如何从联系人中获取电子邮件和姓氏？

Posted 2023-04-17

【中文标题】如何从联系人中获取电子邮件和姓氏？

【英文标题】：How to get email and last name from contacts?

【发布时间】：2016-10-25 16:14:42

【问题描述】：

我使用了联系人选择器的意图。我正在通过意图获取联系数据。为此，我正在获取联系人的姓名、电话号码。

当我尝试获取联系人的电子邮件 ID 时，它只显示联系人的号码而不是电子邮件 ID。同样对于联系人的姓氏，尽管最后一个已设置为联系人，但它始终显示为 null。

代码：

    private void contactPicked(Intent data) 
    Cursor cursor = null;
    try 
        String phoneNo = null ;
        String name = null;
        // getData() method will have the Content Uri of the selected contact
        Uri uri = data.getData();
        //Query the content uri
        cursor = getContentResolver().query(uri, null, null, null, null);
        cursor.moveToFirst();
        // column index of the phone number
        int  phoneIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
        // column index of the contact name
        int  nameIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);

        int contactIdIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID);

        int emailIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA);

        int lastNameIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.StructuredName.FAMILY_NAME);


        mOrganizerPhone = cursor.getString(phoneIndex);
        mOraganizerName = cursor.getString(nameIndex);
        mOrganizersId = cursor.getString(contactIdIndex);
        mOrganizersEmail = cursor.getString(emailIndex);
        mOrganizersLastName = cursor.getString(lastNameIndex);


    Toast.makeText(PlanEventActivity.this,name+" "+phoneNo,Toast.LENGTH_SHORT).show();


     catch (Exception e) 
        e.printStackTrace();
    

谢谢你..

【问题讨论】：

我认为这对你有帮助：***.com/questions/12109391/…

您能告诉我要使用的查询吗？因为当我搜索时，我看到了用于获取电子邮件和结构化姓氏的不同查询。 @HuyN

【参考方案1】：

使用“id”，你可以得到这样的电子邮件地址，这是一个例子：

public class CustomerForm extends Activity 
private final static int CONTACT_PICKER = 1;
private EditText txtMailContacto;
private EditText txtNombreContacto;
private EditText txtTelefono;
@Override
protected void onCreate(Bundle savedInstanceState) 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_customer_form);
    txtMailContacto = (EditText) findViewById(R.id.txtMailContacto);
    txtTelefono = (EditText) findViewById(R.id.txtTelefono);
    txtNombreContacto = (EditText) findViewById(R.id.txtNombreContacto);

public void pickContact(View v)

    Intent contactPickerIntent = 
            new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
    startActivityForResult(contactPickerIntent, CONTACT_PICKER);

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) 
        // check whether the result is ok
    if (resultCode == RESULT_OK) 
        // Check for the request code, we might be using multiple startActivityForReslut
        switch (requestCode) 
        case CONTACT_PICKER:
            contactPicked(data);
            break;
        
     else 
        Log.e("MainActivity", "Failed to pick contact");
    

private void contactPicked(Intent data) 
    ContentResolver cr = getContentResolver();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
    cur.moveToFirst();
    try 
        // getData() method will have the Content Uri of the selected contact
        Uri uri = data.getData();
        //Query the content uri
        cur = getContentResolver().query(uri, null, null, null, null);
        cur.moveToFirst();
                                                // column index of the contact ID
        String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                                                // column index of the contact name 
        String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
        txtNombreContacto.setText(name);        //print data            
                                                // column index of the phone number
        Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, 
                    ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?", 
                    new String[]id, null);
                    while (pCur.moveToNext()) 
                        String phone = pCur.getString(
                                pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                        txtTelefono.setText(phone);         //print data
                     
                    pCur.close();
                                                // column index of the email   
        Cursor emailCur = cr.query(        
                ContactsContract.CommonDataKinds.Email.CONTENT_URI, 
                null,
                ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",  
                new String[]id, null); 
            while (emailCur.moveToNext())  
                // This would allow you get several email addresses
                    // if the email addresses were stored in an array  
                String email = emailCur.getString(
                              emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.ADDRESS));                                         
                txtMailContacto.setText(email);         //print data
         
        emailCur.close();
     catch (Exception e) 
        e.printStackTrace();
    

【讨论】：

对于每个 id 我需要为电子邮件创建光标？那么姓氏呢？ @Huy N

没错！关于姓氏，我上面的解决方案使用“ContactsContract.Contacts.DISPLAY_NAME”并获得全名，您可以在 Java 中使用 spit 方法来获得您想要的名称:)

我试过这个解决方案没有收到电子邮件 ID。 @Huy N

它不会进入电子邮件光标的while循环。 @Huy N

是的，我有权限。我可以看到 id 和显示名称，但看不到 emailid。 @Huy N