将 SQL Server 图形数据库中的 MATCH 子句和 INNER JOIN 与混合模型相结合

Posted 2023-02-18

【中文标题】将 SQL Server 图形数据库中的 MATCH 子句和 INNER JOIN 与混合模型相结合

【英文标题】：Combine MATCH clause and INNER JOIN in SQL Server graph database with mixed model

【发布时间】：2020-09-30 05:25:06

【问题描述】：

我在 SQL Server 中有一些节点和边缘表，它们与存储用户的标准表具有一对多的关系。每条边和节点表都有这种1N的关系。

我想知道如何使用匹配子句和左连接执行查询：

SELECT * FROM Node1Table n1, EdgeTable e, Node2Table n2
LEFT JOIN UserTable usr ON e.usr = usr.ID
MATCH (n1-(e)->n2)

我可以这样写查询：

SELECT * FROM EdgeTable e
INNER JOIN Node1Table n1 ON e.$from_ID = n1.$node_ID
INNER JOIN Node2Table n2 ON e.$to_ID = n2.$node_ID
LEFT JOIN UserTable usr ON e.usr = usr.ID

但我不知道 n1 是来自还是来自对象。

我无法进行内部连接，因为 e.usr 可能为空

感谢您的帮助

编辑：

测试 1：

SELECT * FROM
OBJ_APPLICATION n1, REL_APPLICATION_RESPONSABLE r INNER JOIN    
Management_User u on u.[UserID] = r.[CPQ], OBJ_RESPONSABLE n2
WHERE MATCH(n1-(r)->n2)

error : The identifier "r" in a MATCH clause is used with a JOIN clause or an APPLY operator. JOIN and APPLY are not supported with MATCH clauses.

测试 2：

SELECT * FROM
OBJ_APPLICATION n1, REL_APPLICATION_RESPONSABLE r, OBJ_RESPONSABLE n2
INNER JOIN Management_User u on u.[UserID] = r.[CPQ]
WHERE MATCH(n1-(r)->n2)

error : The multi-part identifier r.CPQ could not be bound

测试 3：

SELECT * FROM
OBJ_APPLICATION n1, REL_APPLICATION_RESPONSABLE r, OBJ_RESPONSABLE n2, Management_User u
WHERE MATCH(n1-(r)->n2)
AND u.[UserID] = r.[CPQ]

Works with an INNER JOIN but in some cases I have to make a LEFT JOIN

【问题讨论】：

我自己从未使用过图形函数，但我建议您先计算图形结果，然后加入用户，例如SELECT * FROM (SELECT * FROM .... MATCH (n1-(e)->n2)) AS g LEFT JOIN UserTable usr ON g.usr = usr.ID.

谢谢你，但它不起作用

你能说得更具体点吗？你有错误吗？

我的建议返回什么错误？

【参考方案1】：

就像 Alex 建议的那样，您可以进行子查询。以下是我正在积极处理的功能齐全的查询。

SELECT
TokensConnectors.*
FROM
(
    SELECT      
        leftWord.word As LeftSide, 
        MiddleWord.word AS MiddleWord,
        DependsOn1.[DependencyType] As [DependencyType1],
        DependsOn1.SentenceId
    FROM 
        Pipeline.Words MiddleWord,
        Pipeline.Words leftWord, 
        Pipeline.DependsOn DependsOn1
    WHERE 
        MATCH(leftWord<-(DependsOn1)-MiddleWord)
        AND leftWord.Word = 'differential'
        and middleWord.word = 'diagnosis'
) AS DifferentialDiagnosis 
INNER JOIN [Pipeline].[DependsOn] AS TokensConnectors ON TokensConnectors.[SentenceId] = DifferentialDiagnosis.SentenceId

这是一个示例，我将 Sentences、ClinicalNotes 和 DependsOn1 进行内部连接。认为链接是在 Where 语句中完成的。

SELECT
    DependsOn1.SentenceId
FROM 
    Pipeline.Words RightWord,
    Pipeline.Words LeftWord, 
    Pipeline.DependsOn DependsOn1,
    Pipeline.Sentences,
    Pipeline.ClinicalNotes
WHERE 
    MATCH(LeftWord<-(DependsOn1)-RightWord)
    AND LeftWord.Word = 'differential'
    and RightWord.word = 'diagnosis'
    AND DependsOn1.SentenceId = Sentences.Id
    AND ClinicalNotes.Id = Sentences.ClinicalNoteId
    AND ClinicalNotes.ProcessingLogId = @processingLogIdessingLogId