ios nsdictionary 创建 json

Posted 2023-03-16

【中文标题】ios nsdictionary 创建 json

【英文标题】：ios nsdictionary create json

【发布时间】：2014-01-24 12:22:26

【问题描述】：

您好，我正在尝试使用 nsdictionary 创建 json 字符串 到目前为止我无法制作这个 json

"user":"username":"test","email":"[e-mail]", "password":"123456789","password_confirmation":"123456789"

这是我的代码：

            NSDictionary *jsonUserDictinary = [NSDictionary dictionaryWithObjectsAndKeys:
                                           [usernameText text], @"username",
                                           [passwordText text], @"password" ,
                                           [emailText text], @"email",
                                           [confirmText text], @"password_confirmation",
                                           nil];


        NSDictionary *jsonSignUpDictionary = [NSDictionary dictionaryWithObjectsAndKeys:jsonUserDictinary, @"user",nil];

        NSData *jsonSignUpData = [NSJSONSerialization dataWithJSONObject:jsonSignUpDictionary options:NSJSONWritingPrettyPrinted error: nil];
        NSString *jsonSignUp = [[NSString alloc] initWithData:jsonSignUpData encoding:NSUTF8StringEncoding];
        NSLog(@"json data string:\n%@", jsonSignUp);

现在我想创建这个 json：

"user":"username":"test","email":"[e-mail]", "password":"123456789","password_confirmation":"123456789","device":"token":"654C4DB3-3F68-4969-8ED2-80EA16B46EB0"

但我找不到添加“设备”对象的方法

【问题讨论】：

你所做的和你对用户嵌套字典所做的完全一样...

【参考方案1】：

NSDictionary *jsonUserDictinary = [NSDictionary dictionaryWithObjectsAndKeys:
                                   [usernameText text], @"username",
                                   [passwordText text], @"password" ,
                                   [emailText text], @"email",
                                   [confirmText text], @"password_confirmation",
                                   nil];

NSDictionary *deviceDic = @@"token": @"your token";
NSDictionary *jsonSignUpDictionary = @@"user":jsonSignUpDictionary, @"device":deviceDic;

【讨论】：

非常感谢。只需将 @"user": jsonSignUpDictionary 更改为 jsonUserDictionary

【参考方案2】：

NSDictionary *deviceResult = [NSDictionary dictionaryWithDictionary:[YourDictionary valueForKey:@"device"]];

for (NSString *tokenKey in [deviceResult allKeys]) 
    NSDictionary *res = [deviceResult valueForKey:tokenKey];

 NSLog(@"Device Token : %@", [res objectForKey:@"token"]);

【参考方案3】：

NSDictionary *dict1 = [[NSDictionary alloc] initWithObjectsAndKeys:
                           @"test", @"username", @"[e-mail]",
                           @"email",@"123456789",@"password",@"123456789",@"password_confirmation", nil];
    NSDictionary *dict2 = [[NSDictionary alloc] initWithObjectsAndKeys:
                           @"token", @"654C4DB3-3F68-4969-8ED2-80EA16B46EB0", nil];
    NSDictionary *myDictionary = [[NSDictionary alloc] initWithObjectsAndKeys:
                                  dict1,@"user",dict2,@"device",nil];
    NSData *jsonData = [NSJSONSerialization dataWithJSONObject:myDictionary
                                                       options:0
                                                         error:nil];
    NSString *JSONString = [[NSString alloc] initWithBytes:[jsonData bytes] length:[jsonData length] encoding:NSUTF8StringEncoding];
    NSLog(@"%@",JSONString);

【参考方案4】：

NSMutableString *mutableString = nil; NSString *string= @"";

@try

    if (mutableString == nil)
    
        mutableString = [[NSMutableString alloc] init];
    

    [mutableString appendFormat:@""];
    [mutableString appendFormat:@"\"string1\":%@"",",@""];
    [mutableString appendFormat:@"\"string2\":\"%@\"",@""];
    [mutableString appendFormat:@""];
    jsonString = mutableString ;

@catch (NSException *exception)



@finally

    return string;