器 - 我复制了 CRUDController 并替换了块
if ($form->isSubmitted()) ...
<?php
namespace A26\CMS\ContentBundle\Controller;
use Sonata\AdminBundle\Controller\CRUDController as Controller;
class ArticleAdminController extends Controller
public function createAction()
$request = $this->getRequest();
// the key used to lookup the template
$templateKey = 'edit';
$this->admin->checkAccess('create');
$class = new \ReflectionClass($this->admin->hasActiveSubClass() ? $this->admin->getActiveSubClass() : $this->admin->getClass());
if ($class->isAbstract())
return $this->render(
'SonataAdminBundle:CRUD:select_subclass.html.twig',
array(
'base_template' => $this->getBaseTemplate(),
'admin' => $this->admin,
'action' => 'create',
),
null,
$request
);
$object = $this->admin->getNewInstance();
$preResponse = $this->preCreate($request, $object);
if ($preResponse !== null)
return $preResponse;
$this->admin->setSubject($object);
/** @var $form \Symfony\Component\Form\Form */
$form = $this->admin->getForm();
$form->setData($object);
$form->handleRequest($request);
if ($form->isSubmitted())
$response = $this->forward("A26CMSPagesBundle:PageAdmin:create", array('_sonata_admin' => $this->container->get('request')->get('_sonata_admin')));
dump($response);
die();
$formView = $form->createView();
// set the theme for the current Admin Form
$this->setFormTheme($formView, $this->admin->getFormTheme());
return $this->render($this->admin->getTemplate($templateKey), array(
'action' => 'create',
'form' => $formView,
'object' => $object,
), null);
请帮忙!也许它可以用另一种方式实现?
提前致谢!!
【问题讨论】:
【参考方案1】:您的 $response 方式是正确的,但现在您需要在操作结束时返回它,否则转发将永远不会发生
【讨论】:
【参考方案2】:关于你得到的错误,
改为:
$this->setFormTheme($formView, $this->admin->getFormTheme());
使用:
$this->get('twig')->getExtension('form')->renderer->setTheme($formView, $this->admin->getFormTheme());
或者:
$this->get('twig')->getExtension('Symfony\Bridge\Twig\Extension\FormExtension')->renderer->setTheme($formView, $this->admin->getFormTheme());
【讨论】:
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