Python 2 - TypeError: int() 参数必须是字符串、类似字节的对象或数字，而不是“列表”

Posted 2023-05-07

【中文标题】Python 2 - TypeError: int() 参数必须是字符串、类似字节的对象或数字，而不是“列表”

【英文标题】：Python 2 - TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'

【发布时间】：2017-02-02 02:23:36

【问题描述】：

如何解决此错误？当我尝试用泡菜加载我的保存时，它给了我这个

Traceback (most recent call last):
  File "C:\Users\user\Downloads\game.py", line 315, in <module>
    menu()
  File "C:\Users\user\Downloads\game.py", line 261, in menu
    if (0) > int(hunger) or (0) > int(thirst):
TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'

这就是我加载/保存的方式

with open('objs.pickle', "rb") as f:  
    money = pickle.load(f)
    hunger = pickle.load(f)
    thirst = pickle.load(f)
    energy = pickle.load(f)
    wanted = pickle.load(f)
    gun = pickle.load(f)


with open('objs.pickle', 'ab') as f:  
    pickle.dump([money, hunger, thirst, energy, gun, wanted], f)

【问题讨论】：

总是将 FULL 错误信息放在 QUESTION 中。还有其他有用的信息。

我在那里编辑过

使用print(hunger, thirst) 看看你在这个变量中有什么。

[1000.0] [1000.0, 10, 10, 10, 0, 0]

data = pickle.load(f), hunger = data[1], thirst = data[2]

【参考方案1】：

首先使用'wb' 而不是'ab' 只有最后一个值

以后你可以使用

with open('objs.pickle', "rb") as f:  
    money = pickle.load(f)
    hunger = pickle.load(f)
    thirst = pickle.load(f)
    energy = pickle.load(f)
    gun = pickle.load(f)
    wanted = pickle.load(f)


with open('objs.pickle', 'wb') as f:  
    pickle.dump(money, f)
    pickle.dump(hunger, f)
    pickle.dump(thirst, f)
    pickle.dump(energy, f)
    pickle.dump(gun, f)
    pickle.dump(wanted, f)

或

with open('objs.pickle', "rb") as f:  
    money, hunger, thirst, energy, gun, wanted = pickle.load(f)

with open('objs.pickle', 'wb') as f:  
    pickle.dump([money, hunger, thirst, energy, gun, wanted], f)