从 Service 向 Activity 发送简单消息
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【中文标题】从 Service 向 Activity 发送简单消息【英文标题】:Sending a simple message from Service to Activity 【发布时间】:2015-08-18 04:37:50 【问题描述】:我正在尝试找到一种将整数值从我的服务发送到我的 MainActivity 的方法,但我无法通过互联网上的教程找到它。我正在使用处理程序来接收我从服务中的线程发送的消息。
我在服务中的线程代码:
private class ServiceThread extends Thread
@Override
public void run()
super.run();
try
Log.i("Service", "TASK PERFORMED");
int x = 0;
for (int i = 0; i < 20; i++)
x += (random.nextInt(20) + 20);
theInteger = x/20;
Message msg = Message.obtain();
msg.what = MY_RND_INT;
msg.arg1 = theInteger;
handler.sendMessage(msg);
catch(Exception e)
e.getMessage();
我尝试接收消息的代码:
public Messenger mMessenger = new Messenger(new IncomingHandler());
class IncomingHandler extends Handler
@Override
public void handleMessage(Message msg)
switch (msg.what)
case SimpleService.MY_RND_INT:
rndInt.setText(msg.arg1);
break;
default:
super.handleMessage(msg);
【问题讨论】:
@AnixPasBesoin 抱歉,回来晚了!感谢您的回复 【参考方案1】:你是这样做的:
服务端
// Supposing that your value is an integer declared somewhere as: int myInteger;
private void sendMessage()
// The string "my-message" will be used to filer the intent
Intent intent = new Intent("my-message");
// Adding some data
intent.putExtra("my-integer", myInteger);
LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
活动端
@Override
public void onResume()
super.onResume();
// This registers messageReceiver to receive messages.
LocalBroadcastManager.getInstance(this)
.registerReceiver(messageReceiver, new IntentFilter("my-message"));
// Handling the received Intents for the "my-integer" event
private BroadcastReceiver messageReceiver = new BroadcastReceiver()
@Override
public void onReceive(Context context, Intent intent)
// Extract data included in the Intent
int yourInteger = intent.getIntExtra("my-integer", -1); // -1 is going to be used as the default value
;
@Override
protected void onPause()
// Unregister since the activity is not visible
LocalBroadcastManager.getInstance(this).unregisterReceiver(messageReceiver);
super.onPause();
【讨论】:
嗨,我尝试使用此代码,但是当我使用 sendMessage() 时,应用程序崩溃了。接收方需要注册吗? @user1527152 是的。检查我提供的示例代码和答案。 如果不在同一个包里怎么办?以上是关于从 Service 向 Activity 发送简单消息的主要内容,如果未能解决你的问题,请参考以下文章
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