在 WHERE 子句中使用类似 WINDOW 的函数对表进行 SQL 更新

Posted 2023-03-31

【中文标题】在 WHERE 子句中使用类似 WINDOW 的函数对表进行 SQL 更新

【英文标题】：SQL updates to table using WINDOW-like function in WHERE clause

【发布时间】：2019-07-24 05:00:42

【问题描述】：

我有一份按代表、客户、交易编号汇总销售交易的报告，如果总部已与他们联系以查看他们是否需要其他帮助，则标记为标记。当我提取数据时，我可以看到一些销售代表在同一​​个帐户中进行了多项交易。

这是报告的示例。在此示例中，已联系过销售代表 A，但从未联系过销售代表 B。我们要填写销售代表 A 已联系的字段，同时将销售代表 B 保留为

opportunity owner | Account   | contacted   | deal no.
--------------------------------------------------------
Sales rep A       | account 1 | Sales rep A | 1
Sales rep A       | account 2 | <null>      | 2
Sales rep A       | account 1 | <null>      | 3
Sales rep B       | account a | <null>      | 1
Sales rep B       | account b | <null>      | 2
...

我想使用“销售代表 A”（或“是”）更新已联系的列 所以它看起来像这样：

opportunity owner | Account   | contacted   | deal no.
--------------------------------------------------------
Sales rep A       | account 1 | Yes         | 1
Sales rep A       | account 2 | Yes         | 2
Sales rep A       | account 1 | Yes         | 3
Sales rep B       | account a | <null>      | 1
Sales rep B       | account b | <null>      | 2
...

对我来说，这看起来像是一个窗口函数的例子，但也许自联接会更好。我试图弄清楚 select 函数会是什么样子

SELECT "opportunity owner", "contacted", "Account", "deal no."
DENSE_RANK () OVER (PARTITION by 
--"opportunity owner"
 (SELECT "opportunity owner" FROM "test_weekly_top_deal_report" WHERE "worked with this rep before?"  LIKE 'Sales rep A')) AS "rank"

FROM "test_weekly_top_deal_report"
WHERE "opportunity owner"  LIKE 'Sales rep A'

这给了我：

opportunity owner | Account   | contacted   | deal no.
--------------------------------------------------------
Sales rep A       | account 1 | Sales rep A | 1
Sales rep A       | account 2 | <null>      | 2
Sales rep A       | account 1 | <null>      | 3

但是当我修改它以运行 所有 代表时，我使用了这个：

SELECT "opportunity owner", "worked with this rep before?", "account name",
DENSE_RANK () OVER (PARTITION by 
--"opportunity owner"
 (SELECT "opportunity owner" FROM "test_weekly_top_deal_report" WHERE "worked with this rep before?"  NOT LIKE 'NO')) AS "rank"

FROM "test_weekly_top_deal_report"

WHERE 子句中的小改动现在变为“NOT LIKE 'NO'”。那只是给了我一个错误：

The database reported a syntax error: [Amazon](500310) Invalid operation: 
Invalid Query: Details: ----------------------------------------------- error: 
Invalid Query: code: 8001 context: single-row subquery returns more than one row query: 2151115 location: 0.cpp:8

建议？我如何让这个迭代所有的代表，从而填写“联系”列？

【参考方案1】：

select ("opportunity owner" from "test_weekly_top_deal_report"
    where "contacted" is "opportunity owner") as X;
select case
   when ("opportunity owner" in (X)) and ("contacted" is null or "contacted" is "opportunity owner")
   then 'Yes'
   else 'No' as contacted
from "test_weekly_top_deal_report"

【讨论】：

感谢@ketcham 的回复。我在请求中并不清楚。我只想更新那些已联系过的代表。所以逻辑有点复杂 - 如果每个代表的任何一行不为空，则将所有联系的行设置为代表的名称。对所有代表重复。我更新了示例表以更清晰。

啊，我明白了——刚刚编辑过。不幸的是，我目前无法对此进行测试，但这应该符合您的需求