AFNetworking 2.0 发送带有字典参数数组的发布请求

Posted 2023-02-24

【中文标题】AFNetworking 2.0 发送带有字典参数数组的发布请求

【英文标题】：AFNetworking 2.0 Send Post Request with array of dictionary Parameters

【发布时间】：2016-03-07 05:39:15

【问题描述】：

我想在以下 API 中尝试 post 参数，但参数未正确传递，并且收到的响应给出了需要数据的消息。有谁能帮忙解决一下这个问题。

我的网址是

forapp.com/api/getContacts.php?data=[ “姓名”：“abc”，“电话”：“1234567890”，“姓名”：“凯特 铃","电话":"9925992599" ]

那么我如何将这种类型的请求传递给 api

   AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    NSDictionary *params = @@"name": @"hello",
                             @"phone": @"1234567890";
    NSLog(@"Dict %@",params);
    manager.responseSerializer.acceptableContentTypes = [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"text/html"];

[manager POST:@"http://forapp.com/api/getContacts.php" parameters:params success:^(AFHTTPRequestOperation *operation, id responseObject) 
    NSLog(@"JSON: %@", responseObject);

 failure:^(AFHTTPRequestOperation *operation, NSError *error) 
    NSLog(@"Error: %@", error);

];

【问题讨论】：

usu 喜欢这样。使用 AFNetworking 2.0 ***.com/questions/33767908/…

很容易调用 WS

查看我的回答希望对您有所帮助：- ***.com/a/35497323/3515115

【参考方案1】：

只需添加

第一步

// create the dictionary of "name":"abc","phone":"1234567890","name":"Kate Bell","phone":"9925992599" this

NSDictionary *params = @@"name": @"hello",
                         @"phone": @"1234567890";

第二步

//create the one array of this output [ "name":"abc","phone":"1234567890","name":"Kate Bell","phone":"9925992599" ]

NSMutableArray *arr = [NSMutableArray arrayWithObjects:params,nil];

第三步

// convert your object to JSOn String
NSError *error = nil;
NSString *createJSON = [[NSString alloc] initWithData:[NSJSONSerialization dataWithJSONObject:objectsInCart
                                                                                options:NSJSONWritingPrettyPrinted
                                                                                  error:&error]
                                       encoding:NSUTF8StringEncoding];

第四步

//create the another one dictionary for send the data for like data=[ "name":"abc","phone":"1234567890","name":"Kate Bell","phone":"9925992599" ]

 NSDictionary *pardsams = @@"data": createJSON;

第五步

  // finally start your request
  AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];

    NSLog(@"Dict %@",pardsams);
    manager.responseSerializer.acceptableContentTypes = [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"text/html"];

[manager POST:@"http://forapp.com/api/getContacts.php" parameters:pardsams success:^(AFHTTPRequestOperation *operation, id responseObject) 
    NSLog(@"JSON: %@", responseObject);

 failure:^(AFHTTPRequestOperation *operation, NSError *error) 
    NSLog(@"Error: %@", error);

];

【讨论】：

我不知道你可以将数组传递给你的请求，我们不知道你的请求的原因，尝试一次

不工作它需要提供相同的响应数据

@Birendra -- 检查更新的答案兄弟，它可以帮助你

@Birendra -- 我一步一步解释，对你有帮助

@Anbu.karthik objectsInCart 是什么？

【参考方案2】：

根据这个网址

forapp.com/api/getContacts.php?data=[ "name":"abc","phone":"1234567890","name":"Kate Bell","phone":"9925992599" ]

你应该这样实现

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    NSDictionary *params = @@"name": @"hello",
                             @"phone": @"1234567890";
    NSLog(@"Dict %@",params);
manager.responseSerializer = [AFJSONResponseSerializer serializer];

manager.requestSerializer = [AFJSONRequestSerializer serializer];

    manager.responseSerializer.acceptableContentTypes = [manager.responseSerializer.acceptableContentTypes setByAddingObject:@"text/html"];

[manager POST:@"http://forapp.com/api/getContacts.php" parameters:@@"data": @[params] success:^(AFHTTPRequestOperation *operation, id responseObject) 
    NSLog(@"JSON: %@", responseObject);

 failure:^(AFHTTPRequestOperation *operation, NSError *error) 
    NSLog(@"Error: %@", error);

];

【参考方案3】：

添加以下内容：

// httpClient is a subclass of AFHTTPRequestOperationManager or AFHTTPSessionManager
httpClient.requestSerializer = AFJSONRequestSerializer;

还要检查您的帖子数组是否包含任何其他对象。它只包含数组。