找出两个数组中都有，并且重复次数最多的元素

Posted 2020-11-21 _NKi

var itemA = [1, 2, 3, 3]
var itemB = [3, 3, 2]
var crossArr = [];
var countArr = [];

itemA.forEach((e) => {
    if (itemB.includes(e)) {
        !crossArr.includes(e) && crossArr.push(e);
    }   
})

function count(item, total = 0, index = 0, arr = itemA.concat(itemB)) {
    if (arr.indexOf(item, index) >= 0) {
        total++;
        index = arr.indexOf(item, index) + 1;
        return count(item, total, index)
    }
    return total;
}

countArr = crossArr.map(e => {
    return count(e)
})
var maxCount = Math.max(...countArr);
var maxCountIndex = countArr.indexOf(maxCount)
var maxValue = crossArr[maxCountIndex]

console.log(`${maxValue}重复最多次,共${maxCount}次`)