LINQ查询中的C#多个OR条件[重复]

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【中文标题】LINQ查询中的C#多个OR条件[重复]【英文标题】:C# multiple OR conditions in LINQ query [duplicate] 【发布时间】:2021-08-07 09:47:25 【问题描述】:

我正在尝试使用 LINQ 链接多个值或循环。

情况

平台:.net 5C# 9

我们正在为列表构建过滤逻辑。在当前情况下,它涉及要过滤的字符串值。 用户可以搜索一个或多个值。他可以决定单个搜索词是否为 AND/OR 链接,以及某个值是否为否定。

我看到了这个条目。但由于我的值在循环中,我不能使用||。https://***.com/a/37195788/1847143

例子:

名称中带有“A”的所有动物SELECT * FROM "Animal" WHERE "Name" = 'A'; 名称中带有“A”或“B”的所有动物SELECT * FROM "Animal" WHERE "Name" = 'A' OR "Name" = 'B'; 名称中包含“A”或“B”或非“C”的所有动物(这将是毫无意义的搜索)SELECT * FROM "Animal" WHERE "Name" = 'A' OR "Name" = 'B' OR "Name" != 'C' ; 名称中带有“A”和“B”的所有动物SELECT * FROM "Animal" WHERE "Name" = 'A' AND "Name" = 'B'; 名称中包含“A”和“B”而不是“C”的所有动物SELECT * FROM "Animal" WHERE "Name" = 'A' AND "Name" = 'B' AND "Name" != 'C';

问题

与 LINQ 的 AND 链接没有问题。但是这些值如何与 OR 联系起来呢?

代码示例

using System.Collections.Generic;
using System.Linq;

namespace SampleProject

    public class Program
    
        public static void Main(string[] args)
        
            // Or Condtion
            Condition condition = Condition.Or;

            var animalsQuery = Animals.AsQueryable();

            // Loop over all search values to extend the query
            foreach (FilterValue filterValue in FilterValues)
            
                switch (filterValue.LikeType)
                
                    case LikeType.Left: // LIKE '%value'
                        animalsQuery = filterValue.IsNegated
                            ? animalsQuery.Where(animal => !animal.Name.EndsWith(filterValue.Value))
                            : animalsQuery.Where(animal => animal.Name.EndsWith(filterValue.Value));

                        break;

                    case LikeType.Right: // LIKE 'value%'
                        animalsQuery = filterValue.IsNegated
                            ? animalsQuery.Where(animal => !animal.Name.StartsWith(filterValue.Value))
                            : animalsQuery.Where(animal => animal.Name.StartsWith(filterValue.Value));

                        break;

                    case LikeType.LeftAndRight: // LIKE '%value%'
                        animalsQuery = filterValue.IsNegated
                            ? animalsQuery.Where(animal => !animal.Name.Contains(filterValue.Value))
                            : animalsQuery.Where(animal => animal.Name.Contains(filterValue.Value));

                        break;

                    case LikeType.Equals: // Like 'value'
                        animalsQuery = filterValue.IsNegated
                            ? animalsQuery.Where(animal => animal.Name != filterValue.Value)
                            : animalsQuery.Where(animal => animal.Name == filterValue.Value);
                        break;
                
            

            var result = animalsQuery.ToList();
        

        /// Values to filter
        public static List<Animal> Animals = new()
        
            new() Name = "Lenny",
            new() Name = "Gideon",
            new() Name = "Shania",
            new() Name = "Jada",
            new() Name = "Kamil",
            new() Name = "Fariha",
        ;

        /// Search Values
        public static List<FilterValue> FilterValues = new()
        
            new() Value = "a", LikeType = LikeType.Left,
            new() Value = "n", LikeType = LikeType.Right,
            new() Value = "f", LikeType = LikeType.LeftAndRight,
            new() Value = "k", LikeType = LikeType.Equals,
        ;
    

    public class Animal
    
        public string Name  get; set; 
    

    public class FilterValue
    
        public string   Value      get; set; 
        public bool     IsNegated  get; set; 
        public LikeType LikeType   get; set; 
    

    public enum LikeType
    
        Left         = 1,
        Right        = 2,
        LeftAndRight = 3,
        Equals       = 4,
    

    public enum Condition
    
        And = 1,
        Or  = 2,
    

【问题讨论】:

如果OR 都等于而不是不等于,那么问题很简单——使用Contains(即有一个List&lt;string&gt; 的值)。 != 唉,这不会那么好。 与其链接多个 Where 调用,不如为每个条件创建一个 lambda,将这些 lambda 与 &amp;&amp; 和/或 || 运算符组合,然后使用组合结果进行一个 Where 调用. 你可能需要一个 PredicateBuilder;即可以创建和组合 linq 查询谓词的类。它通常包括 OR、AND、NOT、XOR、TRUE 和 FALSE 的方法。它的输入是针对项目类的属性名称或 lambda getter 表达式(在您的示例中为“Animal”)。 @mjwills 但是这样我不能将StartsWithEndsWith 结合起来。所有“以 A 开头”和“以 E 结尾”的动物。 SELECT * FROM "Animal" WHERE "Name" LIKE 'A%' AND "Name" LIKE '%E'; @TheBigNeo 没错。 【参考方案1】:

