我需要获取值> 0的密钥[重复]

Posted 2023-03-13

【中文标题】我需要获取值> 0的密钥[重复]

【英文标题】：I need to get the key that has the value > 0 [duplicate]

【发布时间】：2021-01-08 21:42:07

【问题描述】：

在本例中，我需要获取值 > 0 的键是 005340302403，我该怎么做？

var json = 
    "productSkuInventoryStatus": 
        "005340304004": 0,
        "005340304003": 0,
        "005340304002": 0,
        "005340304001": 0,
        "005340302401": 0,
        "005340302402": 0,
        "005340301401": 0,
        "005340304005": 0,
        "005340301403": 0,
        "005340302405": 0,
        "005340301402": 0,
        "005340301405": 0,
        "005340302403": 1,
        "005340301404": 0,
        "005340302404": 0
    


var array1 = Object.values(json.productSkuInventoryStatus);
const found = array1.find(element => element > 0); 
console.log(found)// get de value > 0
// how to get the key of this value greater than 0

【问题讨论】：

使用 Object.entries 你会得到 [key,value] 对。现在你可以得到这两个值了。

【参考方案1】：

您可以使用Object.keys 和Array.find 从对象中获取单个键。

var json = 
    "productSkuInventoryStatus": 
        "005340304004": 0,
        "005340304003": 0,
        "005340304002": 0,
        "005340304001": 0,
        "005340302401": 0,
        "005340302402": 0,
        "005340301401": 0,
        "005340304005": 0,
        "005340301403": 0,
        "005340302405": 0,
        "005340301402": 0,
        "005340301405": 0,
        "005340302403": 1,
        "005340301404": 0,
        "005340302404": 0
    


const result = Object.keys(json.productSkuInventoryStatus).find(key => json.productSkuInventoryStatus[key] > 0);
console.log(result)

要从带有value > 0 的对象中获取所有键，则可以使用Array.filter。此操作的结果是一个数组。

var json = 
  "productSkuInventoryStatus": 
    "005340304004": 0,
    "005340304003": 0,
    "005340304002": 0,
    "005340304001": 0,
    "005340302401": 0,
    "005340302402": 0,
    "005340301401": 0,
    "005340304005": 0,
    "005340301403": 0,
    "005340302405": 0,
    "005340301402": 0,
    "005340301405": 0,
    "005340302403": 1,
    "005340301404": 0,
    "005340302404": 0
  


const result = Object.keys(json.productSkuInventoryStatus).filter(key => json.productSkuInventoryStatus[key] > 0);
console.log(result)

【参考方案2】：

您可以为此使用Object.entries。

const result = Object.entries(json.productSkuInventoryStatus).filter(item => item[1] > 0).map(item => item[0]);
console.log(result);

【参考方案3】：

你也可以像这样遍历对象键，只是另一种方法

let greater = "";
for(let prop in json.productSkuInventoryStatus)
  if(json.productSkuInventoryStatus[prop] > 0) greater = prop;

console.log(greater);