如何从谷歌地图的经纬度坐标中获取城市名称？
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【中文标题】如何从谷歌地图的经纬度坐标中获取城市名称？【英文标题】：How to get city name from latitude and longitude coordinates in Google Maps? 【发布时间】：2011-01-18 18:38:51 【问题描述】：如果我有城镇或地区的经纬度坐标，如何在 Google 地图中获取城市名称？
我尝试使用纬度、经度和国家，但我不知道如何获得城市名称。
【问题讨论】：
【参考方案1】：从Geocoder 对象，您可以调用getFromLocation(double, double, int) 方法。它将返回具有getLocality() 方法的Address 对象列表。
Geocoder gcd = new Geocoder(context, Locale.getDefault());
List<Address> addresses = gcd.getFromLocation(lat, lng, 1);
if (addresses.size() > 0)
System.out.println(addresses.get(0).getLocality());
else
// do your stuff
【讨论】：
我收到错误消息“等待服务器响应超时”。我已添加 Internet 权限。还需要别的吗？ 有时 getLocality() 返回 null 并且城市名称停留在 mAdminArea 对于美国（和其他一些国家）的地址，使用 getAdminArea() 返回状态 请不要使用地理编码器。它在许多设备上引发异常，需要重新启动才能再次正常工作。getLocality() 有时会返回 null。 getAdminArea() 给出了加拿大的省或州，而getSubAdminAread() 给出了城市，但这很奇怪，例如“多伦多分部”【参考方案2】：
我正在使用此代码。您也可以通过 this 获取有关纬度和经度的城市和其他详细信息：
public class getReverseGeoCoding
private String Address1 = "", Address2 = "", City = "", State = "", Country = "", County = "", PIN = "";
public void getAddress()
Address1 = "";
Address2 = "";
City = "";
State = "";
Country = "";
County = "";
PIN = "";
try
JSONObject jsonObj = parser_Json.getJSONfromURL("http://maps.googleapis.com/maps/api/geocode/json?latlng=" + Global.curLatitude + ","
+ Global.curLongitude + "&sensor=true&key=YOUR_API_KEY");
String Status = jsonObj.getString("status");
if (Status.equalsIgnoreCase("OK"))
JSONArray Results = jsonObj.getJSONArray("results");
JSONObject zero = Results.getJSONObject(0);
JSONArray address_components = zero.getJSONArray("address_components");
for (int i = 0; i < address_components.length(); i++)
JSONObject zero2 = address_components.getJSONObject(i);
String long_name = zero2.getString("long_name");
JSONArray mtypes = zero2.getJSONArray("types");
String Type = mtypes.getString(0);
if (TextUtils.isEmpty(long_name) == false || !long_name.equals(null) || long_name.length() > 0 || long_name != "")
if (Type.equalsIgnoreCase("street_number"))
Address1 = long_name + " ";
else if (Type.equalsIgnoreCase("route"))
Address1 = Address1 + long_name;
else if (Type.equalsIgnoreCase("sublocality"))
Address2 = long_name;
else if (Type.equalsIgnoreCase("locality"))
// Address2 = Address2 + long_name + ", ";
City = long_name;
else if (Type.equalsIgnoreCase("administrative_area_level_2"))
County = long_name;
else if (Type.equalsIgnoreCase("administrative_area_level_1"))
State = long_name;
else if (Type.equalsIgnoreCase("country"))
Country = long_name;
else if (Type.equalsIgnoreCase("postal_code"))
PIN = long_name;
// JSONArray mtypes = zero2.getJSONArray("types");
// String Type = mtypes.getString(0);
// Log.e(Type,long_name);
catch (Exception e)
e.printStackTrace();
public String getAddress1()
return Address1;
public String getAddress2()
return Address2;
public String getCity()
return City;
public String getState()
return State;
public String getCountry()
return Country;
public String getCounty()
return County;
public String getPIN()
return PIN;
For more detail on how to get Google Map Api key
JSON 解析器类
public class parser_Json
public static JSONObject getJSONfromURL(String url)
// initialize
InputStream is = null;
String result = "";
JSONObject jObject = null;
// http post
try
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
catch (Exception e)
Log.e("log_tag", "Error in http connection " + e.toString());
// convert response to string
try
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
sb.append(line + "\n");
is.close();
result = sb.toString();
catch (Exception e)
Log.e("log_tag", "Error converting result " + e.toString());
// try parse the string to a JSON object
try
jObject = new JSONObject(result);
catch (JSONException e)
Log.e("log_tag", "Error parsing data " + e.toString());
return jObject;
您可以从这个问题获得更多信息：Get the particular address using latitude and longitude
【讨论】：
