Qt 显示应用程序,如果当前正在运行
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【中文标题】Qt 显示应用程序,如果当前正在运行【英文标题】:Qt show application, if currently running 【发布时间】:2018-01-02 12:26:11 【问题描述】:我正在创建一个最小化到系统托盘的单实例应用程序,我想显示当前正在运行的实例,然后退出新的实例。如何创建此功能?
main.cpp
#include <QApplication>
#include <QQmlApplicationEngine>
#include <QIcon>
#include <QQuickWidget>
#include <QSystemTrayIcon>
#include <QQmlContext>
#include <QQmlEngine>
#include <QSystemSemaphore>
#include <QSharedMemory>
// Declare a user-defined data type to work with an icon in QML
Q_DECLARE_METATYPE(QSystemTrayIcon::ActivationReason)
Q_DECL_EXPORT int main(int argc, char *argv[])
#if defined(Q_OS_WIN)
QCoreApplication::setAttribute(Qt::AA_EnableHighDpiScaling);
#endif
QApplication app(argc, argv);
QQmlApplicationEngine engine;
QSystemSemaphore semaphore("deploy", 1); // create semaphore
semaphore.acquire(); // Raise the semaphore, barring other instances to work with shared memory
#ifndef Q_OS_WIN32
// in linux / unix shared memory is not freed when the application terminates abnormally,
// so you need to get rid of the garbage
QSharedMemory nix_fix_shared_memory("deploy Shared Memory");
if(nix_fix_shared_memory.attach())
nix_fix_shared_memory.detach();
#endif
QSharedMemory sharedMemory("deploy Shared Memory"); // Create a copy of the shared memory
bool is_running; // variable to test the already running application
if (sharedMemory.attach()) // We are trying to attach a copy of the shared memory
// To an existing segment
is_running = true; // If successful, it determines that there is already a running instance
else
sharedMemory.create(1); // Otherwise allocate 1 byte of memory
is_running = false; // And determines that another instance is not running
semaphore.release();
// If you already run one instance of the application, then we inform the user about it
// and complete the current instance of the application
if(is_running)
return -1;
// Register QSystemTrayIcon in Qml
qmlRegisterType<QSystemTrayIcon>("QSystemTrayIcon", 1, 0, "QSystemTrayIcon");
// Register in QML the data type of click by tray icon
qRegisterMetaType<QSystemTrayIcon::ActivationReason>("ActivationReason");
// Set icon in the context of the engine
engine.rootContext()->setContextProperty("iconTray", QIcon(":/deploy.png"));
engine.load(QUrl(QStringLiteral("qrc:/main.qml")));
if (engine.rootObjects().isEmpty())
return -1;
return app.exec();
main.qml
import QtQuick 2.9
import QtQuick.Controls 2.2
import QtQuick.Controls 1.4 as Tray
import QtQuick.Dialogs 1.2
import QtQuick.Extras 1.2
import QtQuick.Window 2.0
import QSystemTrayIcon 1.0
Window
visible: true
id: application
width: 640
height: 480
title: qsTr("Test")
// system tray
QSystemTrayIcon
id: systemTray
// Initial initialization of the system tray
Component.onCompleted:
icon = iconTray // Set icon
toolTip = "Deploy App"
show();
if(application.visibility === Window.Hidden)
application.show()
else
application.hide()
/* By clicking on the tray icon define the left or right mouse button click was.
* If left, then hide or open the application window.
* If right, then open the System Tray menu
* */
onActivated:
if(reason === 1)
trayMenu.popup()
else
if(application.visibility === Window.Hidden)
application.show()
else
application.hide()
// Menu system tray
Tray.Menu
id: trayMenu
Tray.MenuItem
text: qsTr("Show App")
onTriggered: application.show()
Tray.MenuItem
text: qsTr("Quit")
onTriggered:
systemTray.hide()
Qt.quit()
我尝试创建一个对象,并在我的main.cpp
和我的main.qml
中将其运行状态设置为 false 或 true,然后检查值并退出应用程序。
QQmlApplicationEngine engine;
QQmlContext *context = engine.rootContext();
SingleInstance singleInstance;
context->setContextProperty("SingleInstance", &singleInstance);
if (is_running)
singleInstance.running(true);
在我的main.qml
中,我检查应用程序是否正在运行。
Connections
target: SingleInstance
Component.onCompleted:
if (SingleInstance.running)
if(application.visibility === Window.Hidden)
Qt.quit()
【问题讨论】:
【参考方案1】:我们最终为单个实例做的是使用QLocalSocket,它在 Windows 上被命名为管道,在 Unix 上被命名为本地域套接字,而不是 QSharedMemory
,这需要更多的调整才能让它正确。基本上你做这样的事情来检查服务器是否正在运行(appName
必须是唯一的应用程序标识符,你可以使用例如QCoreApplication::applicationName):
bool isSingleInstanceRunning(QString appName)
QLocalSocket socket;
socket.connectToServer(m_appName);
bool isOpen = socket.isOpen();
socket.close();
return isOpen;
如果您收到false
,您将创建自己的服务器(在应用程序的生命周期内保留此实例):
QLocalServer* startSingleInstanceServer(QString appName)
QLocalServer* server = new QLocalServer;
server->setSocketOptions(QLocalServer::WorldAccessOption);
server->listen(appName);
您还可以将命令行参数从启动应用程序传递到已经运行的实例 - 在应用程序的启动实例中打开套接字并发送命令行参数。在现有实例端,只需挂钩到QLocalServer::newConnection 信号,打开套接字并挂钩到QLocalSocket::readyRead 信号。
【讨论】:
【参考方案2】:对于这个用例 QtSingleApplication
已经创建,它也适用于 Qt5:
https://github.com/qtproject/qt-solutions/tree/master/qtsingleapplication
【讨论】:
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