自定义 URL 方案错误：此应用不允许查询方案

Posted 2023-02-24

【中文标题】自定义 URL 方案错误：此应用不允许查询方案

【英文标题】：Custom URL Scheme Error : This app is not allowed to query for scheme

【发布时间】：2019-10-22 10:34:46

【问题描述】：

我有 2 个应用程序，一个客户端和一个服务器。我正在尝试使用 URL 方案在 ios 应用程序之间进行应用程序间通信

（我已经参考了这个https://developer.apple.com/documentation/uikit/inter-process_communication/allowing_apps_and_websites_to_link_to_your_content/defining_a_custom_url_scheme_for_your_app作为指导）

这是客户端的plist

<dict>
    <key>CFBundleDevelopmentRegion</key>
    <string>$(DEVELOPMENT_LANGUAGE)</string>
    <key>CFBundleExecutable</key>
    <string>$(EXECUTABLE_NAME)</string>
    <key>CFBundleIdentifier</key>
    <string>$(PRODUCT_BUNDLE_IDENTIFIER)</string>
    <key>CFBundleInfoDictionaryVersion</key>
    <string>6.0</string>
    <key>CFBundleName</key>
    <string>$(PRODUCT_NAME)</string>
    <key>CFBundlePackageType</key>
    <string>APPL</string>
    <key>CFBundleShortVersionString</key>
    <string>1.0</string>
    <key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleTypeRole</key>
            <string>Viewer</string>
            <key>CFBundleURLName</key>
            <string>com.test.serverendapp</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>serverendapp</string>
            </array>
        </dict>
    </array>
    <key>CFBundleVersion</key>
    <string>1</string>
    <key>LSApplicationQueriesSchemes</key>
    <array>
        <string>com.test.serverendapp</string>
    </array>
    <key>LSRequiresIPhoneOS</key>
    <true/>
    <key>UILaunchStoryboardName</key>
    <string>LaunchScreen</string>
    <key>UIMainStoryboardFile</key>
    <string>Main</string>
    <key>UIRequiredDeviceCapabilities</key>
    <array>
        <string>armv7</string>
    </array>
    <key>UISupportedInterfaceOrientations</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
    <key>UISupportedInterfaceOrientations~ipad</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationPortraitUpsideDown</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
</dict>
</plist>

iOS端代码

@IBAction func tapToClient()
        let urlsrting = "com.test.serverEndApp://requestInfo?userID='22'"
        let url = URL(string: urlsrting)!
        if UIApplication.shared.canOpenURL(url)

            if #available(iOS 10.0, *) 
                UIApplication.shared.open(url, options: [:])  (success) in
                    print(" this is \(success)")
                

             else 
                UIApplication.shared.openURL(url)
            
        else

            let alertController = UIAlertController(title: "Error", message:
                "There is no such server app here", preferredStyle: .alert)
            alertController.addAction(UIAlertAction(title: "Dismiss", style: .default))

            self.present(alertController, animated: true, completion: nil)

        
    

服务器端

列表

<dict>
    <key>CFBundleDevelopmentRegion</key>
    <string>$(DEVELOPMENT_LANGUAGE)</string>
    <key>CFBundleExecutable</key>
    <string>$(EXECUTABLE_NAME)</string>
    <key>CFBundleIdentifier</key>
    <string>$(PRODUCT_BUNDLE_IDENTIFIER)</string>
    <key>CFBundleInfoDictionaryVersion</key>
    <string>6.0</string>
    <key>CFBundleName</key>
    <string>$(PRODUCT_NAME)</string>
    <key>CFBundlePackageType</key>
    <string>APPL</string>
    <key>CFBundleShortVersionString</key>
    <string>1.0</string>
    <key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleTypeRole</key>
            <string>Viewer</string>
            <key>CFBundleURLName</key>
            <string>com.test.clientendapp</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>clientendapp</string>
            </array>
        </dict>
    </array>
    <key>CFBundleVersion</key>
    <string>1</string>
    <key>LSApplicationQueriesSchemes</key>
    <array>
        <string>com.test.clientendapp</string>
    </array>
    <key>LSRequiresIPhoneOS</key>
    <true/>
    <key>UILaunchStoryboardName</key>
    <string>LaunchScreen</string>
    <key>UIMainStoryboardFile</key>
    <string>Main</string>
    <key>UIRequiredDeviceCapabilities</key>
    <array>
        <string>armv7</string>
    </array>
    <key>UISupportedInterfaceOrientations</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
    <key>UISupportedInterfaceOrientations~ipad</key>
    <array>
        <string>UIInterfaceOrientationPortrait</string>
        <string>UIInterfaceOrientationPortraitUpsideDown</string>
        <string>UIInterfaceOrientationLandscapeLeft</string>
        <string>UIInterfaceOrientationLandscapeRight</string>
    </array>
</dict>
</plist>

代码

 @IBAction func tapToServer()
        let urlsrting = "com.test.clientEndApp://provideInfo?username='Debanjan'"
        let url = URL(string: urlsrting)!
        if UIApplication.shared.canOpenURL(url)
            if #available(iOS 10.0, *) 
                UIApplication.shared.open(url, options: [:])  (success) in
                    print(" this is \(success)")
                

             else 
                UIApplication.shared.openURL(url)
            
        else
            let alertController = UIAlertController(title: "Error", message:
                "There is no such client app here", preferredStyle: .alert)
            alertController.addAction(UIAlertAction(title: "Dismiss", style: .default))

            self.present(alertController, animated: true, completion: nil)

        
    

我从他们那里得到的只是

-canOpenURL：URL 失败：“com.test.clientEndApp://provideInfo?username='Debanjan'” - 错误： "此应用不允许查询scheme com.test.clientendapp"

-canOpenURL：URL 失败：“com.test.serverEndApp://requestInfo?userID='22'” - 错误：“此应用 不允许查询方案 com.test.serverendapp"

我已按照所有步骤进行操作，但仍处于这种状态。帮助我意识到我做错了什么

我在 iPhone 8 iOS 12.2 模拟器上运行它，在 xcode 12.2 上

【问题讨论】：

在设备上运行，而不是模拟器。

【参考方案1】：

如果你注册，你就是在做相反的事情：

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>com.test.clientEndApp</string>
</array>

你应该调用这个方案

let urlsrting = "com.test.clientEndApp://provideInfo?username='Debanjan'"

您在LSApplicationQueriesSchemes 中缺少com.test.

【讨论】：

我就是这么做的。它仍然给我错误。请检查更新的 plist。

你做了什么？您仍然调用与您注册的方案不同的 url 之间存在差异：com.test.clientEndApp 和 clientEndApp

我更改了您提到的客户端和服务器应用程序的 url 方案。客户端应用现在有 serverendapp 方案，服务器有 clientendapp 方案

是的，即使加了com.test前缀，还是不行。我从你的观点理解，客户端应用程序应该指向 serverapp 的 url 方案，反之亦然。我这样做并运行了该项目。也清理了我的模拟器

看起来您没有尝试过，而且错误完全一样，您 100% 确定方案在各处设置的完全相同？

【参考方案2】：

所以，感谢@Lu_ 指出我的错误

积分： 1.客户端应用程序将具有服务器应用程序的方案，反之亦然 2. LS 应该有一个完整的名字，没有这样的 com.test 或什么不是