美丽的汤和uTidy

Posted 2023-02-23

【中文标题】美丽的汤和uTidy

【英文标题】：Beautiful Soup and uTidy

【发布时间】：2010-10-27 13:09:11

【问题描述】：

我想将utidy 的结果传递给Beautiful Soup，唉：

page = urllib2.urlopen(url)
options = dict(output_xhtml=1,add_xml_decl=0,indent=1,tidy_mark=0)
cleaned_html = tidy.parseString(page.read(), **options)
soup = BeautifulSoup(cleaned_html)

运行时出现如下错误：

Traceback (most recent call last):
  File "soup.py", line 34, in <module>
    soup = BeautifulSoup(cleaned_html)
  File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1499, in __init__
    BeautifulStoneSoup.__init__(self, *args, **kwargs)
  File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1230, in __init__
    self._feed(isHTML=isHTML)
  File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1245, in _feed
    smartQuotesTo=self.smartQuotesTo, isHTML=isHTML)
  File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1751, in __init__
    self._detectEncoding(markup, isHTML)
  File "/var/lib/python-support/python2.6/BeautifulSoup.py", line 1899, in _detectEncoding
    xml_encoding_match = re.compile(xml_encoding_re).match(xml_data)
TypeError: expected string or buffer

我收集 utidy 返回一个 XML 文档，而 BeautifulSoup 需要一个字符串。有没有办法投射clean_html？还是我做错了，应该采取不同的方法？

【参考方案1】：

将传递给 BeautifulSoup 的值转换为字符串。 在您的情况下，对最后一行进行以下编辑：

soup = BeautifulSoup(str(cleaned_html))

【参考方案2】：

只需将str() 包裹在cleaned_html 周围 将其传递给 BeautifulSoup 时。