@ErumHannan 你可以在你的服务中这样做 ** new getReverseGeoCoding().getCity(); ** 这将返回您当前的 City 或 lat，long 来自 Global 类。 我使用了你的代码，但它返回一个错误，上面写着 "error_message":"您必须使用 API 密钥来验证对 Google Maps Platform API 的每个请求。有关其他信息，请参阅 http: \/\/g.co\/dev\/maps-no-account","results":[],"status":"REQUEST_DENIED" 我应该如何解决？【参考方案3】：试试这个
List<Address> list = geoCoder.getFromLocation(location
.getLatitude(), location.getLongitude(), 1);
if (list != null & list.size() > 0)
Address address = list.get(0);
result = address.getLocality();
return result;
【讨论】：
【参考方案4】：只需使用此方法并传递您的经度、经度即可。
public static void getAddress(Context context, double LATITUDE, double LONGITUDE)
//Set Address
try
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null && addresses.size() > 0)
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
Log.d(TAG, "getAddress: address" + address);
Log.d(TAG, "getAddress: city" + city);
Log.d(TAG, "getAddress: state" + state);
Log.d(TAG, "getAddress: postalCode" + postalCode);
Log.d(TAG, "getAddress: knownName" + knownName);
catch (IOException e)
e.printStackTrace();
return;
【讨论】：
这增加了哪些现有答案中没有的内容？ @OrangeDog 一个带有 Try Catch 异常的简化方法。所以其他人可以很容易地理解它。【参考方案5】：试试下面的代码希望对你有用：-
CityAsyncTask cst = new CityAsyncTask(HomeScreenUserLocation.this,
latitude, longitude);
cst.execute();
String lo = null;
try
lo = cst.get().toString();
catch (InterruptedException e)
// TODO Auto-generated catch block
e.printStackTrace();
catch (ExecutionException e)
// TODO Auto-generated catch block
e.printStackTrace();
和AsyncTask
public class CityAsyncTask extends AsyncTask<String, String, String>
Activity act;
double latitude;
double longitude;
public CityAsyncTask(Activity act, double latitude, double longitude)
// TODO Auto-generated constructor stub
this.act = act;
this.latitude = latitude;
this.longitude = longitude;
@Override
protected String doInBackground(String... params)
String result = "";
Geocoder geocoder = new Geocoder(act, Locale.getDefault());
try
List<Address> addresses = geocoder.getFromLocation(latitude,
longitude, 1);
Log.e("Addresses", "-->" + addresses);
result = addresses.get(0).toString();
catch (IOException e)
e.printStackTrace();
return result;
@Override
protected void onPostExecute(String result)
// TODO Auto-generated method stub
super.onPostExecute(result);
【讨论】：
【参考方案6】： private class MatchingNearByLocationTask extends
AsyncTask<Void, Void, Void>
@Override
protected void onPreExecute()
super.onPreExecute();
// Showing progress dialog
progressDialog = new ProgressDialog(mContext);
progressDialog.setMessage("Loading...");
progressDialog.setCancelable(true);
progressDialog.show();
@Override
protected Void doInBackground(Void... arg0)
jsonStr = getLocationInfo(Latitude, Longitude).toString();
if (jsonStr != null)
Log.i("location--??", jsonStr);
JSONObject jsonObj;
try
jsonObj = new JSONObject(jsonStr);
String Status = jsonObj.getString("status");
if (Status.equalsIgnoreCase("OK"))
JSONArray Results = jsonObj.getJSONArray("results");
JSONObject zero = Results.getJSONObject(0);
JSONArray address_components = zero
.getJSONArray("address_components");
for (int i = 0; i < address_components.length(); i++)
JSONObject zero2 = address_components
.getJSONObject(i);
String long_name = zero2.getString("long_name");
JSONArray mtypes = zero2.getJSONArray("types");
String Type = mtypes.getString(0);
if (Type.equalsIgnoreCase("administrative_area_level_2"))
// Address2 = Address2 + long_name + ", ";
String City = long_name;
Log.d(" CityName --->", City + "");
catch (JSONException e)
e.printStackTrace();
return null;
@Override
protected void onPostExecute(Void result)
super.onPostExecute(result);
// Dismiss the progress dialog
if (progressDialog.isShowing())
progressDialog.dismiss();
@Override
protected void onCancelled()
super.onCancelled();
progressDialog.dismiss();
private JSONObject getLocationInfo(double lat, double lng)
HttpGet httpGet = new HttpGet(
"http://maps.googleapis.com/maps/api/geocode/json?latlng="
+ lat + "," + lng + "&sensor=false");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();
try
response = client.execute(httpGet);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1)
stringBuilder.append((char) b);
