在一个查询中按计数和运算符获取结果

Posted 2023-02-22

【中文标题】在一个查询中按计数和运算符获取结果

【英文标题】：Get results by count and operators in one query

【发布时间】：2017-02-21 06:26:15

【问题描述】：

我认为问题是错误的，但我不知道如何正确提问。

此查询选择所有工作人员的所有企业，其job_types 包含C 字母。

$connect = DB::table('relationship')
->join('workers', 'workers.id', '=', 'relationship.w_id')
->join('business', 'business.id', '=', 'relationship.b_id')
->whereRaw('job_types LIKE "%C%"')
->groupBy('relationship.w_id')
->get();

我正在使用 foreach 来显示结果

foreach ($connect as $item) 
 echo $item->name;
 // etc

我想选择所有大于 3 或小于 3 或等于 3 的企业（取决于我需要什么）job_types LIKE "%C%" 并存储这样的信息：

1. APPLE | Tom | C
2. APPLE | Tim | C
3. APPLE | Jeff | C
4. IBM | Jenny | C
5. IBM | Sean | C
6. IBM | Ian | C
// etc``

@KikiTheOne 的回答有点用，但它没有根据需要显示结果。

【问题讨论】：

那么哪一列包含工人数？然后只需在 whereRaw 中执行 worker_count > 5 大于 5 等。

数据库中没有存储计数的列

@MattCowley 我猜有一个 Worker 表和一个 Businesstable 和一个 Real 表。像workerA 一样的不动产ia |商务 B。你必须在你的第一次加入时按 b_id 和 Count(workers) 分组。

为什么不只是->where('job_types', 'like', '%C%') 而不是->whereRaw()？

@Neat 因为真正的查询比这里更复杂。在这里我只发布了小而易读的查询。

【参考方案1】：

*****解决方案*****

SELECT 
 * 
FROM 
    people_details as t1 
inner join 
    people_branches as t2 
on t1.id = t2.id 
    inner join 
    ( 
        SELECT 
            count(t1.id) as worker_counter,t1.branch_id
        FROM 
            people_branches as t1 
                inner join people_details as t2 
                    on t1.id = t2.id 
        WHERE 
            t2.job_types LIKE '%C%' 
            group by branch_id 
    ) as t3 
    on t2.branch_id = t3.branch_id 
inner join people_frontpage as t4 
    on t4.id = t1.id 
inner join business as t5 
    on t5.id = t2.branch_id 
WHERE 
    t1.job_types LIKE '%C%' 
    AND t3.worker_counter > 200

---------

---

旧 - 更新

---

SELECT 
    t3.bus_name, t1.name, t1.job_types 
FROM 
    SO_WORKER as t1 
    inner join 
        SO_RELATIONSHIP as t2 
            on t1.id = t2.w_id 
    inner join 
    (
        SELECT 
            count(t1.w_id) as worker_counter,t1.b_id,t3.bus_name 
        FROM 
            SO_RELATIONSHIP as t1 
            inner join SO_WORKER as t2 
                on t1.w_id = t2.id 
            inner join SO_BUSINESS as t3 
                on t3.id = t1.b_id 
        WHERE 
            t2.job_types LIKE '%C%' 
            group by b_id
    ) as t3 
    on t2.b_id = t3.b_id 
WHERE t1.job_types LIKE '%C%'
AND t3.worker_counter <= 3

未格式化

SELECT t3.bus_name, t1.name, t1.job_types FROM SO_WORKER as t1 inner join SO_RELATIONSHIP as t2 on t1.id = t2.w_id inner join (SELECT count(t1.w_id) as worker_counter,t1.b_id,t3.bus_name FROM SO_RELATIONSHIP as t1 inner join SO_WORKER as t2 on t1.w_id = t2.id inner join SO_BUSINESS as t3 on t3.id = t1.b_id WHERE t2.job_types LIKE '%C%' group by b_id) as t3 on t2.b_id = t3.b_id WHERE t1.job_types LIKE '%C%' AND t3.worker_counter <= 3

----------------------------------------------- ---

旧代码

关于帖子 1 中的 cmets。

Table: SO_BUSINESS
    id      |       bus_name
    --------------------
    1       |       BUSI A
    2       |       BUSI B

Table: SO_WORKER
    id      |       job_types
    ---------------------
    1       |       CEO
    2       |       GFO
    3       |       CTO
    4       |       Manager
    5       |       Worker

Table: SO_RELATIONSHIP
    w_id    |       b_id
    ----------------
    1       |       1
    2       |       2
    3       |       1
    4       |       1
    5       |       2

Query: Output
    workers_count   |       b_id        |       bus_name
    --------------------------------------------
    2               |       1           |       BUSI A

.

SELECT * 
FROM 
    (
        SELECT 
            count(t1.w_id) as workers_count,
            t1.b_id,
            t3.bus_name
        FROM 
            SO_RELATIONSHIP as t1 
            inner join 
                SO_WORKER as t2 on t1.w_id = t2.id 
            inner join 
                SO_BUSINESS as t3 on t1.b_id = t3.id 
        WHERE 
            t2.job_types LIKE '%C%' 
        GROUP BY t1.b_id
    ) as t4 
WHERE 
    t4.workers_count < 3  

未格式化的代码：

SELECT * FROM (SELECT count(t1.w_id) as workers_count,t1.b_id,t3.bus_name FROM SO_RELATIONSHIP as t1 inner join SO_WORKER as t2 on t1.w_id = t2.id inner join SO_BUSINESS as t3 on t1.b_id = t3.id WHERE t2.job_types LIKE '%C%' GROUP BY t1.b_id) as t4 WHERE t4.workers_count < 3  

如果这对你有帮助，请告诉我

【讨论】：

早上好。因此，关系表具有以下字段：1. r_id (for auto increment) 2. b_id 3. w_id。我现在就试试你的代码

看起来，您的代码运行良好，但我有一个，最后一个问题。例如：t4.workers_count = 3 仅显示一行，如果该企业有 3 名员工，"%C%"。如何将该公司名称复制 3 次并存储这 3 个工人信息？您的查询运行良好，但这个小改动将使这个查询成为传奇。

看起来我是通过更改 group by 自己制作的，为了验证我添加了 order by name。谢谢，如果可能的话，让我们继续保持联系。

好的，所以问题还是存在，想不通，如何显示正确的结果。如果t4.wokers_count = 3 它显示所有拥有 3 名工人的企业"%C%"。如何将已创建的业务复制 3 次，并在每个复制行中显示一名工人的信息。查看更新的问题。

【参考方案2】：

$connect = DB::table('relationship')
->join('workers', 'workers.id', '=', 'relationship.w_id')
->join('business', 'business.id', '=', 'relationship.b_id')
->selectRaw('workers.*,business.*,(select count(*) from workers where job_types like "%c%") as workers_count')
->where('job_types', 'like', '%C%')
->having('workers_count','>=',5)
->groupBy('relationship.w_id')
->get();

【讨论】：

我认为您在 selectRaw 行中犯了一个错误。没有引号

对不起，它给了我一个错误的 SQL 语法错误。 You have an error in your SQL syntax; check the manual that corresponds to your mysql server version for the right syntax to use near '*).

它正在工作，但看起来运算符不起作用，因为它给我的结果不正确。例如，如果我设置 workers_count < 3 它仍然返回具有例如 6 个工人的企业。