多个联系人选取器列表

Posted 2023-04-17

【中文标题】多个联系人选取器列表

【英文标题】：Multiple Contact Picker List

【发布时间】：2012-07-02 06:52:26

【问题描述】：

我有一个联系人选择器列表，其中包含具有电话号码的联系人的复选框。 现在，我的问题是似乎无法获取选中的联系人的姓名和电话号码。

这是我的代码：

    import android.app.ListActivity;
    import android.content.ContentResolver;
    import android.content.Intent;
    import android.database.Cursor;
    import android.net.Uri;
    import android.os.Bundle;
    import android.provider.ContactsContract;
    import android.provider.ContactsContract.CommonDataKinds.Phone;
    import android.util.Log;
    import android.util.SparseBooleanArray;
    import android.view.View;
    import android.view.View.OnClickListener;
    import android.widget.Button;
    import android.widget.EditText;
    import android.widget.ListAdapter;
    import android.widget.ListView;
    import android.widget.SimpleCursorAdapter;

    public class Create_Group extends ListActivity implements OnClickListener

        // List variables
        public String[] Contacts = ;
        public int[] to = ;
        public ListView myListView;

        Button save_button;

        @Override
        public void onCreate(Bundle savedInstanceState) 
            super.onCreate(savedInstanceState);
            setContentView(R.layout.create_group);

            // Initializing the buttons according to their ID
            save_button = (Button)findViewById(R.id.save_group_button);

            // Defines listeners for the buttons
            save_button.setOnClickListener(this);

            Cursor mCursor = getContacts();
            startManagingCursor(mCursor);

            ListAdapter adapter = new SimpleCursorAdapter(this, android.R.layout.simple_list_item_multiple_choice, mCursor,
                                                          Contacts = new String[] ContactsContract.Contacts.DISPLAY_NAME ,
                                                          to = new int[]  android.R.id.text1 );
            setListAdapter(adapter);
            myListView = getListView();
            myListView.setItemsCanFocus(false);
            myListView.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);

         

        private Cursor getContacts() 
            // Run query
            Uri uri = ContactsContract.Contacts.CONTENT_URI;
            String[] projection = new String[]  ContactsContract.Contacts._ID,
                                            ContactsContract.Contacts.DISPLAY_NAME;
            String selection = ContactsContract.Contacts.HAS_PHONE_NUMBER + " = '"
                    + ("1") + "'";
            String[] selectionArgs = null;
            String sortOrder = ContactsContract.Contacts.DISPLAY_NAME
                    + " COLLATE LOCALIZED ASC";

            return managedQuery(uri, projection, selection, selectionArgs,
                    sortOrder);
        

        public void onClick(View src) 
            Intent i;
            switch (src.getId())
            
            case R.id.save_group_button:

                int checked_Names_Counter = 0;

                // Goes over the list of contacts and checks which were checked
                for (int j = 0; j < myListView.getCount(); j++)
                
                    if (myListView.isItemChecked(j) == true)
                       
                        Cursor cur = getContacts();
                        ContentResolver contect_resolver = getContentResolver();
                        cur.moveToFirst();

                        /**
                        * Here I tried to compare the IDs but each list has different IDs so it didn't really help me...
                        // Converts the current checked name ID into a String
                        String Checked_ID = String.valueOf(myListView.getCheckedItemIds()[checked_Names_Counter]);

                        // Checks if the current checked ID matches the cursors ID, if not move the cursor to the next name
                        while (Checked_ID != cur.getString(cur.getColumnIndexOrThrow(ContactsContract.Contacts._ID)))
                        
                            cur.moveToNext();
                        
                        */

                        /**
                        * Here I tried to compare the names, even though it's not a good pratice, and it didn't work either...
                        String Checked_Name = myListView.getAdapter().getItem(checked_Names_Counter).toString();

                        // Checks if the current checked ID matches the cursors ID, if not move the cursor to the next name
                        while (Checked_Name != cur.getString(cur.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME)))
                        
                            cur.moveToNext();
                        
                        */
                        String id = cur.getString(cur.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
                        String name = "";
                        String no = "";

                        Cursor phoneCur = contect_resolver.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                                ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]  id , null);


                        name = phoneCur.getString(phoneCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                        no = phoneCur.getString(phoneCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

                        id = null;
                        name = null;
                        no = null;
                        phoneCur = null;
                        checked_Names_Counter++;

                    
                

                // Goes back to the Manage Groups screen
                i = new Intent(this, Manage_Groups.class);
                startActivity(i);
                break;  
        

      
    

有什么想法吗？

谢谢！！

【参考方案1】：

看起来你很亲密，我使用 ListView.getCheckedItemIds() 来返回所选联系人的唯一 ID：

public void onClick(View view) 
    long[] ids = myListView.getCheckedItemIds();
    for(long id : ids) 
        Cursor contact = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, 
                ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]  id + "" , null);

        // Do whatever you want with the data
    

加法

我有一个关于这段代码的小问题：

// Goes back to the Manage Groups screen
i = new Intent(this, Manage_Groups.class);
startActivity(i);

这是否会让用户回到上一个 Activity？如果是这样，您应该改用finish();。 finish() 结束当前 Activity，将其从堆栈中取出并释放所有内存（浪费的内存更少意味着应用程序更快。）它还允许之前的 Activity 在离开时恢复保存的状态（填充 EditTexts，之前的 Spinner 选择、切换按钮和复选标记等）Activity 从用户离开的地方继续。

【讨论】：

是的，它确实回到了以前的活动，我会添加你所说的。另外，我只是简单地检查了您发布的内容，但我认为它很好用，我稍后会完成检查。谢谢！！！

@user1476876 如果此答案对您有帮助，请单击左上角的复选标记。

作为对看到此答案的其他人的警告。您不应该在主线程上调用 ContentResolver.query。由于调用将执行文件 IO，因此您可能会遇到 ANR。在 Loader 或 AsyncTask 或类似中加载联系人。您还可以编辑查询以在一个查询中加载所有相关联系人，而不是每个联系人一个查询。