在graphql中嵌套片段

Posted 2023-03-08

【中文标题】在graphql中嵌套片段

【英文标题】：Nesting fragments in graphql

【发布时间】：2018-03-13 20:41:51

【问题描述】：

我正在尝试在我的 graphql 查询中嵌套片段（无递归或无限扩展）。但是，graphql 架构不认为我的查询是有效的，或者片段定义似乎是多余的。我想要的 graphql 响应结构是：

`
  
    "data":  
        "availability":  
            "mon":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            ,
            "tue":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            ,
            "wed":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            ,
            "thu":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            ,
            "fri":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            ,
            "sat":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            ,
            "sun":  
                "open":"5.00 a.m.",
                "close":"10.00 p.m.",
                "allday":false,
                "closed":false
            
        
    

`

可用性的类型为 Availability 和 mon、tue 等的类型为 Day

方法 1：这不是 graphql 中的有效语法。 graphql 抛出错误（不允许以这种方式嵌套）

`
fragment Hours on Day 
    open
    close
    allday
    closed


fragment DailyAvailability on Availability 
    mon 
    tue 
    wed 
    thu 
    fri 
    sat 
    sun


query 
    availability 
        ... DailyAvailability 
            ... Hours
        
    

`

方法 2：这可行，但似乎是多余的，因为我必须在每一天分别分配 Hours。

`
fragment Hours on Day 
    open
    close
    allday
    closed


fragment DailyAvailability on Availability 
    mon ... Hours
    tue ... Hours
    wed ... Hours
    thu ... Hours
    fri ... Hours
    sat ... Hours
    sun ... Hours


query 
    availability 
        ... DailyAvailability
    

`

请建议是否有一种方法可以嵌套片段，就像我在第一种方法中打算做的那样。

【参考方案1】：

您似乎想使用带有“别名”的字段请求。您的架构将类似于：

type QueryRoot 
  availability: Availability


type Availability 
  openingHours(forDay: WeekDay): Day


enum WeekDay 
  mon 
  tue 
  wed 
  thu 
  fri 
  sat 
  sun


type Day 
  open: String
  close: String
  allday: Boolean
  closed: Boolean

那么这个查询会给你你所要求的：

query q 
  availability 
    mon: openingHours(forDay: mon)  ... DailyAvailability 
    tue: openingHours(forDay: tue)  ... DailyAvailability 
    wed: openingHours(forDay: wed)  ... DailyAvailability 
    thu: openingHours(forDay: thu)  ... DailyAvailability 
    fri: openingHours(forDay: fri)  ... DailyAvailability 
    sat: openingHours(forDay: sat)  ... DailyAvailability 
    sun: openingHours(forDay: sun)  ... DailyAvailability 
  

fragment DailyAvailability on Day 
  open
  close
  allday
  closed