informatica 聚合器路由器和表达式
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【中文标题】informatica 聚合器路由器和表达式【英文标题】：informatica aggregator router and expression 【发布时间】：2018-02-19 08:38:21 【问题描述】：想问我有一个方案可以将此 sql 查询转换为 informatica 映射：
select v.id,
case when v.type = 21 then nvl(
(SELECT nvl(SUM(nvl(amount,0)),0)
FROM view1
WHERE ctype IN (252,82) AND id = v.id AND id2 = v.id2
GROUP BY id, id2) ,0)
else -1*nvl(
(SELECT nvl(SUM(nvl(amt,0)),0)
FROM view2
WHERE vtype IN (252,82) AND txn_id = v.txn_id AND txn_id2 = 1
GROUP BY txn_id, txn_id2),0) end AS amt1,
case when v.type = 21 then nvl(
(SELECT nvl(SUM(nvl(amount,0)),0)
FROM view1
WHERE ctype IN (253,105) AND id = v.id AND id2 = v.id2
GROUP BY id, id2),0)
else -1*nvl(
(SELECT nvl(SUM(nvl(amt,0)),0)
FROM view2
WHERE vtype IN (253,105) AND txn_id = v.txn_id AND txn_id2 = 1
GROUP BY txn_id, txn_id2),0)
end AS amt2,
case when v.type = 21 then nvl(
(SELECT nvl(SUM(nvl(amount,0)),0)
FROM view1
WHERE ctype IN (251,75,136,135,149,164) AND id = v.id AND id2 = v.id2
GROUP BY id, id2) ,0)
else -1*nvl(
(SELECT nvl(SUM(nvl(amt,0)),0)
FROM view2
WHERE vtype IN (251,75,136,135,149,164) AND txn_id = v.txn_id AND txn_id2 = 1
GROUP BY txn_id, txn_id2),0)
end AS amt3,
case when v.type = 21 then nvl(
(SELECT nvl(SUM(nvl(amount,0)),0)
FROM view1
WHERE ctype IN (6,101,148) AND id = v.id AND id2 = v.id2
GROUP BY id, id2) ,0)
else -1*nvl(
(SELECT nvl(SUM(nvl(amt,0)),0)
FROM view2
WHERE vtype IN (6,101,148) AND txn_id = v.txn_id AND txn_id2 = 1
GROUP BY txn_id, txn_id2),0) end AS amt4
from tblabc v, tblabc2 x
where v.status=2 and v.last_updated_datetime>sysdate
v.sid=x.sid (+)
如何在 informatica 中编码？
首先我使用 tblabc 中的连接器根据 id 和 id2 来查看 1，然后
tblabc2 -> \
joiner 1 ----------------------------------------------------?
tblabc -> / |
| / -> aggregator for amt1
joiner2 --> router < -> aggregator for amt2
view1 -> / \ -> aggregator for amt3
\-> aggregator for amt4
view2???
但是如何从 amt1,2,3,4 的聚合器加入回连接器 1？
我无法将它链接回来，当我拖动箭头时，它没有显示链接，知道吗？
【问题讨论】：
【参考方案1】：在这种情况下，您正在执行自联接（因为两个管道都源自同一来源）。在将端口拖到连接器转换之前，请检查 Sorted input 属性。并确保两个管道确实按键排序 - 否则会出现执行错误。
【讨论】：
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