BigQuery 月度活跃用户？

Posted 2023-03-25

【中文标题】BigQuery 月度活跃用户？

【英文标题】：BigQuery Monthly Active Users?

【发布时间】：2017-01-19 14:40:54

【问题描述】：

我目前正在处理来自此post 的查询。该查询是用旧版 SQL 编写的，在我的环境中不起作用。我已修改查询以使用现代 SQL 函数，并将 SELECT date as date 更新为使用 timestamp_micros。

我还应该提到，我尝试选择的行来自 Firebase Analytics。

我的查询：

SELECT 
    FORMAT_TIMESTAMP('%Y-%m-%d', TIMESTAMP_MICROS(event.timestamp_micros)) as date,
    SUM(CASE WHEN period = 7  THEN users END) as days_07,
    SUM(CASE WHEN period = 14 THEN users END) as days_14,
    SUM(CASE WHEN period = 30 THEN users END) as days_30
FROM (
    SELECT
        FORMAT_TIMESTAMP('%Y-%m-%d', TIMESTAMP_MICROS(event.timestamp_micros)) as date,
        periods.period as period,
        COUNT(DISTINCT user_dim.app_info.app_instance_id) as users
    FROM `com_sidearm_fanapp_uiowa_ios.*` as activity
    CROSS JOIN
        UNNEST(event_dim) as event  
    CROSS JOIN (
        SELECT 
            FORMAT_TIMESTAMP('%Y-%m-%d', TIMESTAMP_MICROS(event.timestamp_micros)) as date
        FROM `com_sidearm_fanapp_uiowa_IOS.*`
        CROSS JOIN
            UNNEST(event_dim) as event 
        GROUP BY event.timestamp_micros
    ) as dates
    CROSS JOIN (
        SELECT 
            period 
        FROM 
            (
                SELECT 7 as period 
                UNION ALL
                SELECT 14 as period 
                UNION ALL
                SELECT 30 as period
            )
    ) as periods
    WHERE 
        dates.date >= activity.date 
    AND 
        SAFE_CAST(FLOOR(TIMESTAMP_DIFF(dates.date, activity.date, DAY)/periods.period) AS INT64) = 0
    GROUP BY 1,2
)
CROSS JOIN 
    UNNEST(event_dim) as event
GROUP BY date
ORDER BY date DESC

【问题讨论】：

对于其他访问这篇文章的人，BQ 导出模式定义为here。

【参考方案1】：

在 [24:13] 错误时列名句点不明确。

要修复这个特定的错误 - 你应该在下面修复

    CROSS JOIN (
        SELECT 
            period 
        FROM 
            (SELECT 7 as period), 
            (SELECT 14 as period), 
            (SELECT 30 as period)
    ) as periods

所以它应该看起来像：

    CROSS JOIN (
        SELECT 
            period 
        FROM 
            (SELECT 7 as period UNION ALL
            SELECT 14 as period UNION ALL
            SELECT 30 as period)
    ) as periods

回答您更新的问题

试试下面。我没有机会测试它，但希望它可以帮助您解决您的查询

SELECT 
    date,
    SUM(CASE WHEN period = 7  THEN users END) as days_07,
    SUM(CASE WHEN period = 14 THEN users END) as days_14,
    SUM(CASE WHEN period = 30 THEN users END) as days_30
FROM (
    SELECT 
        activity.date as date,
        periods.period as period,
        COUNT(DISTINCT user) as users
    FROM (
      SELECT
          event.timestamp_micros as date, 
           user_dim.app_info.app_instance_id as user
      FROM `yourTable` CROSS JOIN UNNEST(event_dim) as event  
    ) as activity
    CROSS JOIN (
        SELECT 
            event.timestamp_micros  as date
        FROM `yourTable` CROSS JOIN UNNEST(event_dim) as event 
        GROUP BY event.timestamp_micros
    ) as dates
    CROSS JOIN (
        SELECT period 
        FROM 
            (SELECT 7 as period UNION ALL 
            SELECT 14 as period UNION ALL
            SELECT 30 as period)
    ) as periods
    WHERE dates.date >= activity.date 
    AND SAFE_CAST(FLOOR(TIMESTAMP_DIFF(TIMESTAMP_MICROS(dates.date), TIMESTAMP_MICROS(activity.date), DAY)/periods.period) AS INT64) = 0
    GROUP BY 1,2
)
GROUP BY date
ORDER BY date DESC

【讨论】：

这是有效的，但现在又抛出了另一个错误：Name date not found inside activity at [31:32]

正如您在问题中提到的 - 原始查询是为其中包含 date 字段的不同表编写的。所以你需要确保你使用的文件存在于你的表中

我查询的字段确实存在于我的表中。我很确定这一点。我已将date 更改为timestamp_micros

请查看更新后的问题。我更改了 date 字段的格式以匹配原始旧 SQL 查询中的内容。

@JoeScotto - 这不是 SO 的工作方式 - 如果您有新问题，您应该将其作为新问题发布。相反，您不断更改现有问题，从而使原始问题的答案完全无效！作为一个例外（对我自己而言），我会再回答一次——但在未来——我不会回答这种永无止境的一体式问题。顺便说一句——通常你的问题的标题不应该是你正在处理的项目或任务名称——而是你遇到的明确的简短和具体的问题。我知道这并不总是那么简单 - 但这就是 SO 的工作原理