catch (ClientProtocolException e)
catch (IOException e)
JSONObject jsonObject = new JSONObject();
try
jsonObject = new JSONObject(stringBuilder.toString());
catch (JSONException e)
e.printStackTrace();
return jsonObject;
【讨论】：
【参考方案7】：试试这个
var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);
geocoder.geocode(
'latLng': latlng,
function(results, status)
if (status == google.maps.GeocoderStatus.OK)
if (results[0])
var add= results[0].formatted_address ;
var value=add.split(",");
count=value.length;
country=value[count-1];
state=value[count-2];
city=value[count-3];
alert("city name is: " + city);
else
alert("address not found");
else
alert("Geocoder failed due to: " + status);
);
【讨论】：
【参考方案8】：我找到了解决此问题的新方法。在这里，我使用了 google http 服务来获取基于经度和纬度的位置的总信息。您只需要在 url 和您的 api 密钥中传递纬度和经度（例如：latlng=21.1497409, 79.08747970000002 & key=YOUR API KEY）。这是我在ExampleServiceClass 获得的服务
getService(url)
return this.http.get(url).map((data: any) => data.json())
你可以把它放在任何你想要的地方，然后从你需要位置数据的组件中调用下面的服务
this._exampleService.getService("https://maps.googleapis.com/maps/api/geocode/json?latlng=21.1497409, 79.08747970000002&key=YOUR API KEY").subscribe(getplaceData =>
var placeDataDest: any;
placeDataDest = getplaceData;
console.log("i got place id yeee " + placeDataDest['results'][0]['place_id']);
console.log("i got place details yeee " + placeDataDest['results']);
);
类似地找到城市名称....希望你会发现这很有用
【讨论】：
【参考方案9】：请参考以下代码
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(latitude, longitude, 1);
String cityName = addresses.get(0).getAddressLine(0);
String stateName = addresses.get(0).getAddressLine(1);
String countryName = addresses.get(0).getAddressLine(2);
【讨论】：
【参考方案10】：尝试使用这个 api：
网址 ":http://maps.googleapis.com/maps/api/geocode/json?latlng="+String.valueOf(you_lattitude)+","+String.valueOf(your_longitude)
【讨论】：
【参考方案11】：如果你有一个列表，你可以使用它：
Address address = list.get(0);
String cityname = address.getLocality();
【讨论】：
【参考方案12】： com.alibaba.fastjson.JSONObject jsonObject = com.alibaba.fastjson.JSONObject.parseObject(data);
if("OK".equals(jsonObject.getString("status")))
String formatted_address;
JSONArray results = jsonObject.getJSONArray("results");
if(results != null && results.size() > 0)
com.alibaba.fastjson.JSONObject object = results.getJSONObject(0);
String addressComponents = object.getString("address_components");
formatted_address = object.getString("formatted_address");
Log.e("amaya","formatted_address="+formatted_address+"--url="+url);
if(findCity)
boolean finded = false;
JSONArray ac = JSONArray.parseArray(addressComponents);
if(ac != null && ac.size() > 0)
for(int i=0;i<ac.size();i++)
com.alibaba.fastjson.JSONObject jo = ac.getJSONObject(i);
JSONArray types = jo.getJSONArray("types");
if(types != null && types.size() > 0)
for(int j=0;j<ac.size();j++)
String string = types.getString(i);
if("administrative_area_level_1".equals(string))
finded = true;
break;
if(finded) break;
Log.e("amaya","city="+formatted_address);
else
Log.e("amaya","poiName="+hotspotPoi.getPoi_name()+"--"+hotspotPoi);
if(hotspotPoi != null) hotspotPoi.setPoi_name(formatted_address);
EventBus.getDefault().post(new AmayaEvent.GeoEvent(hotspotPoi));
这是一种解析谷歌反馈数据的方法。
【讨论】：
【参考方案13】：工作代码：
addresses = geocoder.getFromLocation(mMap.getCameraPosition().target.latitude, mMap.getCameraPosition().target.longitude, 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5
String locality = addresses.get(0).getLocality(); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String subLocality = addresses.get(0).getSubLocality(); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
//String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String address1 = addresses.get(0).getAddressLine(1); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String address2 = addresses.get(0).getAddressLine(2); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
// String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName();
【讨论】：
【参考方案14】：import org.json.JSONObject
fun parseLocation(response: String): GeoLocation?
