如何根据python中的排序功能对业务ID进行排序

Posted 2023-02-19

【中文标题】如何根据python中的排序功能对业务ID进行排序

【英文标题】：how to sort the business id based on sort function in python

【发布时间】：2021-06-07 11:53:32

【问题描述】：

例子：

enter code here
businesses: [
    Business(id=1, rating=4.0, vegan_friendly=True, price=4, distance=10.0),
    Business(id=2, rating=2.5, vegan_friendly=False, price=2, distance=5.0),
    Business(id=3, rating=4.5, vegan_friendly=False, price=1, distance=1.0),
    Business(id=4, rating=3.0, vegan_friendly=True, price=2, distance=3.4),
    Business(id=5, rating=4.5, vegan_friendly=true, price=1, distance=6.3),
    Business(id=6, rating=3.5, vegan_friendly=True, price=2, distance=1.2),
]

根据id从高到低排序

【问题讨论】：

你已经尝试了什么？

它已经按 id 排序，如果您想按评级排序，请澄清/确认？并显示和编辑问题以显示您尝试过的代码。

【参考方案1】：

# To sort the list in place...
businesses.sort(key=lambda x: x.id, reverse=True)

# To return a new list, use the sorted() built-in function...
newlist = sorted(businesses, key=lambda x: x.id, reverse=True)

【讨论】：

当我想使用带有少量过滤器的代码时，它将如何工作 def filter_and_sort_businesses(businesss: List[Business], only_vegan_friendly: bool = False, max_price: Optional[int] = None, max_distance: Optional [float] = None, ) -> List[int]:

@komal vyas 请问你是怎么解决这个问题的

【参考方案2】：

您可以使用python内置方法sorted并提供排序key：

businesses = [
    Business(id=1, rating=4.0, vegan_friendly=True, price=4, distance=10.0),
    Business(id=2, rating=2.5, vegan_friendly=False, price=2, distance=5.0),
    Business(id=3, rating=4.5, vegan_friendly=False, price=1, distance=1.0),
    Business(id=4, rating=3.0, vegan_friendly=True, price=2, distance=3.4),
    Business(id=5, rating=4.5, vegan_friendly=true, price=1, distance=6.3),
    Business(id=6, rating=3.5, vegan_friendly=True, price=2, distance=1.2),
]
businesses_sorted = sorted(businesses, key=lambda business: business.id)

反向列表使用reverse标志：

businesses_sorted_reversed = sorted(businesses, key=lambda business: business.id, reverse=True)