[__NSArrayM objectAtIndex:]: 索引 9223372036854775807 超出范围 [0 .. 13]'

Posted 2023-03-12

【中文标题】[__NSArrayM objectAtIndex:]: 索引 9223372036854775807 超出范围 [0 .. 13]\'

【英文标题】：[__NSArrayM objectAtIndex:]: index 9223372036854775807 beyond bounds [0 .. 13]'[__NSArrayM objectAtIndex:]: 索引 9223372036854775807 超出范围 [0 .. 13]'

【发布时间】：2015-04-17 04:50:17

【问题描述】：

我在我的 xcode 项目中实现了一个 SQLite 数据库。我想将数据库中的所有名称查看到 tableview 中，但出现错误

NSRangeException'，原因：'*** -[__NSArrayM objectAtIndex:]：索引 9223372036854775807 越界 [0 .. 13]'

@interface DisplayViewController ()
@property (nonatomic, strong) DBManager *dbManager;
@property (nonatomic, strong) NSArray *arrPeopleInfo;
  @end

@implementation DisplayViewController

- (void)viewDidLoad 
    [super viewDidLoad];
    self.mytableview.delegate = self;
    self.mytableview.dataSource = self;
    
    NSString *docsDir;
    NSArray *dirPaths;
    
    
    //Get the directory
    dirPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    docsDir = dirPaths[0];
     self.dbManager = [[DBManager alloc] initWithDatabaseFilename:@"IApp.db"];    //Build the path to keep the database
   // _databasePath = [[NSString alloc] initWithString:[docsDir stringByAppendingPathComponent:@"IApp.db"]];
   // [self getcount];
    [self loadData];
   // [self getcount];
        // Do any additional setup after loading the view.



      
- (void)loadData 
    // Form the query.
    NSString *query = @"select * from iApp";
    
   
    if (self.arrPeopleInfo != nil) 
        self.arrPeopleInfo = nil;
    
    self.arrPeopleInfo = [[NSArray alloc] initWithArray:[self.dbManager loadDataFromDB:query]];
    
    [self.mytableview reloadData];

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView 
    //#warning Potentially incomplete method implementation.
    // Return the number of sections.
    return  1;


- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section 
    return self.arrPeopleInfo.count;
    // return [arri count];


- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
    
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"idCellRecord" forIndexPath:indexPath];
    
    NSInteger indexOfname = [self.dbManager.arrColumnNames indexOfObject:@"firstname"];
    NSInteger indexOffname = [self.dbManager.arrColumnNames indexOfObject:@"lastname"];
  
    cell.textLabel.text = [NSString stringWithFormat:@"%@ %@", [[self.arrPeopleInfo objectAtIndex:indexPath.row] objectAtIndex:indexOfname], [[self.arrPeopleInfo objectAtIndex:indexPath.row] objectAtIndex:indexOffname]];
    
    
    return cell;
      

【参考方案1】：

当您在某物中搜索某个项目时，如果该方法找不到该项目，Cocoa 将返回NSNotFound 作为索引。这也适用于-indexOfObject:。 NSNotFound 是一个很大的整数 (INT_MAX)，您可以在 Q 的标题中看到。

因此

NSInteger indexOfname = [self.dbManager.arrColumnNames indexOfObject:@"firstname"];

如果在接收器中找不到@"firstName"，则为NSNotFound。请检查您是否有这样的密钥。错字？骆驼香烟盒？ firstNams?

如果您在编译时不知道密钥，则必须检查它，正如@Inder 告诉您的那样：

if(indexOfname==NSNotFound)
  // The object is not present

顺便说一句：你真的应该重新检查你的命名。它不遵循 Cocoa 命名约定。

【参考方案2】：

您可以通过非常简单的检查来防止这种情况发生。

if(indexOfname < [self.dbManager.arrColumnNames count] && indexOffname < [self.dbManager.arrColumnNames count]) 
    cell.textLabel.text = [NSString stringWithFormat:@"%@ %@", [[self.arrPeopleInfo objectAtIndex:indexPath.row] objectAtIndex:indexOfname], [[self.arrPeopleInfo objectAtIndex:indexPath.row] objectAtIndex:indexOffname]];     

else 
    cell.textLabel.text = @""; // or what ever you want to do

【参考方案3】：

请检查indexOfname或indexOffname是否等于NSNotFound

NSInteger indexOfname = [self.dbManager.arrColumnNames indexOfObject:@"firstname"];
NSInteger indexOffname = [self.dbManager.arrColumnNames indexOfObject:@"lastname"];

if (indexOfname == NSNotFound) 
  //Then don't use this index


if (indexOffname == NSNotFound) 
  //Then don't use this index

【参考方案4】：

实际上你已经成功地从Database获取了所有记录。所以左边部分是如何在UITableViewCell 中显示。根据以下代码修改cellForRowAtIndexPath。

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 

       UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"idCellRecord" forIndexPath:indexPath];


       cell.textLabel.text = [NSString stringWithFormat:@"%@ %@", [[self.arrPeopleInfo objectAtIndex:indexPath.row] valeuForKey:@"firstname"], [[self.arrPeopleInfo objectAtIndex:indexPath.row] valueForKey:@"lastname"]];


return cell;

【讨论】：

评论不用于扩展讨论；这个对话是moved to chat。