使用 c++ 的代码块我试图从我的类中打印出一个访问器函数。错误表明对成员 get_address 的请求

Posted 2023-02-17

【中文标题】使用 c++ 的代码块我试图从我的类中打印出一个访问器函数。错误表明对成员 get_address 的请求

【英文标题】：using code blocks for c++ I'm trying to print out an accessor function from my class. the error states that request for member get_address

【发布时间】：2015-01-23 00:52:36

【问题描述】：

这是我的代码，它包括主文件、头文件和源文件

请求“ob”中的成员“get_address”，它是非类类型 AddressSpace(std::string, std::string, std::string, int) aka AddressSpace(std::basic_string, std ::basic_string, std::basic_string, int)

main.cpp

#include <iostream>
#include <string>
#include "AddressSpace.h"
#include "AddressSpace.cpp"

using namespace std;


int main()

   string address;
   string town;
   string state;
   int postal;

    cout << "What is the street you live on?: " <<endl;
    cin >> address;
    cout << "What is the city you live in?: " <<endl;
    cin >> town;
    cout <<"What is the state you live in?: " << endl;
    cin >> state;
    cout << "What is the postal code?: " << endl;
    cin >> postal;


    AddressSpace ob(string address,string town,string state,int postal);

    cout << "Address" << ob.get_address() << endl;

    return 0;

地址空间.h

#ifndef ADDRESSSPACE_H_INCLUDED
#define ADDRESSSPACE_H_INCLUDED

#include <iostream>
#include <string>

using namespace std;

class AddressSpace

public:
//Default constructor
    AddressSpace();
//overload constructor
    AddressSpace(string, string, string, int);
//Accessor Functions
    string get_address() const;
    // get_address - returns address
    string get_town() const;
    // get_town -returns town
    string get_state() const;
    // get_state - returns state
    int get_postal() const;
    // get_postal returns zip code
private:
    //member variables
    string street;
    string city;
    string st;
    int zip;

;


#endif // ADDRESSSPACE_H_INCLUDED

地址空间.cpp

#include "AddressSpace.h"

AddressSpace::AddressSpace(string address, string town, string state, int postal)
    string street = address;
    string city = town;
    string st = state;
    int zip = postal;


string AddressSpace::get_address() const 
    return street;


string AddressSpace::get_town() const 
   return city;


string AddressSpace::get_state() const 
  return st;


int AddressSpace::get_postal() const 
 return zip;

【参考方案1】：

main() 中的以下代码行是function declaration 或原型。

AddressSpace ob(string address,string town,string state,int postal);

如果您删除括号内的类型名称，它将按照您的意图使用给定的参数构造一个名为 ob 的对象。

AddressSpace ob(address, town, state, postal);

【讨论】：

感谢它遵守 :)

【参考方案2】：

当声明一个新对象时，你不要在它前面加上类型。您还没有实例化字符串或整数。在 C/C++ 中，未实例化的值是随机的，因此最好给每个变量一个默认值。您还应该包含 AddressSpace.h 和 AddressSpace.cpp 的代码，以便我们更好地了解可能出现的其他问题

另外，请注意 main() 参数的变化。没有必要，但始终包含它被认为是一种很好的形式。如果您的程序是从命令行运行的，这些参数将填充参数的数量和参数本身。

我认为您的代码应该看起来更像这样：

#include <iostream>
#include <string>
#include "AddressSpace.h"
//#include "AddressSpace.cpp"    //This line isn't needed, you should only include the header file

using namespace std;

int main(int argc, char** argv)

    string address = "";
    string town = "";
    string state = "";
    int postal = 0; //Note postal codes for Europe include letters, and you most-likely won't be doing math with a zipcode so it might make more sense to make it a string

    cout << "What is the street you live on?:" << endl;
    cin >> address;
    cout << "What is the city you live in?:" << endl;
    cin >> town;
    cout << "What is the state you live in?:" << endl;
    cin >> state;
    cout << "What is the postal code?:" << endl;
    cin >> postal;

    AddressSpace ob(address, town, state, postal);

    cout << "Address " << ob.get_address(); << endl;

    return 0;

【讨论】：

感谢您的帮助和正确编程的建议。我确实包含了头文件和源文件，我不知道为什么你看不到它们