数据库中的值未插入codeIgniter？

Posted 2023-02-25

【中文标题】数据库中的值未插入codeIgniter？

【英文标题】：values in database not inserted in codeIgniter?

【发布时间】：2015-10-07 18:24:54

【问题描述】：

我是 php 框架的新手，我创建了一个简单的表单，想将它的值插入到数据库中，但没有这样做，不知道我错在哪里！！！

每次我得到 mysql 返回一个空结果集（即零行）。 我正在使用 CodeIgniter 3 和 mysqli 驱动程序这是我的控制器

<?php 
      //display_errors(on);
       error_reporting(E_ALL);

      class Register extends CI_Controller 

      public function index () 

      //Validations

      $rules=array (

                "username"=> array(
                    "field"=>"username",
                    "label"=>"Username",
                    "rules"=>"required|max_length[20]|min_length[5]|callback_username_is_taken"


                ),

                "password"=> array(
                    "field"=>"password",
                    "label"=>"Password",
                    "rules"=>"required|max_length[20]|min_length[6]"


                ),

                "pass_conf"=> array(
                    "field"=>"pass_conf",
                    "label"=>"Password",
                    "rules"=>"required|matches[password]"


                ),
                "email"=> array(
                    "field"=>"email",
                    "label"=>"Email",
                    "rules"=>"required|valid_email|callback_is_taken"


                )

      );

      //set the rules

      $this->form_validation->set_rules($rules);
      //Override the message
      $this->form_validation->set_message('required','The %s field is empty');

      // check to see if form has been submitted
      if ($this->form_validation->run()!=true) 
             $this->load->helper('url');
             $this->load->view('register'); //Display page
             $this->load->view('footer');
      else 
            echo "Donkey Butt";

            $form=array();
            $form['username']=$this->input->post("username");
            $form['password']=md5($this->input->post("password"));
            $form['email']=$this->input->post("email");

            if(self::createUser($form['username'],$form['password'],$form['email'])==true) 

                    //Created User Successfully
                    echo "Success";
                    //$this->load->view("success",$data);

            else
                echo "problem in subbmitting the form";
            


      
      

      public function username_is_taken($input) 





            $query="SELECT * FROM `tbl_usrs` WHERE  `username`=? ";
            $arg=array ($input);
            $exec=$this->db->query($query,$arg) or die(mysqli_error());
            echo $query;

            if($exec->num_rows() >0)

            
                $this->form_validation->set_message('username_is_taken','Sorry the UserName <b> $input </b> is already taken');
                return false;


            else 
                return true;
            

      


        public function email_is_taken($input) 

            $query="SELECT * FROM `tbl_usrs` WHERE `email`=? ";
            $arg=array ($input);
            $exec=$this->db->query($query,$arg) or die(mysqli_error());
            echo $query;
            if($exec->num_rows() >0)

            
                $this->form_validation->set_message('email_is_taken','Sorry the email <b> $input </b> is already taken');
                return false;


            else 
                return true;
            

      

      public function createUser($user,$pass,$email)
      
            $query="
                INSERT INTO `tbl_usrs` (`username`,`password`,`email`,`ip`)
                VALUES (?,?,?,?)

            ";
            $arg=array (self::protect($user),self::protect($password),$email,$_SERVER['REMOTE_ADDR']);

            if($this->db->query($query,$arg)==true)
            
                echo $query;
                return true; // if added to database
            else 
                    return false;
               


      

      public function protect($str) 
            return mysqli_real_escape_string($str);
      


      ?>

【问题讨论】：

请给一些调试代码的参考

这是我得到的错误 错误号：1048 列“用户名”不能为空 INSERT INTO tbl_usrs (username,password,email,ip) 值 ( NULL,NULL,'[e-mail]','::1') 文件名：C:/xampp/htdocs/koopanda/application/controllers/Register.php 行号：132

你必须有其他错误......我可以清楚地看到mysqli_real_escape_string只有参数你应该把mysqli_链接作为第一个参数

非常感谢，我没有注意到这一点，也没有认真对待

【参考方案1】：

修复 mysqli_real_escape_string($str); //两个参数除外，只有一个给定 修复是让你的代码工作