返回到相关对象的按钮

Posted 2023-02-24

【中文标题】返回到相关对象的按钮

【英文标题】：Back button to a related object

【发布时间】：2021-03-30 19:01:47

【问题描述】：

我正在构建一个应用程序，我可以在其中添加食谱并将配料添加到这些食谱中。在查看 recipe_details 时，我有一个 add_new_ingredient 按钮。当我使用 new_ingredient_form 时，我希望有 后退按钮 来返回食谱的详细信息。我正在尝试通过配方的 pk 但它不起作用。我怎样才能通过配方的 pk 才能回到以前的视图？

models.py

class Recipe(Timestamp):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False, unique=True)
    title = models.CharField(max_length=100, unique=True)
    preparation = models.TextField()

    def __str__(self):
        return self.title


class Ingredient(Timestamp):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False, unique=True)
    recipe = models.ForeignKey(Recipe, on_delete=models.CASCADE)
    name = models.CharField(max_length=100)
    amount = models.PositiveSmallIntegerField(blank=True, null=True)
    unit = models.ForeignKey('Unit', on_delete=models.SET_NULL, blank=True, null=True)

    def __str__(self):
        return self.name

views.py

class RecipeView(generic.DetailView):

    model = Recipe
    context_object_name = 'recipe'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['ingredients_list'] = Ingredient.objects.filter(recipe=self.object.pk)        
        return context
        

class AddIngredientView(generic.edit.CreateView):

    model = Ingredient
    fields = [
        'name',
        'amount',
        'unit'
    ]
    success_url = '/'
    template_name = 'recipes/add_ingredient.html'

    def dispatch(self, request, *args, **kwargs):
        self.recipe = get_object_or_404(Recipe, pk=self.kwargs['pk'])
        return super().dispatch(request, *args, **kwargs)

    def form_valid(self, form):
        form.instance.recipe = self.recipe
        return super().form_valid(form)

    def get_success_url(self):

        if 'add_another' in self.request.POST:
            url = reverse_lazy('recipes:add_ingredient', kwargs='pk': self.object.recipe_id)

        else:
            url = reverse_lazy('recipes:recipe', kwargs='pk': self.object.recipe_id)

        return url 

add_ingredient.html

% extends "base.html" %
% load crispy_forms_tags %

% block content %

<form method="POST">
    % csrf_token %
     form|crispy 
    <button class="btn btn-success" type="submit">Save</button>
    <button class="btn btn-success" type="submit" name="add_another">Save and add another</button>
    <a href="% url 'recipes:recipe' recipe.pk %", class="btn btn-primary", role="button">Back</a>

</form>

% endblock %

【参考方案1】：

您可以通过将request.META.HTTP_REFERER 添加到按钮的 href 属性来转到上一页。

Django request to find previous referrer