这进入了表达式树重写的领域。好消息是:它不是非常复杂并且你可以同时执行你的否定步骤:

using System;
using System.Collections.Generic;
using System.Diagnostics.CodeAnalysis;
using System.Linq;
using System.Linq.Expressions;

namespace SampleProject

    public class Program
    
        static Expression<Func<T, bool>> Combine<T>(Condition condition, Expression<Func<T, bool>> left, Expression<Func<T, bool>> right, bool negateRight)
        
            if (right is null) return left;
            if (left is null)
            
                return negateRight ?
                    Expression.Lambda<Func<T, bool>>(
                         Expression.Not(right.Body), right.Parameters)
                    : right;
            

            var leftP = left.Parameters.Single();
            var rightP = right.Parameters.Single();

            var rightBody = right.Body;
            if (!ReferenceEquals(leftP, rightP))
            
                // swap all uses of rightP on rightBody to leftP
                // i.e. normalize on the parameter
                rightBody = new SwapVisitor(rightP, leftP).Visit(rightBody);
            
            if (negateRight)
            
                rightBody = Expression.Not(rightBody);
            
            return Expression.Lambda<Func<T, bool>>(condition switch
            
                Condition.And => Expression.AndAlso(left.Body, rightBody),
                Condition.Or => Expression.OrElse(left.Body, rightBody),
                _ => throw new ArgumentOutOfRangeException(nameof(condition)),
            , left.Parameters);
        

        class SwapVisitor : ExpressionVisitor
        
            private readonly Expression _from, _to;
            public SwapVisitor(Expression from, Expression to)
            
                _from = from;
                _to = to;
            
            public override Expression Visit(Expression node)
                => ReferenceEquals(node, _from) ? _to : base.Visit(node);
        
        public static void Main(string[] args)
        
            // Or Condtion
            Condition condition = Condition.Or;

            var animalsQuery = Animals.AsQueryable();
            // Loop over all search values to extend the query
            Expression<Func<Animal, bool>> predicate = null;
            foreach (FilterValue filterValue in FilterValues)
            
                switch (filterValue.LikeType)
                
                    case LikeType.Left: // LIKE '%value'
                        predicate = Combine(condition, predicate, animal => animal.Name.EndsWith(filterValue.Value), filterValue.IsNegated);

                        break;

                    case LikeType.Right: // LIKE 'value%'
                        predicate = Combine(condition, predicate, animal => animal.Name.StartsWith(filterValue.Value), filterValue.IsNegated);

                        break;

                    case LikeType.LeftAndRight: // LIKE '%value%'
                        predicate = Combine(condition, predicate, animal => animal.Name.Contains(filterValue.Value), filterValue.IsNegated);

                        break;

                    case LikeType.Equals: // Like 'value'
                        predicate = Combine(condition, predicate, animal => animal.Name == filterValue.Value, filterValue.IsNegated);
                        break;
                
            

            if (predicate is not null)
            
                animalsQuery = animalsQuery.Where(predicate);
            
            var result = animalsQuery.ToList();
        

        /// Values to filter
        public static List<Animal> Animals = new()
        
            new()  Name = "Lenny" ,
            new()  Name = "Gideon" ,
            new()  Name = "Shania" ,
            new()  Name = "Jada" ,
            new()  Name = "Kamil" ,
            new()  Name = "Fariha" ,
        ;

        /// Search Values
        public static List<FilterValue> FilterValues = new()
        
            new()  Value = "a", LikeType = LikeType.Left ,
            new()  Value = "n", LikeType = LikeType.Right ,
            new()  Value = "f", LikeType = LikeType.LeftAndRight ,
            new()  Value = "k", LikeType = LikeType.Equals ,
        ;
    

    public class Animal
    
        public string Name  get; set; 
    

    public class FilterValue
    
        public string Value  get; set; 
        public bool IsNegated  get; set; 
        public LikeType LikeType  get; set; 
    

    public enum LikeType
    
        Left = 1,
        Right = 2,
        LeftAndRight = 3,
        Equals = 4,
    

    public enum Condition
    
        And = 1,
        Or = 2,
    

【讨论】:

非常感谢。这完美地工作。 Combine开头有个小bug。如果第一个/单个right 值是left == nullright != nullnegateRight == true,那么right 不会被否定。 if (left is null) return negateRight ? Expression.Lambda&lt;Func&lt;T, bool&gt;&gt;(Expression.Not(right.Body), right.Parameters) : right; @TheBigNeo 够公平的!

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