具有公共值的 XML SelectNodes，迭代

Posted 2023-04-12

【中文标题】具有公共值的 XML SelectNodes，迭代

【英文标题】：XML SelectNodes with common values, iteratively

【发布时间】：2021-06-04 23:25:59

【问题描述】：

我有一个登记选民的 XML 文档，并且可能有多个人在一个地址。我想为每个不同的地址（数字和街道）迭代地选择节点。我的目标是能够将一个地址的所有居民的姓名组合到一行中。例如“罗伯特和奥尔加 bbbbbb”，或“Jennifer eeeee 和 James fffff”，或者只是“Desmond aaaaaa”。 我只需要 XPath 查询方面的帮助。如果 LINQ 是答案，我也想听听。你能帮我解决这个问题吗？

<addresses xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <address>
        <LastName>aaaaaa</LastName>
        <FirstName>DESMOND</FirstName>
        <Number>311</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>bbbbbb</LastName>
        <FirstName>OLGA</FirstName>
        <Number>315</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>bbbbbb</LastName>
        <FirstName>ROBERT</FirstName>
        <Number>315</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>cccccc</LastName>
        <FirstName>YUJI</FirstName>
        <Number>316</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>dddddd</LastName>
        <FirstName>MARK</FirstName>
        <Number>319</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>dddddd</LastName>
        <FirstName>HILARY</FirstName>
        <Number>319</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>eeeeee</LastName>
        <FirstName>JENNIFER</FirstName>
        <Number>320</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>ffffff</LastName>
        <FirstName>JAMES</FirstName>
        <Number>320</Number>
        <Street>APPLETON ST</Street>
    </address>
    <address>
        <LastName>gggggg</LastName>
        <FirstName>NORA</FirstName>
        <Number>323</Number>
        <Street>APPLETON ST</Street>
    </address>
</addresses>```

【参考方案1】：

尝试关注。大多数人会使用效率不高的 Xml 序列化。在这种情况下，我更喜欢 Xml Linq：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1

    class Program
    
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        
            XDocument doc = XDocument.Load(FILENAME);

            List<Address> addresses = doc.Descendants("address").Select(x => new Address()
            
                lastName = (string)x.Element("LastName"),
                firstName = (string)x.Element("FirstName"),
                number = (int)x.Element("Number"),
                street = (string)x.Element("Street")
            ).ToList();

            var groups = addresses.GroupBy(x => new  number = x.number, street = x.street ).ToList();
        
    
    public class Address
    
        public string lastName  get; set; 
        public string firstName  get; set; 
        public int number  get; set; 
        public string street  get; set; 
    

【讨论】：

绝对完美，非常感谢jdweng！！