使用 JSON 从 Android 发送 Base64 图像到 php webservice，解码，保存到 SQL

Posted 2023-02-24

【中文标题】使用 JSON 从 Android 发送 Base64 图像到 php webservice，解码，保存到 SQL

【英文标题】：Send Base64 image from Android with JSON to php webservice, decode, save to SQL

【发布时间】：2013-08-31 23:38:09

【问题描述】：

正如描述所说，我正在 android 中拍照。它被压缩并添加到byte[]，然后添加到base64encoded。它使用 JSON 发送到我的 Web 服务，“应该”在该服务中对其进行解码并保存在 SQL 表行中。我可以将编码的字符串保存在单独的行中，这样我就知道它已经到了。

谁能看看这个并告诉我我哪里做错了？ *对不起，冗长的代码。如果有人提供帮助，我不想错过任何事情！

安卓端

@Override
    protected String doInBackground(String... args) 
        // TODO Auto-generated method stub
        // Check for success tag

        int success;
        stream = new ByteArrayOutputStream();
        picture.compress(Bitmap.CompressFormat.JPEG, 50, stream);
        image = stream.toByteArray();

        String ba1 = Base64.encodeToString(image, Base64.DEFAULT);

        SharedPreferences sp = PreferenceManager.getDefaultSharedPreferences(MainScreen.this);
        String post_username = sp.getString("username", "anon");

        try 
            ArrayList<NameValuePair> params = new ArrayList<NameValuePair>();
            params.add(new BasicNameValuePair("username", post_username));
            params.add(new BasicNameValuePair("picture", ba1));

           JSONObject json = jsonParser.makeHttpRequest(POST_COMMENT_URL,
                    "POST", params);


            success = json.getInt(TAG_SUCCESS);
            if (success == 1) 
                Log.d("Picture Added!", json.toString());
                //finish();
                return json.getString(TAG_MESSAGE);
             else 
                Log.d("Upload Failure!", json.getString(TAG_MESSAGE));
                return json.getString(TAG_MESSAGE);

            
         catch (JSONException e) 
            e.printStackTrace();
        

        return null;

    

    protected void onPostExecute(String file_url) 
        // dismiss the dialog once product deleted
        pDialog.dismiss();
        if (file_url != null) 
            Toast.makeText(MainScreen.this, file_url, Toast.LENGTH_LONG)
                    .show();
        

    

PHP 端

<?php
require("config.inc.php");
if (!empty($_POST)) 
    $user = $_POST['username'];
    $data = $_POST['picture'];
    $data = base64_decode($data);
    $im = imagecreatefromstring($data);
    header('Content-Type: image/jpeg', true);
    ob_start();
    imagejpeg($im);
    $imagevariable = ob_get_contents();
    ob_end_clean();

$query = "INSERT INTO pictures ( username, photo, rawdata ) VALUES ( :user, :photo, :raw ) ";

$query_params = array(
    ':user' => $user,
    ':photo' => $imagevariable,
    ':raw' => $_POST['picture']
);

try 
    $stmt   = $db->prepare($query);
    $result = $stmt->execute($query_params);

catch (PDOException $ex) 
    $response["success"] = 0;
    $response["message"] = "Database Error. Couldn't add post!";
    die(json_encode($response));

$response["success"] = 1;
$response["message"] = "Picture Successfully Added!";
echo json_encode($response);

 else 

?>

【问题讨论】：

rawdata 在 mysql 中设置的值是什么类型？ Blob 还是别的什么？

我正在使用 rawdata 来确认它正在从应用程序一直到数据库。 rawdata 只是一个文本行并存储了 base64 数据。在我可以解码和存储图像之后，我就不需要它了。这只是为了测试。

如果有人能引导我完成它，我也会很高兴使用多方。我认为弄清楚如何解码这个 base64 会更容易。

只要确保如果您在实时环境中使用它，它非常非常不安全，并且基本上所有内容都可以注入到图像字符串的 base64 版本中。

【参考方案1】：

我想发布我的解决方案，以防其他人遇到此问题。我总是来S.O.寻求答案，所以现在轮到我帮助别人了。我在使用位图时遇到了内存不足错误的问题。我将其更改为多部分帖子，以将图片作为文件和字符串上传，例如他们的名字，但您可以向其中添加任何字符串。第一部分是android端，下面是数据库的php。使用 move file 方法将图片添加到目录中的文件中。数据库存储该图片的路径。我搜索了两天，从堆栈溢出帖子中拼凑起来。

安卓

public void onClick(View v) 
    if (v.getId() == R.id.capture_btn) 
        try 

            Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
            startActivityForResult(intent, CAMERA_IMAGE_CAPTURE);

         catch (ActivityNotFoundException anfe) 

            String errorMessage = "Whoops - your device doesn't support capturing images!";
            Toast toast = Toast.makeText(this, errorMessage,
                    Toast.LENGTH_SHORT);
            toast.show();

        

    


