在对象的 json 数组中找到一个键值并返回另一个带有角度的键值

Posted 2023-03-13

【中文标题】在对象的 json 数组中找到一个键值并返回另一个带有角度的键值

【英文标题】：Find a key value in json array of objects and return another key value with angular

【发布时间】：2019-06-07 22:46:15

【问题描述】：

如何遍历我的 json 数据以找到两个特定的键值，例如weight =“8m”和meters =“7t”然后返回找到这两个值的对象的名称值，例如“25吨”。

data.json（小样本）

    [
      
       "name": "20t",
       "weight": ["1t","2t","3t","4t","5t"],
       "meters": ["7m","8m","9m","10m","12m","14m","16m","18m"]
      ,
      
       "name": "25t",
       "weight": ["1t","2t","3t","4t","5t","6t","7t","8t"],
       "meters": ["7m","8m","9m","10m","12m","14m","16m","18m","20m","22m"]
      
    ]

我可以使用 ngif 和 ngfor 遍历所有数据。

    <div *ngIf="crane?.length">
      <div *ngFor="let data of crane">

        <p>data.name</p>
        <p>data.weight</p>
        <p>data.meters</p>

      </div>
    </div>

但我只需要输出重量和米与我想要的键值匹配的特定名称值。关于如何实现这一目标的任何想法？我对 Angular 很陌生，任何帮助将不胜感激。

【问题讨论】：

您可以添加示例输出吗？

【参考方案1】：

试试这个：

const data = [
      
       "name": "20t",
       "weight": ["1t","2t","3t","4t","5t"],
       "meters": ["7m","8m","9m","10m","12m","14m","16m","18m"]
      ,
      
       "name": "25t",
       "weight": ["1t","2t","3t","4t","5t","6t","7t","8t"],
       "meters": ["7m","8m","9m","10m","12m","14m","16m","18m","20m","22m"]
      
    ]

const w = "7t";
const m = "8m";

const filteredData = data
            .filter(
              (data) => 
                  data.weight
                    .some((weight) => weight === w) 
                  && 
                  data.meters
                    .some((meter) => meter === m)
              );

const keys = filteredData.map((data) => data.name);

console.log(keys);

【参考方案2】：

我挂了你的一些句子，与提供的数据相比，它没有多大意义，但看起来像这样：

const data = [
      
        "name": "20t",
        "weight": ["1t", "2t", "3t", "4t", "5t"],
        "meters": ["7m", "8m", "9m", "10m", "12m", "14m", "16m", "18m"]
      ,
      
        "name": "25t",
        "weight": ["1t", "2t", "3t", "4t", "5t", "6t", "7t", "8t"],
        "meters": ["7m", "8m", "9m", "10m", "12m", "14m", "16m", "18m", "20m", "22m"]
      
    ]
    //ow can I loop through my json data to find two specific key values e.g. weight = "8t" and meters = "7m" then return the name value of the object where these two values are found e.g. "25t".

    const result = data.filter(a => a.weight.find(w => w == "8t"))
      .filter(a => a.meters.find(m => m == "7m"))
      .map(a => a.name);
    console.log(result)

【讨论】：

这行得通，但是，预先设置变量可以提供更大的灵活性，非常感谢