“超级”对象的描述符“__init__”需要参数
Posted
技术标签:
【中文标题】“超级”对象的描述符“__init__”需要参数【英文标题】:descriptor '__init__' of 'super' object needs argument 【发布时间】:2014-07-15 19:22:38 【问题描述】:我正在尝试用 Python 制作一个面向对象的基于文本的游戏,并尝试实现我的第一个属性和装饰器。使用'Python 3 Object Oriented Programming' 中的第 5 章,我尝试使用讨论的示例和概念来获取以下代码,以便在实例化时设置游戏对象的 'current_room' 属性:
class Room(object):
''' An area of the game's map.'''
def __init__(self):
print("Accessing the Room __init__ method.")
class FirstRoom(Room):
''' Just some room.'''
def __init__(self):
print("Accessing the FirstRoom __init__ method.")
super.__init__()
class SecondRoom(Room):
''' Just some other room.'''
def __init__(self):
print("Accessing the SecondRoom __init__ method.")
super.__init__()
class Game(object):
''' Creates a new game.'''
current_room = None # Class-level definition of this property.
def __init__(self):
print("Created a new Game object.")
self.current_room = FirstRoom()
@property
def current_room(self):
''' Returns the current position of the actor.'''
print("Getting the _current_room attribute for the Game object.")
return self._current_room
@current_room.setter
def set_room(self, new_room):
''' Sets the current_room property of the Game object.'''
print("Setting the _current_room attribute for the Game object.")
self._current_room = new_room
但是,当我运行此代码时,我得到以下输出:
>>> g = Game()
Created a new Game object.
Accessing the FirstRoom __init__ method.
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/home/drew/Desktop/test.py", line 27, in __init__
self.current_room = FirstRoom()
File "/home/drew/Desktop/test.py", line 11, in __init__
super.__init__()
TypeError: descriptor '__init__' of 'super' object needs an argument
我的代码中缺少什么以使此语法正常工作?我需要为我的“current_room”属性显式定义一个描述符吗? [这本书没有提到任何关于描述符的内容,至少不像你在这里看到的那样:Python Descriptors Demystified。]
【问题讨论】:
您实际上需要致电super
。
How to call Base Class's __init__ method from the child class?的可能重复
看起来像语法 super().__init__() 并将 self.current_room = FirstRoom() 更改为 self._current_room = FirstRoom() 修复了下一个错误。谢谢!
@RSahu 我不认为这个问题是重复的(至少是那个问题)。事实上,OP 的问题不是调用super
而您链接的问题确实 调用super
并且产生的错误完全不同。
【参考方案1】:
super 错误实际上是在您调用 super 之前将 print 打印出来,以下代码可以正常工作:
class Room(object):
''' An area of the game's map.'''
def __init__(self):
print("Accessing the Room __init__ method.")
class FirstRoom(Room):
''' Just some room.'''
def __init__(self):
super().__init__()
print("Accessing the FirstRoom __init__ method.")
class SecondRoom(Room):
''' Just some other room.'''
def __init__(self):
super().__init__()
print("Accessing the SecondRoom __init__ method.")
您需要了解@property
等的工作原理。
Property python docs
从文档中,确保为附加函数提供与原始属性相同的名称
class Game(object):
''' Creates a new game.'''
current_room = None # Class-level definition of this property.
def __init__(self):
print("Created a new Game object.")
self._current_room = FirstRoom()
@property
def current_room(self, room):
''' Returns the current position of the actor.'''
print("Getting the _current_room attribute for the Game object.")
return self._current_room
@current_room.setter # same function name as the property.
def current_room(self, new_room):# same name as the property
''' Sets the current_room property of the Game object.'''
print("Setting the _current_room attribute for the Game object.")
self._current_room=new_room
【讨论】:
是的,使用 Python 3.4.0。 不用担心。看看文档,有几个很好的例子来说明 @property 等是如何工作的。【参考方案2】:这里是工作代码:
class Room(object):
''' An area of the game's map.'''
def __init__(self):
print("Accessing the Room __init__ method.")
class FirstRoom(Room):
''' Just some room.'''
def __init__(self):
print("Accessing the FirstRoom __init__ method.")
#super.__init__()
super(FirstRoom, self).__init__()
class SecondRoom(Room):
''' Just some other room.'''
def __init__(self):
print("Accessing the SecondRoom __init__ method.")
super(SecondRoom, self).__init__()
#super.__init__()
class Game(object):
''' Creates a new game.'''
_current_room = None # Class-level definition of this property.
def __init__(self):
print("Created a new Game object.")
self._current_room = FirstRoom()
@property
def current_room(self):
''' Returns the current position of the actor.'''
print("Getting the _current_room attribute for the Game object.")
return self._current_room
@current_room.setter
def set_room(self, new_room):
''' Sets the current_room property of the Game object.'''
print("Setting the _current_room attribute for the Game object.")
self._current_room = new_room
当运行时:
>>> g = Game()
Created a new Game object.
Accessing the FirstRoom __init__ method.
Accessing the Room __init__ method.
>>>
希望对您有所帮助。
【讨论】:
【参考方案3】:使用super().__init__()
代替super.__init__()
【讨论】:
谢谢你,亲爱的以上是关于“超级”对象的描述符“__init__”需要参数的主要内容,如果未能解决你的问题,请参考以下文章
当父级不从对象继承时,Python 2.x 超级 __init__ 继承不起作用