@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) 
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == CAMERA_IMAGE_CAPTURE
            && resultCode == Activity.RESULT_OK) 
        getLastImageId();

        new PostPicture().execute();
    


private int getLastImageId() 
    // TODO Auto-generated method stub
    final String[] imageColumns =  MediaStore.Images.Media._ID,
            MediaStore.Images.Media.DATA ;
    final String imageOrderBy = MediaStore.Images.Media._ID + " DESC";
    Cursor imageCursor = managedQuery(
            MediaStore.Images.Media.EXTERNAL_CONTENT_URI, imageColumns,
            null, null, imageOrderBy);
    if (imageCursor.moveToFirst()) 
        int id = imageCursor.getInt(imageCursor
                .getColumnIndexOrThrow(MediaStore.Images.Media._ID));
        fullPath = imageCursor.getString(imageCursor
                .getColumnIndex(MediaStore.Images.Media.DATA));
        Log.d("pff", "getLastImageId: :id " + id);
        Log.d("pff", "getLastImageId: :path " + fullPath);
        return id;

     else 
        return 0;
    


class PostPicture extends AsyncTask<String, String, String> 

    @Override
    protected void onPreExecute() 
        super.onPreExecute();
        pDialog = new ProgressDialog(MainScreen.this);
        pDialog.setMessage("Uploading Picture");
        pDialog.setIndeterminate(false);
        pDialog.setCancelable(true);
        pDialog.show();

    

    @Override
    protected String doInBackground(String... args) 
        // TODO Auto-generated method stub
        // Check for success tag

        HttpClient client = new DefaultHttpClient();
        HttpPost post = new HttpPost("http://www.your-php-page.php");

        try 

            MultipartEntity entity = new MultipartEntity(
                    HttpMultipartMode.BROWSER_COMPATIBLE);
            File file = new File(fullPath);
            cbFile = new FileBody(file, "image/jpeg");
            Log.d("sending picture", "guest name is " + guest_name);
            Log.d("Sending picture", "guest code is " + guest_code);
            entity.addPart("name",
                    new StringBody(guest_name, Charset.forName("UTF-8")));
            entity.addPart("code",
                    new StringBody(guest_code, Charset.forName("UTF-8")));
            entity.addPart("picture", cbFile);
            post.setEntity(entity);

            HttpResponse response1 = client.execute(post);
            HttpEntity resEntity = response1.getEntity();
            String Response = EntityUtils.toString(resEntity);
            Log.d("Response", Response);

         catch (IOException e) 
            Log.e("asdf", e.getMessage(), e);

        
        return null;

    

    protected void onPostExecute(String file_url) 
        // dismiss the dialog once product deleted
        pDialog.dismiss();
        if (file_url != null) 
            Toast.makeText(MainScreen.this, file_url, Toast.LENGTH_LONG)
                    .show();
        

    

这就是 PHP。另请注意，我包括我的数据库登录页面。您可以输入您的分贝。密码并在此处登录，但我选择不这样做。

<?php
require("config.inc.php");
if (!empty($_POST)) 

if (empty($_POST['name'])) 
    $response["success"] = 0;
    $response["message"] = "Did not receive a name";
    die(json_encode($response));        
 else 
    $name = $_POST['name'];



if (empty($_FILES['picture'])) 
    $response["success"] = 0;
    $response["message"] = "Did not receive a picture";
    die(json_encode($response));        
 else 
    $file = $_FILES['picture'];



    $target_path = "uploads/whatever-you-want-it-to-be/";
            // It could be any string value above

    /* Add the original filename to our target path.  
    Result is "uploads/filename.extension" */
    $target_path = $target_path . basename( $_FILES['picture']['name']); 

    if(move_uploaded_file($_FILES['picture']['tmp_name'], $target_path)) 
        echo "The file ".  basename( $_FILES['picture']['name']). 
        " has been uploaded";
     else
        $response["success"] = 0;
        $response["message"] = "Database Error. Couldn't upload file.";
        die(json_encode($response));
    

 else 
    $response["success"] = 0;
    $response["message"] = "You have entered an incorrect code. Please try again.";
    die(json_encode($response));


$query = "INSERT INTO name-of-table ( directory, name, photo ) VALUES ( directory, :name, :photo ) ";

$query_params = array(
    ':directory' => $directory,
    ':name' => $name,
    ':photo' => $_FILES['picture']['name']
        );

try 
    $stmt   = $db->prepare($query);
    $result = $stmt->execute($query_params);

catch (PDOException $ex) 
    $response["success"] = 0;
    $response["message"] = "Database Error. Couldn't add path to picture";
    die(json_encode($response));

$response["success"] = 1;
$response["message"] = "Picture Successfully Added!";
die (json_encode($response));




?>

【讨论】：

你能展示你的其余代码吗，什么是 MultipartEntity 和 FileBody 所有这些都出错了？谢谢！

@Lion789 您可能没有传递正确的文件。上面的代码是完整的，除了定义文件和字符串。您可以在新问题中发布您的代码并向我发送链接吗？我会尽力帮忙的！

***.com/questions/21192778/… 有一个问题是我在尝试不同的方式时遇到了困境

感谢您的回答