Javascript查找经纬度和半径的位置
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【中文标题】Javascript查找经纬度和半径的位置【英文标题】：Javascript find location with lat,long and radius 【发布时间】：2020-08-01 18:32:37 【问题描述】：我需要找到所提供的经纬度和半径附近的所有位置。我想我可以通过使用地理围栏来实现这一点，但我不知道如何进行。我有以下数据。
设置 lat long 并获取每个 lat long 在5km 内的半径位置。
任何人帮助如何开始这个。
我的输入：
经纬度
33.450909, -112.073196
33.466210, -112.064620
33.451640, -112.099130
33.437160, -112.048400
33.480860, -112.082130
33.489950, -112.074700
目前尝试过：
<!DOCTYPE html >
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
<title>Creating a Store Locator on Google Maps</title>
<style>
/* Always set the map height explicitly to define the size of the div
* element that contains the map. */
#map
height: 100%;
/* Optional: Makes the sample page fill the window. */
html, body
height: 100%;
margin: 0;
padding: 0;
</style>
</head>
<body style="margin:0px; padding:0px;" onload="initMap()">
<div>
<label for="raddressInput">Search location:</label>
<input type="text" id="addressInput" size="15"/>
<label for="radiusSelect">Radius:</label>
<select id="radiusSelect" label="Radius">
<option value="50" selected>50 kms</option>
<option value="30">30 kms</option>
<option value="20">20 kms</option>
<option value="10">10 kms</option>
</select>
<input type="button" id="searchButton" value="Search"/>
</div>
<div><select id="locationSelect" style="width: 10%; visibility: hidden"></select></div>
<div id="map" style="width: 100%; height: 90%"></div>
<script>
var map;
var markers = [];
var infoWindow;
var locationSelect;
function initMap()
var sydney = lat: 33.450909, lng: -112.073196;
map = new google.maps.Map(document.getElementById('map'),
center: sydney,
zoom: 11,
mapTypeId: 'roadmap',
mapTypeControlOptions: style: google.maps.MapTypeControlStyle.DROPDOWN_MENU
);
infoWindow = new google.maps.InfoWindow();
searchButton = document.getElementById("searchButton").onclick = searchLocations;
locationSelect = document.getElementById("locationSelect");
locationSelect.onchange = function()
var markerNum = locationSelect.options[locationSelect.selectedIndex].value;
if (markerNum != "none")
google.maps.event.trigger(markers[markerNum], 'click');
;
function searchLocations()
var address = document.getElementById("addressInput").value;
var geocoder = new google.maps.Geocoder();
geocoder.geocode(address: address, function(results, status)
if (status == google.maps.GeocoderStatus.OK)
searchLocationsNear(results[0].geometry.location);
else
alert(address + ' not found');
);
function clearLocations()
infoWindow.close();
for (var i = 0; i < markers.length; i++)
markers[i].setMap(null);
markers.length = 0;
locationSelect.innerHTML = "";
var option = document.createElement("option");
option.value = "none";
option.innerHTML = "See all results:";
locationSelect.appendChild(option);
function searchLocationsNear(center)
clearLocations();
var radius = document.getElementById('radiusSelect').value;
var searchUrl = 'storelocator.php?lat=' + center.lat() + '&lng=' + center.lng() + '&radius=' + radius;
downloadUrl(searchUrl, function(data)
var xml = parseXml(data);
var markerNodes = xml.documentElement.getElementsByTagName("marker");
var bounds = new google.maps.LatLngBounds();
for (var i = 0; i < markerNodes.length; i++)
var id = markerNodes[i].getAttribute("id");
var name = markerNodes[i].getAttribute("name");
var address = markerNodes[i].getAttribute("address");
var distance = parseFloat(markerNodes[i].getAttribute("distance"));
var latlng = new google.maps.LatLng(
parseFloat(markerNodes[i].getAttribute("lat")),
parseFloat(markerNodes[i].getAttribute("lng")));
createOption(name, distance, i);
createMarker(latlng, name, address);
bounds.extend(latlng);
map.fitBounds(bounds);
locationSelect.style.visibility = "visible";
locationSelect.onchange = function()
var markerNum = locationSelect.options[locationSelect.selectedIndex].value;
google.maps.event.trigger(markers[markerNum], 'click');
;
);
function createMarker(latlng, name, address)
var html = "<b>" + name + "</b> <br/>" + address;
var marker = new google.maps.Marker(
map: map,
position: latlng
);
google.maps.event.addListener(marker, 'click', function()
infoWindow.setContent(html);
infoWindow.open(map, marker);
);
markers.push(marker);
function createOption(name, distance, num)
var option = document.createElement("option");
option.value = num;
option.innerHTML = name;
locationSelect.appendChild(option);
function downloadUrl(url, callback)
var request = window.ActiveXObject ?
new ActiveXObject('Microsoft.XMLHTTP') :
new XMLHttpRequest;
request.onreadystatechange = function()
if (request.readyState == 4)
request.onreadystatechange = doNothing;
callback(request.responseText, request.status);
;
request.open('GET', url, true);
request.send(null);
function parseXml(str)
if (window.ActiveXObject)
var doc = new ActiveXObject('Microsoft.XMLDOM');
doc.loadXML(str);
return doc;
else if (window.DOMParser)
return (new DOMParser).parseFromString(str, 'text/xml');
function doNothing()
</script>
<script async defer
src="https://maps.googleapis.com/maps/api/js?key=AIzaSyAVD0ngfhOFs5rnww7UFyz9rN6UznOIZ1U&callback=initMap">
</script>
</body>
</html>
使用上面的方法我可以指向单点，但我想要的是得到半径以上提供的每个纬度周围的位置是5 km
【问题讨论】：
请提供足够的示例并分享一些您遇到问题的代码。 【参考方案1】：如果您已经在使用 Google 地图，那么我认为您可以尝试使用 computeDistanceBetween。
这是一个如何使用它的简短示例。您只需要消除那些大于您设置的半径的距离即可。
var home = ['Store', new google.maps.LatLng(29.520130, -98.415542)];
var pts = [
['Client A', new google.maps.LatLng(29.5197902, -98.3867079)],
['Client B', new google.maps.LatLng(29.5165967, -98.4235714)],
['Client C', new google.maps.LatLng(29.5198805, -98.3676648)]
];
var dist = google.maps.geometry.spherical.computeDistanceBetween;
pts.forEach(function(pt)
console.log(home[0] + ' to ' + pt[0] + ': ' + (dist(home[1], pt[1])).toFixed(10));
);
【讨论】：
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