Chisq.test/prop.test 对不同长度的向量
Posted
技术标签:
【中文标题】Chisq.test/prop.test 对不同长度的向量【英文标题】：Chisq.test/prop.test on vectors of different lengths 【发布时间】：2022-01-22 02:21:57 【问题描述】：我正在尝试对一些患者进行手术而其他患者不进行手术的数据进行 chisq.test 或 prop.test。我想看看两组中两种性别的比例是否相等。在我的手术组和非手术组大小不相等的情况下，最合适的测试是什么？
我正在尝试使用以下代码，使用 data.table 但我也得到了以下错误：
> chisq.test(lateral[Surgery == "No", "sex",with=F], lateral[Surgery == "Yes", "sex",with=F])
Error in chisq.test(lateral[Surgery == "No", "sex", with = F], lateral[Surgery == :
'x' and 'y' must have the same length
For prop.test():
Error in complete.cases(x, n) : not all arguments have the same length
数据
setDT(structure(list(sex = c(2L, 2L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 2L, 1L, 2L), Surgery = c("No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes" )), row.names = c(NA, -239L), class = c("data.table", "data.frame" )))
【问题讨论】：
你能提供你的数据dput(your_df_goes_here)吗？
已添加！谢谢！
虽然我们清理起来并不难，但当您发布data.table 的dput(.) 输出时，它包含一个无法使用的组件.internal.selfref = <pointer: ...>。我正在编辑您的问题以将其删除并包含在setDT(.) 中，以便它可以按原样有效使用。请在未来的问题中考虑这一点。谢谢！
底线：使用chisq.test(table(lateral))。
【参考方案1】：
您可以将表格传递给函数chisq.test，使其更简单。例如
df <- structure(list(sex = c(2L, 2L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L,
1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 2L, 2L, 1L, 2L, 1L, 1L, 1L,
2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L,
1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 1L, 2L, 1L, 1L, 1L,
1L, 2L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L,
2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L,
1L, 2L, 1L, 1L, 2L, 2L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L,
2L, 2L, 2L, 1L, 2L, 1L, 1L, 1L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L,
1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
2L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L,
2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 1L, 2L, 1L,
1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L,
2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L,
2L, 2L, 2L, 1L, 2L), Surgery = c("No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "No", "No", "No", "No", "No",
"No", "No", "No", "No", "No", "No", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes",
"Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes", "Yes"
)), row.names = c(NA, -239L), class = c("data.table", "data.frame"))
df$sex <- as.factor(df$sex)
df$Surgery <- as.factor(df$Surgery)
(prop_table <- table(df))
# Surgery
# sex No Yes
# 1 97 66
# 2 57 19
mod1 <- chisq.test(prop_table)
mod1
# Pearson's Chi-squared test with Yates' continuity correction
#
# data: prop_table
# X-squared = 4.7727, df = 1, p-value = 0.02892
str(mod1)
# List of 9
# $ statistic: Named num 4.77
# ..- attr(*, "names")= chr "X-squared"
# $ parameter: Named int 1
# ..- attr(*, "names")= chr "df"
# $ p.value : num 0.0289
# $ method : chr "Pearson's Chi-squared test with Yates' continuity correction"
# $ data.name: chr "prop_table"
# $ observed : 'table' int [1:2, 1:2] 97 57 66 19
# ..- attr(*, "dimnames")=List of 2
# .. ..$ sex : chr [1:2] "1" "2"
# .. ..$ Surgery: chr [1:2] "No" "Yes"
# $ expected : num [1:2, 1:2] 105 49 58 27
# ..- attr(*, "dimnames")=List of 2
# .. ..$ sex : chr [1:2] "1" "2"
# .. ..$ Surgery: chr [1:2] "No" "Yes"
# $ residuals: 'table' num [1:2, 1:2] -0.783 1.147 1.055 -1.544
# ..- attr(*, "dimnames")=List of 2
# .. ..$ sex : chr [1:2] "1" "2"
# .. ..$ Surgery: chr [1:2] "No" "Yes"
# $ stdres : 'table' num [1:2, 1:2] -2.33 2.33 2.33 -2.33
# ..- attr(*, "dimnames")=List of 2
# .. ..$ sex : chr [1:2] "1" "2"
# .. ..$ Surgery: chr [1:2] "No" "Yes"
# - attr(*, "class")= chr "htest"
【讨论】：
以上是关于Chisq.test/prop.test 对不同长度的向量的主要内容，如果未能解决你的问题，请参考以下文章