val geoCodes by lazy doubleArrayOf(0.0, 0.0)
val jObj = JSONObject(response)
if (jObj.has(KEY_RESULTS))
val jArrResults = jObj.getJSONArray(KEY_RESULTS)
for (i in 0 until jArrResults.length())
val jObjResult = jArrResults.getJSONObject(i)
//getting latitude and longitude
if (jObjResult.has(KEY_GEOMETRY))
val jObjGeometry = jObjResult.getJSONObject(KEY_GEOMETRY)
if (jObjGeometry.has(KEY_LOCATION))
val jObjLocation = jObjGeometry.getJSONObject(KEY_LOCATION)
if (jObjLocation.has(KEY_LAT))
geoCodes[0] = jObjLocation.getDouble(KEY_LAT)
if (jObjLocation.has(KEY_LNG))
geoCodes[1] = jObjLocation.getDouble(KEY_LNG)
var administrativeAreaLevel1: String? = null
//getting city
if (jObjResult.has(KEY_ADDRESS_COMPONENTS))
val jArrAddressComponents = jObjResult.getJSONArray(KEY_ADDRESS_COMPONENTS)
for (i in 0 until jArrAddressComponents.length())
val jObjAddressComponents = jArrAddressComponents.getJSONObject(i)
if (jObjAddressComponents.has(KEY_TYPES))
val jArrTypes = jObjAddressComponents.getJSONArray(KEY_TYPES)
for (j in 0 until jArrTypes.length())
when (jArrTypes.getString(j))
VALUE_LOCALITY, VALUE_POSTAL_TOWN ->
return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
ADMINISTRATIVE_AREA_LEVEL_1 ->
administrativeAreaLevel1 = jObjAddressComponents.getString(KEY_LONG_NAME)
else ->
for (i in 0 until jArrAddressComponents.length())
val jObjAddressComponents = jArrAddressComponents.getJSONObject(i)
if (jObjAddressComponents.has(KEY_TYPES))
val jArrTypes = jObjAddressComponents.getJSONArray(KEY_TYPES)
val typeList = ArrayList<String>()
for (j in 0 until jArrTypes.length())
typeList.add(jArrTypes.getString(j))
if (typeList.contains(VALUE_SUBLOCALITY))
var hasSubLocalityLevel = false
typeList.forEach type ->
if (type.contains(VALUE_SUBLOCALITY_LEVEL))
hasSubLocalityLevel = true
if (type == VALUE_SUBLOCALITY_LEVEL_1)
return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
if (!hasSubLocalityLevel)
return GeoLocation(jObjAddressComponents.getString(KEY_LONG_NAME), *geoCodes)
if (geoCodes.isNotEmpty()) return GeoLocation(administrativeAreaLevel1, geoCodes = *geoCodes)
return null
data class GeoLocation(val latitude: Double = 0.0, val longitude: Double = 0.0, val city: String? = null) : Parcelable
constructor(city: String? = null, vararg geoCodes: Double) : this(geoCodes[0], geoCodes[1], city)
constructor(source: Parcel) : this(source.readDouble(), source.readDouble(), source.readString())
companion object
@JvmField
val CREATOR = object : Parcelable.Creator<GeoLocation>
override fun createFromParcel(source: Parcel) = GeoLocation(source)
override fun newArray(size: Int): Array<GeoLocation?> = arrayOfNulls(size)
override fun writeToParcel(dest: Parcel, flags: Int)
dest.writeDouble(latitude)
dest.writeDouble(longitude)
dest.writeString(city)
override fun describeContents() = 0
【讨论】：
【参考方案15】：我在巴西。由于区域细节，有时城市以不同的方式出现。我认为在印度和其他国家也是如此。因此，为了防止错误，我进行了此验证：
private fun getAddress(latLng: LatLng): String
// 1
val geocoder = Geocoder(this)
val addresses: List<Address>?
var city = "no"
try
addresses = geocoder.getFromLocation(latLng.latitude, latLng.longitude, 1)
if (null != addresses && !addresses.isEmpty()) //prevent from error
//sometimes the city comes in locality, sometimes in subAdminArea.
if (addresses[0].locality == null)
city = addresses[0].subAdminArea
else
city = addresses[0].locality
catch (e: IOException)
Log.e("MapsActivity", e.localizedMessage)
return city
您还可以检查城市是否返回“否”。如果是这样，则无法获取用户位置。 希望对您有所帮助。
【讨论】：
null != addresses && !addresses.isEmpty() 在 Kotlin 中看起来很糟糕。以上是关于如何从谷歌地图的经纬度坐标中获取城市名称？的主要内容，如果未能解决你的问题，请参考以下文章