是否可以在 LINQ 查询中拆分值并添加 if 条件?

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【中文标题】是否可以在 LINQ 查询中拆分值并添加 if 条件?【英文标题】:Is it possible to split a value and add an if condition in a LINQ Query? 【发布时间】:2020-11-26 13:16:20 【问题描述】:

我从以下 JSON 响应开始:


  "d": 
    "RowData": [
      
        "GenreId": 11,
        "GenreName": "Musical",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_1"
      ,
      
        "GenreId": 12,
        "GenreName": "kids",
        "subjecturl": "subjecturl_abc",
        "logourl": "logourl_2"
      ,
      
        "GenreId": 13,
        "GenreName": "other",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_3"
      ,
      
        "GenreId": 14,
        "GenreName": "Musical",
        "subjecturl": "subjecturl_abc",
        "logourl": "logourl_4"
      ,
      
        "GenreId": 15,
        "GenreName": "Music",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_5"
      ,
      
        "GenreId": 16,
        "GenreName": "Faimaly",
        "subjecturl": "subjecturl_abc",
        "logourl": "logourl_6"
      ,
      
        "GenreId": 17,
        "GenreName": "other",
        "subjecturl": "subjecturl_abc",
        "logourl": "logourl_7"
      ,
      
        "GenreId": 18,
        "GenreName": "other",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_8"
      ,
      
        "GenreId": 19,
        "GenreName": "kids",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_9"
      ,
      
        "GenreId": 20,
        "GenreName": "Musical",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_10"
      ,
      
        "GenreId": 21,
        "GenreName": "other",
        "subjecturl": "subjecturl_123",
        "logourl": "logourl_11"
      
    ]
  

我的目标是将上面的响应转换成如下所示的新响应:


  "rows": [
    
      "title": "Musical",
      "items": [
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_1",
          "subjecturlsplit": "1"
        ,
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_4",
          "subjecturlsplit": "abc"
        ,
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_10",
          "subjecturlsplit": "10"
        
      ]
    ,
    
      "title": "kids",
      "items": [
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_2",
          "subjecturlsplit": "abc"
        ,
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_9",
          "subjecturlsplit": "9"
        
      ]
    ,
    
      "title": "Music",
      "items": [
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_5",
          "subjecturlsplit": "5"
        
      ]
    ,
    
      "title": "other",
      "items": [
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_3",
          "subjecturlsplit": "3"
        ,
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_7",
          "subjecturlsplit": "abc"
        ,
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_8",
          "subjecturlsplit": "8"
        ,
        
          "hdsubjecturl": "logourl_123",
          "hdlogourl": "logourl_11",
          "subjecturlsplit": "11"
        
      ]
    ,
    
      "title": "Faimaly",
      "items": [
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_6",
          "subjecturlsplit": "abc"
        
      ]
    
  ]

我尝试了以下 LINQ 查询来做出上述响应:

var data = json["d"]?["RowData"]
    .GroupBy(x => x["GenreName"])
    .ToDictionary(g => g.Key, g => g.ToList())
    .Select(kvp => new
    
        title = kvp.Key,
        items = kvp.Value.Select(x => new  hdsubjecturl = x["subjecturl"], url = x["logourl"], subjecturlsplit = "" )
    );
var result = JObject.FromObject(new  rows = data );

使用此查询,我做出了如下回复。


  "rows": [
    
      "title": "Musical",
      "items": [
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_1",
          "subjecturlsplit": ""
        ,
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_4",
          "subjecturlsplit": ""
        ,
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_10",
          "subjecturlsplit": ""
        
      ]
    ,
    
      "title": "kids",
      "items": [
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_2",
          "subjecturlsplit": ""
        ,
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_9",
          "subjecturlsplit": ""
        
      ]
    ,
    
      "title": "Music",
      "items": [
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_5",
          "subjecturlsplit": ""
        
      ]
    ,
    
      "title": "other",
      "items": [
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_3",
          "subjecturlsplit": ""
        ,
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_7",
          "subjecturlsplit": ""
        ,
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_8",
          "subjecturlsplit": ""
        ,
        
          "hdsubjecturl": "subjecturl_123",
          "hdlogourl": "logourl_11",
          "subjecturlsplit": ""
        
      ]
    ,
    
      "title": "Faimaly",
      "items": [
        
          "hdsubjecturl": "subjecturl_abc",
          "hdlogourl": "logourl_6",
          "subjecturlsplit": ""
        
      ]
    
  ]

请注意,每个项目的subjecturlsplit 都是空的。在这里,是否可以在此 LINQ 查询中添加条件逻辑?我想将hdsubjecturl 值拆分为下划线(_)并检查第二部分是否等于abc。如果是,那么我想将subjecturlsplit 设置为hdsubjecturl 字段。否则,我想将hdlogourl 值拆分为下划线并将subjecturlsplit 设置为该拆分的第二部分。还是有其他方法可以做到这一点?

【问题讨论】:

听起来很像,但您的问题措辞复杂。如果您只是询问如何在表达式中编写条件逻辑,您可以使用三元运算符:condition ? resultWhenTrue: resultWhenFalse。此外,由于这是 LINQ to Objects,因此您的选择 lambda 可以具有块体。基本上,你可以做任何事情。 【参考方案1】:

是的,您可以将块体放入 lambda 表达式中,这样您就可以在那里执行您的逻辑:

var data = json["d"]?["RowData"]
    .GroupBy(x => x["GenreName"])
    .ToDictionary(g => g.Key, g => g.ToList())
    .Select(kvp => new
    
        title = kvp.Key,
        items = kvp.Value.Select(x => 
        
            var hdsubjecturl = (string)x["subjecturl"];
            var url = (string)x["logourl"];
            var subjecturlsplit = hdsubjecturl.Split('_')[1] == "abc" ? "abc" : url.Split('_')[1];
            return new  hdsubjecturl, url, subjecturlsplit ;
        )
    );

小提琴:https://dotnetfiddle.net/RH60VC

【讨论】:

感谢您的回答。这对我很有帮助。 是否可以使用相同的查询找到唯一值。这意味着如果 logourl 相同,则仅在 JSON 中存储唯一的 logo url。我在每个地方都尝试过 .Distinct 但没有运气

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