提取用户详细信息的 Oauth-2 身份验证需要 CustomPrincipal 对象

Posted 2023-03-10

【中文标题】提取用户详细信息的 Oauth-2 身份验证需要 CustomPrincipal 对象

【英文标题】：Oauth-2 authentication extracting the user details expects CustomPrincipal object

【发布时间】：2020-01-08 06:28:40

【问题描述】：

我得到了这段代码来在 Spring Boot 项目中实现身份验证。除了提取要进行身份验证的用户外，一切正常。我已经搜索并找不到在其他地方找不到解决方案。

public class CustomUserAuthenticationConverter implements UserAuthenticationConverter 

    private final String EMAIL = "email";

    private Collection<? extends GrantedAuthority> defaultAuthorities;

    public void setDefaultAuthorities(String[] defaultAuthorities) 
        this.defaultAuthorities = AuthorityUtils
                .commaSeparatedStringToAuthorityList(StringUtils.arrayToCommaDelimitedString(defaultAuthorities));
    

    @Override
    public Map<String, ?> convertUserAuthentication(Authentication userAuthentication) 
        Map<String, Object> response = new LinkedHashMap<String, Object>();
        response.put(USERNAME, userAuthentication.getName());

        if (userAuthentication.getAuthorities() != null && !userAuthentication.getAuthorities().isEmpty())
            response.put(AUTHORITIES, AuthorityUtils.authorityListToSet(userAuthentication.getAuthorities()));

        return response;
    

    @Override
    public Authentication extractAuthentication(Map<String, ?> map) 
        if (map.containsKey(USERNAME))
            return new UsernamePasswordAuthenticationToken(
                    new CustomPrincipal(map.get(USERNAME).toString(), map.get(EMAIL).toString()), "N/A",
                    getAuthorities(map));
        return null;
    

    private Collection<? extends GrantedAuthority> getAuthorities(Map<String, ?> map) 
        if (!map.containsKey(AUTHORITIES))
            return defaultAuthorities;

        Object authorities = map.get(AUTHORITIES);

        if (authorities instanceof String)
            return AuthorityUtils.commaSeparatedStringToAuthorityList((String) authorities);

        if (authorities instanceof Collection)
            return AuthorityUtils.commaSeparatedStringToAuthorityList(
                    StringUtils.collectionToCommaDelimitedString((Collection<?>) authorities));

        throw new IllegalArgumentException("Authorities must be either a String or a Collection");
    

除了这个方法sn-p之外，其他部分都正常工作

@Override
        public Authentication extractAuthentication(Map<String, ?> map) 
            if (map.containsKey(USERNAME))
                return new UsernamePasswordAuthenticationToken(
                        new CustomPrincipal(map.get(USERNAME).toString(), map.get(EMAIL).toString()), "N/A",
                        getAuthorities(map));
            return null;
        

我知道它需要一个 CustomPrincipal 对象，其中此字符串作为 USERNAME、EMAIL 传递。我该怎么做才能传递正确的参数？

【参考方案1】：

谢谢大家。问题是 Lombok 库创建构造函数失败，所以简单的答案是手动创建它们。

完美运行。 CustomPrincipal 类需要有一个构造函数，该构造函数接受 2 个参数，这些参数是隐式定义的，但在另一个类的类实例化中需要时不会注入