自定义类的字典数组
Posted
技术标签:
【中文标题】自定义类的字典数组【英文标题】:Array of Dictionaries to Custom Class 【发布时间】:2017-09-29 05:31:39 【问题描述】:我已成功将我的 Firebase 数据提取到字典中,但我很难将这些值放入我的自定义类中。
要从 Firebase 获取我的数据,我使用以下代码:
func testing(completion: @escaping ([String : Any]) -> ())
ref.child("dailyJobs").observe(.childAdded, with: (snapshot) in
if let value = snapshot.value as? [String : Any]
completion(value as [String : Any])
return
completion([:])
)
当我调用函数时
testing (dictionary) in
print(dictionary)
我从 Firebase 得到的字典是这样的(它是一个字典数组):
["name": custom chore list, "multiplier": 1, "assigned": none, "order": 0]
["name": bathrooms, "multiplier": 1, "assigned": none, "order": 1]
["name": laundry, "multiplier": 1, "assigned": none, "order": 2]
["name": living room, "multiplier": 1, "assigned": none, "order": 3]
["name": sweep & vacuum, "multiplier": 1, "assigned": sweep & vacuum, "order": 4]
["name": wipe table, "multiplier": 1, "assigned": none, "order": 5]
["name": counters, "multiplier": 1, "assigned": none, "order": 6]
["name": dishes, "multiplier": 1, "assigned": none, "order": 7]
["name": meal prep, "multiplier": 1, "assigned": none, "order": 8]
["name": feed pet / garbage, "multiplier": 1, "assigned": none, "order": 9]
我的自定义类是这样的:
class JobsAndHabits
var name: String
var multiplier: Double
var assigned: String
var order: Int
init(jobName: String, jobMultiplier: Double, jobAssign: String, jobOrder: Int)
self.name = jobName
self.multiplier = jobMultiplier
self.assigned = jobAssign
self.order = jobOrder
我解析dictionary
的代码是这样的:
testing (dictionary) in
for item in dictionary
print(item)
let multiplier = dictionary["multiplier"] as! Double
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
print(self.dailyJobs)
我得到了这个:
[ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits, ToDo_App.JobsAndHabits]
每个字典都有 4 个。不知何故,我的代码将数组复制了 4 倍,现在我的头疼了。我确信有一个简单的解决方案。
我也试过了:
将所有代码放入原始闭包中,如下所示:
func loadExistingJobs(_ completion: @escaping () -> ())
ref.child("dailyJobs").observe(.childAdded, with: (snapshot) in
if let dictionary = snapshot.value as? [String : Any]
let multiplier = dictionary["multiplier"] as! Double
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(by: $0.order < $1.order)
self.jobsTableView.reloadData()
completion()
)
但是@escaping
闭包没有正常运行,我的后续代码也没有被执行。
TL;DR - 我想从 Firebase 中提取数据并将其附加到我的数组中。
【问题讨论】:
【参考方案1】:请检查:
您的dictionary
是["name": custom chore list, "multiplier": 1, "assigned": none, "order": 0]
,您正在为此编写循环。它有 4 个键,所以它会循环 4 次。
如果你的字典像 [String: Any],那么你必须像下面这样调用:
testing (dictionary) in
let multiplier = Double(dictionary["multiplier"] as! Int)
let name = dictionary["name"] as! String
let assigned = dictionary["assigned"] as! String
let order = dictionary["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
print(self.dailyJobs)
)
如果你的字典像 [[String: Any]],那么你必须像下面这样调用:
func testing(completion: @escaping ([[String : Any]]) -> ())
let dictionary = [[String: Any]]
ref.child("dailyJobs").observe(.childAdded, with: (snapshot) in
for child in (snapshot?.children)!
let snap = child as! FDataSnapshot //each child is a snapshot
if let value = snap.value as? [String : Any]
dictionary.append(value)
completion(dictionary)
)
testing (dictionary) in
for item in dictionary
print(item)
let multiplier = Double(item["multiplier"] as! Int)
let name = item["name"] as! String
let assigned = item["assigned"] as! String
let order = item["order"] as! Int
let dailyJob = JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order)
self.dailyJobs.append(dailyJob)
//
print(self.dailyJobs)
)
【讨论】:
是的,那我该如何避免呢?我难住了。如何将这 四个 键放入我的 one 类对象中? 请检查我的代码。删除了 for 循环。现在你会得到正确的结果。 崩溃了。Unexpectedly found nil while unwrapping an Optional Value
第 1 行:let multiplier = dictionary...
没有。您正在尝试将 Any 转换为 Double。所以它失败了。你的 multiplier
是 Double 并且它在字典中的值是 Int。
好的。搞定了但是现在即使在我调用代码之后数据仍在填充。当我打印到控制台dailyJobs.count
时,我得到1, 2, 3, 4, 5, 6, 7, 8, 9, 10
。这意味着代码仍在运行。它应该只是10
。我的完成处理程序错了吗?【参考方案2】:
你可以试试这段代码,根据你的需要修改
class JobsAndHabits
var name: String
var multiplier: Double
var assigned: String
var order: Int
init(jobName: String, jobMultiplier: Double, jobAssign: String, jobOrder: Int)
self.name = jobName
self.multiplier = jobMultiplier
self.assigned = jobAssign
self.order = jobOrder
class func getAllJobsAndHabbits(forUserID userID: String, completion: @escaping (JobsAndHabits) -> Swift.Void, failure: @escaping () -> ())
if Auth.auth().currentUser != nil
Database.database().reference().child("jobsAndHabits").child(userID).observe(.childAdded, with: (snapshot) in
if snapshot.exists()
let receivedMessage = snapshot.value as! [String: Any]
let name = receivedMessage["content"] as? String ?? ""
let multiplier = receivedMessage["multiplier"] as? Double ?? 0.0
let assigned = receivedMessage["assigned"] as? String ?? ""
let order = receivedMessage["order"] as? Int ?? 0
completion(JobsAndHabits(jobName: name, jobMultiplier: multiplier, jobAssign: assigned, jobOrder: order))
else
failure()
)
else
failure()
调用方式和处理方式
class Test
let dailyJobs:[JobsAndHabits] = []
JobsAndHabits.getAllJobsAndHabbits(forUserID: "12346", completion:
self.dailyJobs.append(dailyJob)
self.dailyJobs.sort(by: $0.order < $1.order)
)
//handle error
【讨论】:
嗯..dailyJobs
仍在异步加载。我想在来自数据库的最终调用中运行代码,而不是增量。你看,我想附加另一个基于 dailyJobs
列表的数组。以上是关于自定义类的字典数组的主要内容,如果未能解决你的问题,请参考以下文章